A = 456 x 6
B = 478 x 9
C = 44 x 11
D = 489 x 9
Kb nhé!
a (2+x):5=6
b 2+x:5=6
c 2x-3=11
d 3.(x-18)+75=0
a) (2 + x) : 5 = 6
2 + x = 6 $\times$ 5
2 + x = 30
x = 30 - 2
x = 28
b) 2 + x : 5 = 6
x : 5 = 6 - 2
x : 5 = 4
x = 4 $\times$ 5
x = 20
c) 2x - 3 = 11
2x = 11 + 3
2x = 14
x = 14 : 2
x = 7
d) 3 . (x - 18) + 75 = 0
3 . (x - 18) = -75
x - 18 = -75 : 3
x - 18 = -25
x = -25 + 18
x = -7
bai1:tim x biet a,(x:23+45)•67
bai2:tinh nhanh a,(44•52•60):(11•13•15) b,123•456-456•123123
\(\left(x:23+45\right).67=8911\)
\(x:23+45=8911:67\)
\(x:23+45=133\)
\(x :23=133-45\)
\(x:23=88\)
\(x=88.23\)
\(x=2024\)
Bài 2:
a, \(\frac{44.52.60}{11.13.15}=\frac{4.11.4.13.4.15}{11.13.15}=4.4.4=64\)
b, \(123.456-456.123123=456\left(123-123123\right)=456.\left(-123000\right)=-56088000\)
Tính nhanh:
456 x 36 + 456 x 61 + 4 x 456 + 456
Giair nhanh mình tick cho nhé!!!
Ta có :
456x36+456x61+4 x456+456
=456x(36+61+4+456)
=456x...tự tính
=...tự tính
Umm mình tưởng là cái 456 đó tính là 1 thôi chứ nhỉ ban???
\(456\times36+456\times61+4\times456+456\)
\(=456\times\left(36+61+4+1\right)\)
\(=456\times102\)
\(=45612\)
Học tốt
( Mn giải thích giúp em vs ạ )
Tổng số hạt trong nguyên tử X là 40, trong đó số hạt mang điện là 22. Tính số hạt electron trong nguyên tử X.
A.8
B.9
C.11
D.10
\(\left\{{}\begin{matrix}P=E\\P+N+E=40\\P+E=22\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}P=E=11\\N=18\end{matrix}\right.\)
=> Chọn C
Phan tich da thuc thanh nhan tu:
2a+6b+15c
4m^2n-8m^2n-12n
a^4-b^4
16b^4-9c^2
5a(x+y)+x+y
b: \(4m^2n-8m^2n-12n\)
\(=-4m^2n-12n\)
\(=-4n\left(m^2+3\right)\)
c: \(a^4-b^4=\left(a^2-b^2\right)\left(a^2+b^2\right)=\left(a^2+b^2\right)\left(a-b\right)\left(a+b\right)\)
d: \(16b^4-9c^2\)
\(=\left(4b^2-3c\right)\left(4b^2+3c\right)\)
e: \(5a\left(x+y\right)+x+y=\left(x+y\right)\left(5a+1\right)\)
Đặt tính rồi tính
a, 37 052 + 28 456
b, 596 178 – 44 695
c, 487 x 215
d, 14790 : 34
a, 37 052 + 28 456
b, 596 178 – 44 695
c, 487 x 215
d, 14790 : 34
tính nhanh : 2010 x 2010 - 2009 x 2011
(456 x 11 +912) x 37 : (13 x 74 )
(44 x 52 x 60) : (11 x13 x 15 )
Giúp mk với ,bài khó quá ,mai mk đi học rùi
2010 x 2010 - 2009 x 2011
= ( 2011 - 2010 ) x 2010 - 2009 x 2011
= 2011 x 2010 - 1 x 2010 - 2009 x 2011
= 2011 x ( 2010 - 2009 ) - 1 x 2010
= 2011 x 1 - 2010
= 2011 - 2010
= 1
( 456 x 11 + 912 ) x 37 : ( 13 x 74 )
= ( 456 x 11 + 456 x 2 ) x 37 : ( 13 x 74 )
= [ 456 x ( 11 + 2 ) ] x 37 : ( 13 x 74 )
= [ 456 x 13 ] x 37 : ( 13 x 74 )
= 13 x 456 x 37 : ( 13 x 37 x 2 )
= 13 x 37 x 2 x 228 : ( 13 x 37 x 2 )
= ( 13 x 37 x 2 ) x 228 : ( 13 x 37 x 2 )
= ( 13 x 37 x 2 ) : ( 13 x 37 x 2 ) x 228
= 1 x 228
= 228
(44 x 52 x 60) : (11 x13 x 15 )
= [ ( 4 x 11 ) x ( 4 x 13 ) x ( 4 x 15 ) ] : (11 x13 x 15 )
= [ 4 x 11 x 4 x 13 x 4 x 15 ] : (11 x13 x 15 )
= [ ( 4 x 4 x 4 ) x ( 11 x 13 x 15 ) ] : (11 x13 x 15 )
= 64 x (11 x13 x 15 ) : (11 x13 x 15 )
= 64 x 1
= 64
a) 2010 x 2010 - 2009 x 2011
= 2010 x 2010 - [ 2009 x ( 2010 +1) ]
=2010 x 2010 - 2009 x 2010 - 2009
=2010( 2010 - 2009 ) -2009
= 2010 -2019
= 1
c) ( 44 x 52 x60 ) : (11x13x15)
\(\frac{44\cdot52\cdot60}{11\cdot13\cdot15}=\frac{4\cdot11\cdot4\cdot13\cdot4\cdot15}{11\cdot13\cdot15}=64\)
B) (456 x 11 +912) x 37 : ( 13 x 74 )
= \(\frac{\left(456\cdot11+912\right)\cdot37}{13\cdot74}=\frac{\left[456\left(11+2\right)\right]\cdot37}{13\cdot37}=\frac{456\cdot13}{13\cdot2}=\frac{456}{2}=228\)
Nhớ k mik nha bn
Thực hiện bằng cách hợp li nhất: ( cần gấp )
a. ( 44 x 52 x 60 ) : ( 11 x 13 x 15 )
b. 123 x 456456 - 456 x 123123
c. ( 98 x 7676 - 9898 x 76 ) : ( 2001 x 2002 x 2003 x... x 2010 )
d. 14 x 29 + 14 x 71 + ( 1 + 2 +3 +4 +...+ 99 ) x ( 199199 x 198 - 198198 x 199 )
a)(44x52x60):(11x13x15) =(44:11)x(52:13)x(60:15)=4x4x4 =64
\(a.\)
\(\left(44.52.60\right):\left(11.13.15\right)=\frac{44.52.60}{11.13.15}\frac{4.4.4\left(11.13.15\right)}{\left(11.13.15\right)}=4^3=64\)
4. tìm số tự nhiên x và y, biết rằng:
a) x.(y - 2 ) = 8
b) ( x - 1 ).( y - 2 )= 9
c) ( x + 1 ) . ( y - 2 ) = 15
Mơn nhé ^ ^
\(a,x\left(y-2\right)=8\\ \Rightarrow x;\left(y-2\right)\inƯ\left(8\right)=\left\{-8;-4;-2;-1;1;2;4;8\right\}\)
\(x\) | \(-8\) | \(-4\) | \(-2\) | \(-1\) | \(1\) | \(2\) | \(4\) | \(8\) |
\(y-2\) | \(-1\) | \(-2\) | \(-4\) | \(-8\) | \(8\) | \(4\) | \(2\) | \(1\) |
\(y\) | \(1\) | \(0\) | \(-2\) | \(-6\) | \(10\) | \(6\) | \(4\) | \(3\) |
Vậy \(\left(x;y\right)=\left(-8;1\right),\left(-4;0\right),\left(-2;-2\right),\left(-1;-6\right),\left(2;6\right),\left(4;4\right),\left(8;3\right)\)
\(b,\left(x-1\right)\left(y-2\right)=9\\ \Rightarrow\left(x-1\right),\left(y-2\right)\inƯ\left(9\right)=\left\{-9;-3;-1;1;3;9\right\}\)
\(x-1\) | \(-9\) | \(-3\) | \(-1\) | \(1\) | \(3\) | \(9\) |
\(y-2\) | \(-1\) | \(-3\) | \(-9\) | \(9\) | \(3\) | \(1\) |
\(x\) | \(-8\) | \(-2\) | \(0\) | \(2\) | \(4\) | \(10\) |
\(y\) | \(1\) | \(-1\) | \(-7\) | \(11\) | \(5\) | \(3\) |
Vậy \(\left(x;y\right)=\left(-8;1\right),\left(-2;-1\right),\left(0;-7\right),\left(2;11\right),\left(4;5\right),\left(10;3\right)\)
\(c,\left(x+1\right)\left(y-2\right)=15\\ \Rightarrow\left(x+1\right),\left(y-2\right)\inƯ\left(15\right)=\left\{-15;-1;1;15\right\}\)
\(x+1\) | \(-15\) | \(-1\) | \(1\) | \(15\) |
\(y-2\) | \(-1\) | \(-15\) | \(15\) | \(1\) |
\(x\) | \(-16\) | \(-2\) | \(0\) | \(14\) |
\(y\) | \(1\) | \(-13\) | \(17\) | \(3\) |
Vậy \(\left(x;y\right)=\left(-16;1\right),\left(-2;-13\right),\left(0;17\right),\left(14;3\right)\)