Tìm x
a, (2x - 15) 5 = ( 2x - 15) 3
b, x + ( x + 1 ) + ( x + 2 ) + ... + ( x + 2013) = 2035147
tìm A. a) A(x-5)/x^2-4x-5=3x^2+9x/x^2+4x+3
b) x^2+x-6/A(x+3)=(5x-1)(x-2)/5x^3-x^2+15x-3
c)x^2-25/2x^2+7x-15=(x-5)A/2x^2+x-6
mong mọi ng làm giúp ạ
b: \(\Leftrightarrow\dfrac{x-2}{A}=\dfrac{\left(5x-1\right)\left(x-2\right)}{x^2\left(5x-1\right)+3\left(5x-1\right)}=\dfrac{x-2}{x^2+3}\)
hay \(A=x^2+3\)
a, | 2x - 1 | = 7 - x
b, (2x- 15)5 =(2x - 15)3
c, (-3x + 2)4 = (3x-2)10
d, x + (x+1) + (x+2) + ...................+(x+2013)
tính x đi ae
thầy ra ko làm lên olm hỏi à?giỏi đó con
mấy bài này dễ mà
a)x=-6
b)8
c)1
d)4
\(a)\) \(\left|2x-1\right|=7-x\)
+) Nếu \(2x-1\ge0\)\(\Rightarrow\)\(2x\ge1\)\(\Rightarrow\)\(x\ge\frac{1}{2}\) ta có :
\(2x-1=7-x\)
\(\Leftrightarrow\)\(2x+x=7+1\)
\(\Leftrightarrow\)\(3x=8\)
\(\Leftrightarrow\)\(x=\frac{8}{3}\) ( thoã mãn )
+) Nếu \(2x-1< 0\)\(\Rightarrow\)\(2x< 1\)\(\Rightarrow\)\(x< \frac{1}{2}\) ta có :
\(-\left(2x-1\right)=7-x\)
\(\Leftrightarrow\)\(-2x+1=7-x\)
\(\Leftrightarrow\)\(2x-x=1-7\)
\(\Leftrightarrow\)\(x=-6\) ( thoã mãn )
Vậy \(x=\frac{8}{3}\) hoặc \(x=-6\)
Chúc bạn học tốt ~
Tìm x biet:
a,5/2x+x=32/15
b,x-7/2x=-32/15
c,-7/3x-7/4x+11/3=18/5
d,-5/6-3x=2/3
e,2x-5/9=-2/3
f,1/2-2/3x=7/12
g,7-|2x-3|=4
h,(19x+2.5^2):14=(13-8)^2-4^2
i,3/4x-2/3=2/7.1/6+5/7.1/6
k,(x+1/2).(2/3-2x)=0
l,x/2013-1/10-1/15-1/21-........-1/120=5/8
Tìm x biết: x+(x+1)+(x+2)+...+(x+2013)=2035147
x+(x+1)+(x+2)+...+(x+2013)=2035147
=> x+x+1+x+2+x+3+...+x+2013=2035147
=>2014x+(1+2+3+...+2013)=2035147
=>2014x+2027091=2035147 (tổng trên bạn tự tính nhé mik không ghi cách tính tổng đâu)
=>2014x=2035147-2027091
=> x =8056/2014
=> x = 4
Vậy x = 4
X+(X+1)+(X+2)+(X+3)+(X+4)+...+(X+2013)=2035147
Xx2014+(1+2+3+4+5+...+2013) =2035147
Xx2014+2027091 =2035147
Xx2014 =8056
X =4
https://d3.violet.vn//uploads/previews/present/4/139/141/preview.swf
Bài 1: Tìm x biết:
a) |x - 1| = 2x - 1
b) 2 |5-2x| -3 (x + 1) = 17
c) | | x - 2 |+ 3 | = 5
d) | 3 - 2x | = 3
Bài 2: Tìm x
a) | x - 1 | + | x + 2 | + | x - 3 | = 14
b) | x + 1 | + | x + 2 | + | x + 3 | + ... + | x + 10 | = 11x
c) | 39/2 - 3x^2 | = 15/2
d) | x + 4 | + | x + 10 | + | x + 101 | + | x + 999 | + | x + 1000 | = 2013
Bài 3: Tìm x
a) | x - 1 | < 5
b) | 1 - 2 x | < 3
c) | 2x + 3 | - 4 > 9
d) | 1/2 - x | + 3 > 7
\(\left|x-1\right|=2x-1\)
\(\Rightarrow\orbr{\begin{cases}x-1=2x-1\\x-1=-2x+1\end{cases}\left(đk:2x\ge\frac{1}{2}\right)}\)
\(\Rightarrow\orbr{\begin{cases}x=0\left(ktm\right)\\x=\frac{2}{3}\left(tm\right)\end{cases}}\)
vậy \(x=\frac{2}{3}\)
Tìm x
a) -x/27 -1 = 2/3
b) x - 4 = -14/35 : 20/-21
c) x + 2/3 = -1/12 . -4/5
d) 1/5 - 3/5x = -15/14 :20/-21
e) -3/7x = 3/5 . 28/9
f)1/2x + 3/5x = -2/3
a: =>x/27+1=-2/3
=>x/27=-5/3
=>x=-45
b: \(\Leftrightarrow x-4=\dfrac{2}{5}:\dfrac{20}{21}=\dfrac{2}{5}\cdot\dfrac{21}{20}=\dfrac{42}{100}=\dfrac{21}{50}\)
=>x=221/50
c: \(\Leftrightarrow x+\dfrac{2}{3}=\dfrac{4}{60}=\dfrac{1}{15}\)
=>x=1/15-2/3=1/15-10/15=-9/15=-3/5
d: \(\Leftrightarrow x\cdot\dfrac{3}{5}=\dfrac{1}{5}-\dfrac{15}{14}\cdot\dfrac{21}{20}\)
=>\(x\cdot\dfrac{3}{5}=\dfrac{1}{5}-\dfrac{3}{2}\cdot\dfrac{3}{4}=\dfrac{1}{5}-\dfrac{9}{8}=\dfrac{-37}{40}\)
=>x=-37/24
e: =>-3/7x=84/45
=>x=-196/45
f: =>11/10x=-2/3
=>x=-20/33
x + ( X+1) + (X+2) + ..... + (X + 2013) = 2035147
\(x+\left(x+1\right)+...+\left(x+2013\right)=2035147\)
\(\Leftrightarrow2014x+2027091=2035147\)
\(\Leftrightarrow2014x=8056\)
hay x=4
B1: Tìm x:
1/ \(\dfrac{x+3}{15}\) = \(\dfrac{1}{3}\) - \(\dfrac{1}{15}\)
2/ (2x - 5) = (x - 3) = 0
3/ (3x - 4) - (2x - 5) = 3
4/ (2x + 1) x (\(\dfrac{1}{2}\)x - 1) = 0
1) PT \(\Leftrightarrow\dfrac{x+3}{15}=\dfrac{4}{15}\) \(\Rightarrow x+3=4\) \(\Rightarrow x=1\)
Vậy ...
2) Mạnh dạn đoán đề là \(\left(2x-5\right)\left(x-3\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}2x-5=0\\x-3=0\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=\dfrac{5}{2}\\x=3\end{matrix}\right.\)
Vậy ...
3) PT \(\Rightarrow3x-4-2x+5=3\)
\(\Rightarrow x=2\)
Vậy ...
4) PT \(\Rightarrow\left[{}\begin{matrix}2x+1=0\\\dfrac{1}{2}x-1=0\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{2}\\x=2\end{matrix}\right.\)
Vậy ...
3) Ta có: \(\left(3x-4\right)-\left(2x-5\right)=3\)
\(\Leftrightarrow3x-4-2x+5=3\)
\(\Leftrightarrow x+1=3\)
hay x=2
x+(x+1)+(x+2)+.....+(x+2013)=2035147
x+(x+1)+(x+2)+.....+(x+2013)=2035147
2014x+(2013+1).2013:2=2035147
=> 2014x+2014.2013:2=2035147
=> 2014x+2007006=2035147
=> x=(2035147-2007006):2014
=> x=28141:2014
=> x= ko chia hết
x + (x + 1) + (x + 2) + ... + (x + 2013) = 2035147
2014x + 2013.2014:2 = 2035147
2014x + 2027091 = 2035147
2014x = 2035147 - 2027091
2014x = 8056
x = 8056/2014 = 4
x + (x + 1) + (x + 2) + ... + (x + 2013) = 2035147
2014x + (1 + 2 + ... + 2013) = 2035147
2014x + 2027091 = 2035147
2014x = 8056
x = 4