\(x+\left(x+1\right)+...+\left(x+2013\right)=2035147\)
\(\Leftrightarrow2014x+2027091=2035147\)
\(\Leftrightarrow2014x=8056\)
hay x=4
x+(x+1)+(x+2)+.....+(x+2013)=2035147
x +(x + 1) +(x +2) +(x+3)+....+( x +2013) =2035147
x+(x+1)+(X+2)+....+(x+2013)=2035147 x bằng gì vậy ạ
Tìm x biết: x+(x+1)+(x+2)+...+(x+2013)=2035147
x + ( x+1) + (x+2)+...+(x+2013)=2035147
trả lời hộ mk nha
mk link cho
Tìm x
a, (2x - 15) 5 = ( 2x - 15) 3
b, x + ( x + 1 ) + ( x + 2 ) + ... + ( x + 2013) = 2035147
a, x+1/2013+x+1/2014+x+1/2015=x+1/2016+x+1/2017
b,x-1/2013+x-2/2014+x-3/2015=x-4/2016-2
tìm số nguyên x:
x+(x+1)+(x+2)+...+2012+2013=2013
Tìm x: (1+1/2+1/3+...+1/2013).x+2013=2014/1+2015/2+...+4025/2012+4026/2013
