\(\left(1+\dfrac{100}{20}\right)\) x \(\dfrac{125}{60}\)

\(=6\) x \(\dfrac{125}{60}\)

\(=\dfrac{750}{60}=\dfrac{25}{2}\)

\(\frac{105105}{107107}=\frac{105}{107}\)

lấy \(\frac{105105}{107107}\)rút gon với 1001 nha

#hoc_tot

105105/107107=105105*1001/107*1001

rút gon tuer và mẫu 2 số 1001( bước này ko viết)

=105/107

Rút gọn:

\(\frac{105105}{107107}=\frac{105105:1001}{107107:1001}=\frac{105}{107}\)

Học tốt nha

Tiểu Ngư Nhi

5/4

5/4

5/4

\(\dfrac{120:28=4}{140;28=5}\)

A = \(\dfrac{1+3+5+...+19}{21+23+25+...+39}\)

A = \(\dfrac{(19+1).[(19-1):2+1]:2}{(39+21).[(39-21):2+1]:2}\)

A = \(\dfrac{20.10:2}{60.10:2}\)

A = \(\dfrac{1}{3}\)

a) \(=x^2+2x-2x=x^2\)

b) \(=4-x^2+x^2=4\)

c) \(=x^2-x^3+x^3+27=x^2+27\)

d) \(=4x^2+4xy+y^2+4x^2-8x^2-4xy=y^2\)

\(\dfrac{5353}{3535}=\dfrac{53}{35}\)

nhớ tick cho mình nhé

\(\dfrac{5353}{3525}=\dfrac{5353:101}{3535:101}=\dfrac{53}{35}\)

cảm ơn các bạn nha

\(A=\left(\dfrac{\sqrt{a}+1}{\sqrt{a}-1}-\dfrac{\sqrt{a}-1}{\sqrt{a}+1}+4\sqrt{a}\right)\left(\sqrt{a}+\dfrac{1}{\sqrt{a}}\right)\left(a>0,a\ne1\right)\)

\(A=\left[\dfrac{\left(\sqrt{a}+1\right)^2}{a-1}-\dfrac{\left(\sqrt{a}-1\right)^2}{a-1}+4\sqrt{a}\right].\left(\dfrac{a+1}{\sqrt{a}}\right)\)

\(A=\left[\dfrac{\left(\sqrt{a}+1+\sqrt{a}-1\right)\left(\sqrt{a}+1-\sqrt{a}+1\right)}{a-1}+\dfrac{4\sqrt{a}\left(a-1\right)}{a-1}\right].\dfrac{a+1}{\sqrt{a}}\)

\(A=\left[\dfrac{4\sqrt{a}+4\sqrt{a}\left(a-1\right)}{a-1}\right].\dfrac{a+1}{\sqrt{a}}\)

\(A=\left[\dfrac{4\sqrt{a}\left(1+a-1\right)}{a-1}\right].\dfrac{a+1}{\sqrt{a}}\)

\(A=\dfrac{\left(4a\sqrt{a}\right)\left(a+1\right)}{\left(a-1\right)\sqrt{a}}=\dfrac{4a\left(a+1\right)}{a-1}=\dfrac{4a^2+4a}{a-1}\)