b)1024(5)-132(5)=892(5)

c)214(5).32(5)=6848(5)

d)211(5):13(5)=17(5)

2,1001(2):11(2)=91(2)

hehe làm bừa sai xin lỗivì tui ko hiểu

Bài 1:

a, 144(5) + 330(5) = 474(5)

b, 1024(5) - 132(5) = 892(5)

c)214(5) . 32(5) = 6848(5)

d)211(5) : 13(5) = 17(5)

Bài 2:

1001(2) : 11(2) = 91(2)

\(=\dfrac{3}{5}+\dfrac{2}{5}\cdot\dfrac{5}{6}=\dfrac{3}{5}+\dfrac{1}{3}=\dfrac{9}{15}+\dfrac{5}{15}=\dfrac{14}{15}\)

\(\dfrac{3}{5}+\dfrac{2}{5}.\dfrac{15}{18}=\dfrac{3}{5}+\dfrac{1}{3}=\dfrac{9}{15}+\dfrac{5}{15}=\dfrac{14}{15}\)

\(\dfrac{3}{5}+\dfrac{1}{3}=\dfrac{14}{15}\)

lỗi

Lỗi rồi bn

= 18/24 - 20/24

= - 1/12

3/4-5/6=18/24+20/24=38/24

tớ nhanh nhất mà

Đúng 100%

Đúng 100%

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3/4 - 5/6 = 18/24 - 20/24 = -2/24 = -1/12

=18+5=23

Bài 1: 

b: \(=\dfrac{x+3-4-x}{x-2}=\dfrac{-1}{x-2}\)

Bài 2: 

a: \(=\dfrac{x+1}{2\left(x+3\right)}+\dfrac{2x+3}{x\left(x+3\right)}\)

\(=\dfrac{x^2+x+4x+6}{2x\left(x+3\right)}=\dfrac{x^2+5x+6}{2x\left(x+3\right)}=\dfrac{x+2}{2x}\)

d: \(=\dfrac{3}{2x^2y}+\dfrac{5}{xy^2}+\dfrac{x}{y^3}\)

\(=\dfrac{3y^2+10xy+2x^3}{2x^2y^3}\)

e: \(=\dfrac{x^2+2xy+x^2-2xy-4xy}{\left(x+2y\right)\left(x-2y\right)}=\dfrac{2x^2-4xy}{\left(x+2y\right)\cdot\left(x-2y\right)}=\dfrac{2x}{x+2y}\)

\(=\dfrac{2}{5}-\dfrac{1}{14}=\dfrac{28-5}{70}=\dfrac{23}{70}\)

\(=\dfrac{2}{5}-\dfrac{1}{14}=\dfrac{23}{70}\)

\(\dfrac{2}{5}-\dfrac{1}{7}.\dfrac{1}{2}=\dfrac{2}{5}-\dfrac{1}{14}=\dfrac{2}{5}+-\dfrac{1}{14}=\dfrac{28}{70}+-\dfrac{5}{70}=\dfrac{23}{70}\)

=\(2.\left(\dfrac{1}{1}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{7}+.....+\dfrac{1}{97}-\dfrac{1}{100}\right)\)

=\(2.\left(\dfrac{1}{1}-\dfrac{1}{100}\right)\)

= \(2.\dfrac{99}{100}\)

=\(\dfrac{99}{50}\)