a) x – 32 : 16 = 48 ó x – 2 = 48 ó x = 48 + 2 ó x = 50

b) 88 – 3.(7+x) = 64 ó 3.(7+x) = 88 – 64 ó 7 + x = 24:3 ó x = 8 – 7 ó x = 1

c) (5+4x) : 3 – 121 : 11 = 4 ó (5+4x) : 3 – 11 = 4 ó (5+4x) : 3 = 4 + 11 ó 5+4x = 15.3 ó 4x = 45 – 5 ó 4x = 40 ó x = 10

d) 15 – 2(3x+1) = 11.13 – 130 ó 15 – 2(3x+1) = 143 – 130 ó 15 – 2(3x+1) = 13

ó 2(3x+1) = 15 – 13 ó 3x + 1 = 2:2 ó 3x = 1 – 1 ó 3x = 0 ó x = 0

\(C=17^0+\left[15^{13}:15^{11}+\left(135-130\right)^3\right]\)

\(C=1+\left(15^2+5^3\right)\)

\(C=1+225+125\)

\(C=351\)

C=17⁰+\(\left[15^{13}:15^{11}+\left(135-130\right)^3\right]\)

=1+\(\left[15^2+5^3\right]\)=1+15²+5³=1+225+125=351

\(C=17^0+\left[15^3:15^{11}+\left(135-130\right)^2\right]\\ C=1+\left[15^2+5^3\right]\\ C=1+350\\ C=351\)

15 - 2( 3\(x\) + 1) = 11 \(\times\) 13 - 130

15 - 2(3\(x\) + 1) = 143 - 130

15 - 2(3\(x\) + 1) = 13

        2(3\(x\) + 1) = 15 - 13 

         2(3\(x\) +1) = 2

            3\(x\) + 1  = 2:2

            3\(x\) + 1  =1

            3\(x\)        = 0

               \(x\) = 0

15-2(3x+1)=11x13-130

15-2(3x+1)=143-130

15-2(3x+1)=13

     2(3x+1)=15-13

2(3x+1)=2

3x+1=2:2

3x+1=1

3x=0

Vậy x=0

` @ L I N H `

15 - 2( 3$x$ + 1) = 11 $\times$ 13 - 130

15 - 2(3$x$ + 1) = 143 - 130

15 - 2(3$x$ + 1) = 13

        2(3$x$ + 1) = 15 - 13 

         2(3$x$ +1) = 2

            3$x$ + 1  = 2:2

            3$x$ + 1  =1

            3$x$        = 0

               $x$ = 0

x=-36

x=11

x=100

x=14

x=-36

x=11

x=100

x=14

2: \(\Leftrightarrow\left(\dfrac{x+1}{12}-1\right)+\left(\dfrac{x+2}{13}-1\right)=\left(\dfrac{x+3}{14}-1\right)+\left(\dfrac{x+4}{15}-1\right)\)

=>x-11=0

=>x=11

3: \(\Leftrightarrow\left(\dfrac{x-85}{15}-1\right)+\left(\dfrac{x-74}{13}-2\right)+\left(\dfrac{x-67}{11}-3\right)+\left(\dfrac{x-64}{9}-4\right)=0\)

=>x-100=0

=>x=100

x = 60 nha bn !!!

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