50%x X+2/3xX=X+4
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Tìm x:
A. {4/7 x X - 1} x 3 = 1/21
B. 3 + x/5 = 3xX+7/5
C. 2/3 x X - 1/3 x X = 5/9
D. {X - 2 1/4} x { -2/3 } x 50% = 2 5/6
giải rõ ràng giúp ạ
càng kĩ thì càng cám ơn
A.\(\left(\frac{4}{7}.x-1\right).3=\frac{1}{21}\)
\(\frac{4}{7}.x-1=\frac{1}{21}:3\)
\(\frac{4}{7}.x-1=\frac{1}{21}.3\)
\(\frac{4}{7}.x-1=\frac{1}{7}\)
\(\frac{4}{7}.x=1+\frac{1}{7}\)
\(\frac{4}{7}.x=\frac{8}{7}\)
\(x=\frac{8}{7}:\frac{4}{7}\)
\(x=\frac{8}{7}.\frac{7}{4}\)
\(x=2\)
Vậy x=2
C.\(\frac{2}{3}.x-\frac{1}{3}.x=\frac{5}{9}\)
\(\left(\frac{2}{3}-\frac{1}{3}\right).x=\frac{5}{9}\)
\(\frac{1}{3}.x=\frac{5}{9}\)
\(x=\frac{5}{9}:\frac{1}{3}\)
\(x=\frac{5}{9}.3\)
\(x=\frac{5}{3}\)
Vậy \(x=\frac{5}{3}\)
D. \(\left(x-2\frac{1}{4}\right).\left(\frac{-2}{3}\right).50\%=2\frac{5}{6}\)
\(x.\frac{-2}{3}-\frac{9}{4}.\frac{-2}{3}=\frac{17}{6}:\frac{1}{2}\)
\(x.\frac{-2}{3}-\frac{-3}{2}=\frac{17}{6}.2\)
\(x.\frac{-2}{3}+\frac{3}{2}=\frac{17}{3}\)
\(x.\frac{-2}{3}=\frac{17}{3}-\frac{3}{2}\)
\(x.\frac{-2}{3}=\frac{34}{6}-\frac{9}{6}\)
\(x.\frac{-2}{3}=\frac{25}{6}\)
\(x=\frac{25}{6}:\frac{-2}{3}\)
\(x=\frac{25}{6}.\frac{3}{-2}\)
\(x=\frac{25}{-4}\)
Vậy \(x=\frac{25}{-4}\)
2/3xX-X/2-1/2=1/4
`@` `\text {Ans}`
`\downarrow`
\(\dfrac{2}{3}\times x-\dfrac{x}{2}-\dfrac{1}{2}=\dfrac{1}{4}?\)
`=>`\(\dfrac{2}{3}x-\dfrac{x}{2}-\dfrac{1}{2}=\dfrac{1}{4}\)
`=>`\(\dfrac{4x}{6}-\dfrac{3x}{6}-\dfrac{1}{2}=\dfrac{1}{4}\)
`=>`\(\dfrac{x}{6}-\dfrac{1}{2}=\dfrac{1}{4}\)
`=>`\(\dfrac{x}{6}=\dfrac{1}{4}+\dfrac{1}{2}\)
`=>`\(\dfrac{x}{6}=\dfrac{3}{4}\)
`=> 4x=3*6`
`=> 4x=18`
`=> x=`\(\dfrac{18}{4}=\dfrac{9}{2}=4,5\)
Vậy, `x=4,5.`
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Ai giúp mik với
4/5 x (3xX+2)-3/4 x X = 0,25
1.Tìm x,biết
a.5/7+4/3:x=1/7
b.5/3xX-1/4=2/6
a)4/3:x=-4/7 b)5/3.x=7/12
⇒x=-16/21 ⇒x=7/20
a. \(\dfrac{5}{7}+\dfrac{4}{3}:x=\dfrac{1}{7}\)
<=> \(\dfrac{5}{7}+\dfrac{4}{3}.\dfrac{1}{x}=\dfrac{1}{7}\)
<=> \(\dfrac{5}{7}+\dfrac{4}{3x}=\dfrac{1}{7}\) ĐKXĐ: x \(\ne\) 0
<=> \(\dfrac{15x}{21x}+\dfrac{28}{21x}=\dfrac{3x}{21x}\)
<=> 15x + 28 = 3x
<=> 15x - 3x = -28
<=> 12x = -28
<=> x = \(\dfrac{-28}{12}=-\dfrac{7}{3}\)
b. \(\dfrac{5}{3}x.\dfrac{-1}{4}=\dfrac{2}{6}\)
<=> \(\dfrac{-5x}{12}=\dfrac{2}{6}\)
<=> -5x . 6 = 12 . 2
<=> -30x = 24
<=> x = \(-\dfrac{4}{5}\)
b)0,5xx+2/3xx+2/3=7/12
c)3/5-2/15:x=1/2
d)50%xx-2va1/2=2va5/6
e)(2va4/5xx-50):2/3-51
f)(4va1/2-2xx)x3va2/3=11/15
g)02/5-(2va1/2xx-3):15=1/10
h)(3/4+x)x1/1+5va1/6-1va1/6
b)0,5xx+2/3xx+2/3=7/12
c)3/5-2/15:x=1/2
d)50%xx-2va1/2=2va5/6
e)(2va4/5xx-50):2/3-51
f)(4va1/2-2xx)x3va2/3=11/15
g)02/5-(2va1/2xx-3):15=1/10
h)(3/4+x)x1/1+5va1/6-1va1/6
tìm x:
a,32:(3xX-2)=8
b,75:(X-18)=25
c,(15-6xX)x243=729
d,4x(X-12)+9=17
e,20-2x(X+4)=4
a) 32 : (3.x - 2) = 8
3x - 2 = 32 : 8
3x - 2 = 4
3x = 4 + 2
3x = 6
x = 6 : 3
x = 2
b) 75 : (x - 18) = 25
x - 18 = 75 : 25
x - 18 = 3
x = 3 + 18
x = 21
c) (15 - 6.x) . 243 = 729
15 - 6x = 729 : 243
15 - 6x = 3
6x = 15 - 3
6x = 12
x = 12 : 6
x = 2
d) 4.(x - 12) + 9 = 17
4(x - 12) = 17 - 9
4(x - 12) = 8
x - 12 = 8 : 4
x - 12 = 2
x = 2 + 12
x = 14
e) 20 - 2.(x + 4) = 4
2(x + 4) = 20 - 4
2(x + 4) = 16
x + 4 = 16 : 2
x + 4 = 8
x = 8 : 2
x = 4
`32: ( 3xx x -2)=8`
`3xx x-2=32:8`
`3xx x-2=4`
`3 xx x=4+2`
`3xx x=6`
`x=6:3`
`x=2`
__
`75 : (x-18) =25`
`x-18=75:25`
`x-18= 3`
`x=3+18`
`x=21`
__
`(15-6 xx x ) xx 243 =729`
`15-6 xx x = 729 : 243`
`15-6 xx x = 3`
`6 xx x=15-3`
`6 xx x=12`
`x=12:6`
`x=2`
__
`4 xx (x-12)+9=17`
`4 xx (x-12)=17-9`
`4 xx (x-12)= 8`
`x-12=8:4`
`x-12=2`
`x=2+12`
`x=14`
__
`20-2xx(x+4)=4`
`2xx(x+4)=20-4`
`2xx(x+4)=16`
`x+4=16:2`
`x+4=8`
`x=8-4`
`x=4`
\(a,32:\left(3\times X-2\right)=8\\ 3\times X-2=32:8=4\\ 3\times X=4+2=6\\ X=\dfrac{6}{3}=2\\ Vậy:X=2\\ ---\\ b,75:\left(X-18\right)=25\\ X-18=75:25=3\\ X=3+18=21\\ Vậy:X=21\\ ---\\ c,\left(15-6\times X\right)\times243=729\\ 15-6\times X=729:243=3\\ 6\times X=15-3=12\\ X=\dfrac{12}{6}=2\\ Vậy:X=2\\ ---\\ d,4\times\left(X-12\right)+9=17\\ 4\times\left(X-12\right)=17-9=8\\ X-12=8:4=2\\ X=2+12=14\\ Vậy:X=14\\ ---\\ e,20-2\times\left(X+4+4\right)=4\\ 2\times\left(X+4\right)=20-4=16\\ X+4=16:2=8\\ X=8-4=4\\ Vậy:X=4\)
tìm nghiệm của đa thức:
3xX(x+1)^2-3x^2(x+2)-4x^2-5x+6\(x^2-5x+6=0\)
\(x^2-2x-3x+6=0\)
\(x\left(x-2\right)-3\left(x-2\right)=0\)
\(\left(x-3\right)\left(x-2\right)=0\)
\(x-3=0\)\(x=3\)
\(x-2=0\)\(x=2\)
Vậy x = 3 và x = 2 là nghiệm của đa thức trên. (cái đa thức kia bạn ghi rõ lại hơn đi)