=>2x-4+11 chia hết cho x-2

=>\(x-2\in\left\{1;-1;11;-11\right\}\)

=>\(x\in\left\{3;1;13;-9\right\}\)

6B

10C

8A

a: \(\Leftrightarrow2x\left(x+2\right)+4>x^2+4x+4\)

\(\Leftrightarrow2x^2+4x-x^2-4x>0\)

=>x<>0

b: \(\Leftrightarrow3\left(1-2x\right)-24x< 4\left(1-5x\right)\)

=>3-6x-24x<4-20x

=>-30x+3<4-20x

=>-10x<1

hay x>-1/10

c: \(\Leftrightarrow x^2+6x+8>x^2+10x+16+26\)

=>6x+8>10x+42

=>-4x>34

hay x<-17/2

Bài 2:

a) \(\dfrac{2}{15}-\dfrac{7}{10}=\dfrac{4}{30}-\dfrac{21}{30}=-\dfrac{17}{30}\)

b) \(\dfrac{-3}{14}+\dfrac{2}{21}=\dfrac{-9}{42}+\dfrac{4}{42}=\dfrac{-5}{42}\)

c) \(\dfrac{-6}{9}+\dfrac{-12}{16}=\dfrac{-96}{144}+\dfrac{-108}{144}=\dfrac{-204}{144}=-\dfrac{17}{12}\)

Bài 3: 

a) \(\dfrac{3}{8}+\dfrac{-5}{6}=\dfrac{3}{8}-\dfrac{5}{6}=\dfrac{18}{48}-\dfrac{40}{48}=-\dfrac{22}{48}=-\dfrac{11}{24}\)

b) \(\dfrac{-8}{18}-\dfrac{15}{27}=\dfrac{-24}{54}-\dfrac{30}{54}=\dfrac{-54}{54}=-1\)

c) \(\dfrac{2}{21}-\dfrac{-1}{28}=\dfrac{8}{84}-\dfrac{-3}{84}=\dfrac{11}{84}\)

dài thế bạn?

:v

Câu 2: 

uses crt;

var i,n,t:integer;

begin

clrscr;

n:=0;

t:=0;

repeat

n:=n+1;

t:=t+n;

until t>100;

writeln(t);

readln;

end.

C2:

var i,s: integer;

begin

while s<=100 do begin

s:=s+i;

i:=i+1;

end;

write(s);

readln

end.

Vì tam giác ABC cân 

=> AB = AC = 8cm

Theo đề bài : AB + AC + BC = 18cm

=> 8 + 8 + BC = 18cm

=> BC = 18 - ( 8 + 8 )

=> BC = 2cm