Rut gon phan so:
x^39+x^36+...+x^3+1
phan x^40+x^38+...+x^2+1
1) Ket qua khi rut gon phan thuc \(\dfrac{x^2+2x+1}{x^3+1}\) la:
\(=\dfrac{\left(x+1\right)^2}{\left(x+1\right)\left(x^2-x+1\right)}=\dfrac{x+1}{x^2-x+1}\)
Cho cac so nguyen duong a,b,c,x,y,z
1, Biet 1/a = 3/b + c = 5/c + a. Hay rut gon phan so A = a/2b - c
2. Biet a/b = 2b/cc = 4c/a. Hay rut gon phan so B = ab + bc + ca/a2 + b + c2
3. Biet x/a = y/b =z/c. Hay rut gon phan so C = x*y*z*(b+c)*(c+a)*(a+b)/a*b*c(y+z)*(z+x)*(x+y)
4. Biet ab/a + 2b = 2/5; bc/b + 2c = 3/4; ca/c +2a = 3/5. Hay rut gon phan so D = abc/ab+bc+ca
5. Biet 3/a -4b = 5c. Hay rut gon phan so E = 3bc + ab - 4ac/6bc - 8ac -ab
Giup minh nhe! Ai lam duoc va dung cho tick.
Thanks cac ban
xin lỗi tớ ấn nhầm chỗ M=7 tớ làm lại rồi đó
ban tra loi het cac cau hoi phia tren kia ho minh dc ko?
Cho cac so nguyen duong a,b,c,x,y,z
1, Biet 1/a = 3/b + c = 5/c + a. Hay rut gon phan so A = a/2b - c
2. Biet a/b = 2b/cc = 4c/a. Hay rut gon phan so B = ab + bc + ca/a2 + b + c2
3. Biet x/a = y/b =z/c. Hay rut gon phan so C = x*y*z*(b+c)*(c+a)*(a+b)/a*b*c(y+z)*(z+x)*(x+y)
4. Biet ab/a + 2b = 2/5; bc/b + 2c = 3/4; ca/c +2a = 3/5. Hay rut gon phan so D = abc/ab+bc+ca
5. Biet 3/a -4b = 5c. Hay rut gon phan so E = 3bc + ab - 4ac/6bc - 8ac -ab
Giup minh nhe! Ai lam duoc va dung cho tick.
Thanks cac ban
(x-5)(x^2+26)+(5-x)(1-5x)
rut gon phan thuc
rut gon phan thuc A=(x^3-6x+7)/(x^3+5x^2-2x-24)
A= [3/2-(x^4-x^4+1/x^2+1)*x^2-x(4*x-1)-4/x^7+6*x^4-x-6]/x^3+29*x+78/3*x^2+12*x-36.rut gon
RUT GON PHAN SO SAU : 3 x 5 x 11 x 13/33 x 35 x 37
x^39+x^36+...+x^3+1
____________________
x^40+x^38+...+x^2+1
Rut gon phan thuc
a, 3x(1-x)\2(x-1)
b, 3(x-y)(x-z)^2\6(x-y)(x-z)
c, x^2-16\4x-x^2 (x#0,x#4)
a, = -3/2
b, = x-z/2
c, = (x-4).(x+4)/-x.(x-4) = -(x+4)/x = -x-4/x
k mk nha