\(\frac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}=\frac{\left(2^2\right)^5.\left(3^2\right)^4-2.\left(2.3\right)^9}{2^{10}.3^8+\left(2.3\right)^8.2^2.5}\)

                            \(=\frac{2^{10}.3^8-2.2^9.3^9}{2^{10}.3^8+2^8.3^8.2^2.5}\)

                              \(=\frac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+2^{10}.3^8.5}\)

                                \(=\frac{2^{10}.3^8.\left(1-3\right)}{2^{10}.3^8.\left(1+5\right)}\)

                                 \(=\frac{-2}{6}=\frac{-1}{3}\)

tự làm cho giỏi

là dấu nhân nha

 ( 4^5.9^4+2.6^9) : (2^10.3^8-6^8.2) = \(\frac{4^5.9^4+2.6^9}{2^{10}.3^8-6^8.2}=\frac{\left(2^2\right)^5.\left(3^2\right)^4+2.6^9}{2^{10}.3^8-6^8.2}\)

= \(\frac{2^{10}.3^8+2.6^9}{2^{10}.3^8-6^8.2}=\frac{2\left(6^8.8\right)}{2.6^8}=\frac{6^8.8}{6^8}=8\)

Ết nha bạn ( eight : 8 )

\(A=\frac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+2^{10}.3^8.5}\)

\(A=\frac{2^{10}.3^8.\left(1-3\right)}{2^{10}.3^8\left(1+5\right)}\)

\(A=\frac{1-3}{1+5}\)

\(A=\frac{-1}{3}\)

Đề bài yêu cầu gì?

\(A=\dfrac{4^5\cdot9^4-2\cdot6^9}{2^{10}\cdot3^8+6^8\cdot20}\)

\(=\dfrac{2^{10}\cdot3^8-2^{10}\cdot3^9}{2^{10}\cdot3^8+3^8\cdot2^{10}\cdot5}\)

\(=\dfrac{2^{10}\cdot3^8\left(1-3\right)}{2^{10}\cdot3^8\cdot\left(1+5\right)}\)

\(=-\dfrac{2}{6}=-\dfrac{1}{3}\)

\(A=\dfrac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}\)

\(=\dfrac{\left(2^2\right)^5.\left(3^2\right)^4-2.\left(2.3\right)^9}{2^{10}.3^8+\left(2.3\right)^8.2^2.5}\)

\(=\dfrac{4^5.3^8-2.2^9.3^9}{2^{10}.3^8+2^8.3^8.2^2.5}\)

\(=\dfrac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+2^{10}.3^8.5}\)

\(=\dfrac{2^{10}.3^8\left(1-3\right)}{2^{10}.3^8\left(1+5\right)}\)

\(=\dfrac{-2}{6}=\dfrac{-1}{3}\)

\(A=\dfrac{\left(2^2\right)^5.\left(3^2\right)^4-2.\left(2.3\right)^9}{2^{10}.3^8+\left(2.3\right)^8.2^2.5}=\dfrac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+2^{10}.3^8.5}=\dfrac{2^{10}.3^8.\left(1-3\right)}{2^{10}.3^8.\left(1+5\right)}=\dfrac{-2}{6}=-\dfrac{1}{3}\)

\(A=\dfrac{4^5.9^4-2.6^9}{2^{10}3^8+6^8.20}\)

\(A=\dfrac{\left(2^2\right)^5.\left(3^2\right)^4-2\left(2.3\right)^9}{2^{10}.3^8+\left(2.3\right)^8.2^2.5}\)

\(A=\dfrac{4^5.3^8-2.2^9.3^9}{2^{10}.3^8+2^8.3^8.2^2.5}\)

\(A=\dfrac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+2^{10}.3^8.5}\)

\(A=\dfrac{\left(2^{10}.3^8\right)\left(1-3\right)}{\left(2^{10}.3^8\right)\left(1+5\right)}\)

\(A=-\dfrac{2}{6}=-\dfrac{1}{3}\)

Vậy \(A=-\dfrac{1}{3}\)

\(\dfrac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}=\dfrac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+2^{10}.3^8.5}=\dfrac{2^{10}.3^8\left(1-3\right)}{2^{10}.3^8\left(1-5\right)}=\dfrac{-2}{-4}=\dfrac{1}{2}\)

\(\frac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}=\frac{2^{10}.3^8-2.2^9.3^9}{2^{10}.3^8+2^8.3^8.2^2.5}=\frac{2^{10}.3^8-2^{10}.3^8.3}{2^{10}.3^8+2^{10}.3^8.5}=\frac{2^{10}.3^8\left(1-3\right)}{2^{10}.3^8\left(1+6\right)}=\frac{-2}{6}=\frac{-1}{3}=-\frac{1}{3}\)