a) 64 - 4 x 6 - 48

= 4 x 16 - 4 x 6 - 48

= 4 x (16 - 6) - 48

= 4 x 10 - 48

= 40 - 48

= -8

b) 96 - 32 : 4 - 49

= 96 - 8 - 49

= 39

Tính

a ) 

64 - 4 x 6 - 48

= 64 - 24 - 48

= 40 - 48 

= -8

b )

96 - 32 : 4 - 49

= 96 - 8 - 49

= 88- 49

=39

tk mk nha

mơn nhiều ạ 

a) 64-4x6-48

=4x16-4x6-48

=4x(16-6) - 48

=4 x 10 - 48

=40-48

=8

b)96-32:4-49

=96-8-49

=39

a) 22+36=58     96−32=64     62−30=32

89−47=42     44+44=88     45−5=40

\(\sqrt{15-6\sqrt{6}}+\sqrt{35-12\sqrt{6}}=\sqrt{\left(3-\sqrt{6}\right)^2}+\sqrt{\left(3\sqrt{3}-2\sqrt{2}\right)^2}\)

\(=3-\sqrt{6}+3\sqrt{3}-2\sqrt{2}\)

\(\sqrt{17-3\sqrt{32}}+\sqrt{17+3\sqrt{32}}=\sqrt{\left(3-2\sqrt{2}\right)^2}+\sqrt{\left(3+2\sqrt{2}\right)^2}\)

\(=3-2\sqrt{2}+3+2\sqrt{2}=6\)

\(\sqrt{49-5\sqrt{96}}+\sqrt{49+5\sqrt{96}}=\sqrt{\left(5-2\sqrt{6}\right)^2}+\sqrt{\left(5+2\sqrt{6}\right)^2}\)

\(=5-2\sqrt{6}+5+2\sqrt{6}=10\)

\(\sqrt{13-\sqrt{160}}+\sqrt{53+4\sqrt{90}}=\sqrt{\left(2\sqrt{2}-\sqrt{5}\right)^2}+\sqrt{\left(3\sqrt{5}+2\sqrt{2}\right)^2}\)

\(=2\sqrt{2}-\sqrt{5}+3\sqrt{5}+2\sqrt{2}=2\sqrt{5}+4\sqrt{2}\)

a: \(\sqrt{15-6\sqrt{6}}+\sqrt{35-12\sqrt{6}}\)

\(=3-\sqrt{6}+3\sqrt{3}-2\sqrt{2}\)

b: \(\sqrt{17-3\sqrt{32}}+\sqrt{17+3\sqrt{32}}\)

\(=3-2\sqrt{2}+3+2\sqrt{2}\)

=6

c: Ta có: \(\sqrt{49-5\sqrt{96}}+\sqrt{49+5\sqrt{96}}\)

\(=5-2\sqrt{6}+5+2\sqrt{6}\)

=10

d: Ta có: \(\sqrt{13-\sqrt{160}}+\sqrt{53+4\sqrt{90}}\)

\(=\sqrt{13-4\sqrt{10}}+\sqrt{53+4\sqrt{90}}\)

\(=2\sqrt{2}-\sqrt{5}+3\sqrt{5}+2\sqrt{2}\)

\(=2\sqrt{5}+4\sqrt{2}\)

a) \(\frac{x-1}{99}+\frac{x-2}{98}+\frac{x-3}{97}+\frac{x-4}{96}=4\)

\(\Rightarrow\frac{x-1}{99}-1+\frac{x-2}{98}-1+\frac{x-3}{97}-1+\frac{x-3}{96}-1=4-4\)

\(\Rightarrow\frac{x-100}{99}+\frac{x-100}{98}+\frac{x-100}{97}+\frac{x-100}{96}=0\)

\(\Rightarrow\left(x-100\right)\left(\frac{1}{99}+\frac{1}{98}+\frac{1}{97}+\frac{1}{96}\right)=0\)

\(\Rightarrow x-1=0\) ( vì \(\frac{1}{99}+\frac{1}{98}+\frac{1}{97}+\frac{1}{96}\ne0\) )

Vậy x = 1

b) \(\frac{x+1}{99}+\frac{x+2}{98}+\frac{x+3}{97}=3\)

\(\Rightarrow\frac{x+1}{99}+1+\frac{x+2}{98}+1+\frac{x+3}{97}+1=3-3\)

\(\Rightarrow\frac{x+100}{99}+\frac{x+100}{98}+\frac{x+100}{97}=0\)

\(\Rightarrow\left(x+100\right).\left(\frac{1}{99}+\frac{1}{98}+\frac{1}{97}\right)=0\)

Vì \(\frac{1}{99}+\frac{1}{98}+\frac{1}{97}\ne0\)

=> x + 100 = 0

=> x           = -100

c) \(\frac{x-1}{99}+\frac{x-2}{49}+\frac{x-4}{32}=6\)

\(\Rightarrow\frac{x-1}{99}-1+\frac{x-2}{49}-2+\frac{x-4}{32}-3=6-6\)

\(\Rightarrow\frac{x-100}{99}+\frac{x-100}{49}+\frac{x-100}{32}=0\)

\(\Rightarrow\left(x-100\right)\left(\frac{1}{99}+\frac{1}{49}+\frac{1}{32}\right)=0\)

Vì \(\frac{1}{99}+\frac{1}{49}+\frac{1}{32}\ne0\)

=> x - 100 = 0

=> x           = 100

Chúc bạn học tốt

có người khác trả lời trước rồi nên chị ko trả lời đâu nhé em trai

a)16.4^x=4⁸

^{\(4^2.4^x=4^{8^{ }}\)}

^{\(4^x=4^{8^{ }}:4^2\)}

\(4^x=4^{6^{ }}\)

\(x=6\)
b)(X-2)(X-5)=0

\(\Rightarrow x-2=0\rightarrow x=2\)

\(x-5=0\rightarrow x=5\)

Vậy x∈ {2;5}
c)2^x+2^x+1=96

\(2^x.1+2^{x^{ }}.2\)

\(2^x.\left(1+2\right)=96\)

\(2^x.3=96\)

\(2^x=96:3\)

\(2^x=32\)

\(2^x=2^5\)

\(x=5\)

\(Zzz\) 😪

Tính hợp lí

a,15.(27+ 18 +6 ) + 15.( 23 +12)

  = 15(27+18+6+23+12)

  = 15.86

  = 1290

b,24.(15 + 49 ) + 12. ( 50 + 42 )

=12.2(15+49)+12.(50+42)

= 12(30+98)+12(50+42)

=12(30+98+50+42)

=12.220

= 2640

c,53.(51+4)+53.(49+96) +53

=53(51+4)+53(49+96)+53.1

=53(51+4+49+96+1)

=53.201

=10653

d,42.( 15 +96) +6.(25 +4).7  

=42(15+96)+42(25+4)

=42(15+96+25+4)

=42.140

=5880

tick đúng cho mk nha pikachu

20-2.(x+14)=16

Tính hợp lí:

\(a)\)\(15.\left(27+18+6\right)+15.\left(23+12\right)\)

\(=\)\(15.51+15.35\)

\(=\)\(15.\left(51+35\right)\)

\(=\)\(15.86\)

\(=\)\(1290\)

\(b)\)\(24.\left(15+49\right)+12.\left(50+42\right)\)

\(=\)\(24.64+12.92\)

\(=\)\(1536+1104\)

\(=\)\(2640\)

\(c)\)\(53.\left(51+4\right)+53.\left(49+96\right)+53\)

\(=\)\(53.55+53.145+53\)

\(=\)\(53.\left(145+55+1\right)\)

\(=\)\(53.201\)

\(=\)\(10653\)

\(d)\)\(42.\left(15+96\right)+6.\left(25+4\right).7\)

\(=\)\(42.\left(15+96\right)+42.\left(25+4\right)\)

\(=\)\(42.111+42.29\)

\(=\)\(42.140\)

\(=\)\(5880\)

Giúp đi

Câu 4:

\(4^{n+2}-4^{n-1}=252\\ \Leftrightarrow4^{n-1}.\left(4^3-1\right)=252\\ \Leftrightarrow4^{n-1}.63=252\\ \Leftrightarrow4^{n-1}=\dfrac{252}{63}=4=4^1\\ \Rightarrow n-1=1\\ \Rightarrow n=2\)

Câu 7:

\(\left(\dfrac{36}{49}\right)^4:\left(-\dfrac{6}{7}\right)^6=\left(\dfrac{6}{7}\right)^{2.4}:\left(\dfrac{6}{7}\right)^6=\left(\dfrac{6}{7}\right)^8:\left(\dfrac{6}{7}\right)^6=\left(\dfrac{6}{7}\right)^{8-6}=\left(\dfrac{6}{7}\right)^2=\dfrac{36}{49}\)

Câu 8:

\(13^{96}=\left(13^3\right)^{32}=2197^{32}\\ 15^{64}=\left(15^2\right)^{32}=225^{32}\\ Vì:2197^{32}>225^{32}\left(Do:2197>225\right)\Rightarrow13^{96}>15^{64}\)