3x - 10= -14
3x-10=14
$3x-10=14$
$3x=14+10$
$3x=24$
$x=24:3$
$x=8$
(7x−12)+(8x−10)+(3x−14)=4.
Lời giải:
$(7x-12)+(8x-10)+(3x-14)=4$
$(7x+8x+3x)-(12+10+14)=4$
$18x-36=4$
$18x=40$
$x=\frac{20}{9}$
\(7x-12+8x-10+3x-14-4=0\)
\(18x-40=0\)
\(x=\dfrac{40}{18}=\dfrac{20}{9}\)
Tính:a) (2y-5)2-2y.(2y-10)
b)(3x-4).(3x+4)- ((-3x)2 -14 )
a) (2y - 5)2 - 2y(2y - 10)
= 4y2 - 20y + 25 - 4y2 + 20y
= 25
b) (3x - 4)(3x + 4) - [(-3x)2 -14]
= 9x2 - 16 - 9x2 + 14
= - 2
Tính: a,x²-5x+6/ x²+7x+12 : x²-4x+4/ x²+3x b,x²+2x-3/ x²+3x-10 : x²+7x+12/ x²-9x+14
a: \(\dfrac{x^2-5x+6}{x^2+7x+12}:\dfrac{x^2-4x+4}{x^2+3x}\)
\(=\dfrac{\left(x-2\right)\left(x-3\right)}{\left(x+3\right)\left(x+4\right)}\cdot\dfrac{x\left(x+3\right)}{\left(x-2\right)^2}\)
\(=\dfrac{x\left(x-3\right)}{\left(x-2\right)\left(x+4\right)}\)
b: \(\dfrac{x^2+2x-3}{x^2+3x-10}:\dfrac{x^2+7x+12}{x^2-9x+14}\)
\(=\dfrac{\left(x+3\right)\left(x-1\right)}{\left(x+5\right)\left(x-2\right)}\cdot\dfrac{\left(x-2\right)\left(x-7\right)}{\left(x+3\right)\left(x+4\right)}\)
\(=\dfrac{\left(x-1\right)\left(x-7\right)}{\left(x+5\right)\left(x+4\right)}\)
Thực hiện phép chia phân thức: x 2 + 2 x - 3 x 2 + 3 x - 10 : x 2 + 7 x + 12 x 2 - 9 x + 14
Bài 1: Tìm số nguyên x biết
a) 14 + 2x = 14 - (-18)
b) 2x + 150 = x + 5.(-4)
c) 5x + 10 = 20 - (3x - 6)
d) 9x - 2x + 10 = 2x + 9
***a, 14+2x=-32
2x=-32-14
2x=-46
x=-46/2
x=-23
Vậy x=-23
xy+14+2y+7x=-10
xy+5x+y=4
xy+x+y=2
xy-10+5x-3y=2
xy-1=3x+5y+4
3x+4y-xy=15
xy+x+y=2
xy+x+y+1=2+1
(xy+x)+(y+1)=3
x(y+1)+(y+1)=3
(x+1)(y+1)=3=1.3=3.1=-1.-3=-3.-1
\(\Rightarrow\left[{}\begin{matrix}x+1=1;y+1=3\\x+1=3;y+1=1\\x+1=-1;y+1=-3\\x+1=-3;y+1=-1\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0;y=2\\x=2;y=0\\x=-2;y=-4\\x=-4;y=-2\end{matrix}\right.\)
Vậy:.................
xy+14+2y+7x= -10
\(\Leftrightarrow\)y(x+2)+7(x+2)=-10
\(\Leftrightarrow\)(y+7)(x+2)=-10=1.(-10)=2.(-5)=5.(-2)=10.(-1)
y+7 | 1 | 2 | 5 | 10 |
x+2 | -10 | -5 | -2 | -1 |
y | -6 | -5 | -2 | 3 |
x | -12 | -7 | -4 | -3 |
3x -(-17)=14
/x+9/.2=10
Làm hộ mình
3x-(-17)=14
3x=14+(-17)
3x=-3
x=(-3):3
x=-1
Vậy x=-1.
|x+9|.2=10
|x+9|=10:2
|x+9|=5
\(\Rightarrow\orbr{\begin{cases}x+9=-5\\x+9=5\end{cases}\Rightarrow\orbr{\begin{cases}x=-14\\x=-4\end{cases}}}\)
Vậy \(x\in\left\{-14;-4\right\}\)
\(3x-\left(-17\right)=14\)
\(3x+17=14\)
\(3x=14-17\)
\(3x=-3\)
\(x=-1\)
\(a,\left|x+9\right|.2=10\)
\(\left|x+9\right|=5\)
\(th1:x+9=5\)
\(x=-4\)
\(Th2:x+9=-5\)
\(x=-14\)
Vậy.....
hok tốt!!
3x + 17 = 14
suy ra 3x= 14 - 17
suy ra 3x= -3
suy ra x= -1
b) /x+9/ .2=10
suy ra /x+9/ = 5
suy ra x+9 = 5 hoặc x+9 = -5
suy ra x = -4 hoặc x= -14
Vậy x thuộc {-14; -4}
(x-5)\(^{10}\)+ (3x-y+14)\(^{10}\) < 0