\(\frac{1}{8}+\frac{1}{24}+\frac{1}{48}+\frac{1}{80}+\frac{1}{120}\)

\(=\frac{1}{2}(\frac{1}{2.4}+\frac{1}{4.6}+\frac{1}{6.8}+\frac{1}{8.10}+\frac{1}{10.12})\)

\(=\frac{1}{2}(\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+..+\frac{1}{10}-\frac{1}{12})\)

\(=\frac{1}{2}\cdot\left(\frac{1}{2}-\frac{1}{12}\right)=\frac{1}{2}\cdot\frac{5}{12}=\frac{5}{24}\)

\(1200:24-\left(19-x\right)=38\)

\(\Leftrightarrow50-\left(19-x\right)=38\)

\(\Leftrightarrow19-x=50-38\)

\(\Leftrightarrow19-x=12\)

\(\Leftrightarrow x=7\)

\(2-\left[\left(5\frac{5}{24}+x\right)-7\frac{5}{24}\right]=0\)

\(2-\left[\frac{125}{24}+x-\frac{173}{24}\right]=0\)

\(2-\left(\frac{-48}{24}+x\right)=0\)

\(\frac{-48}{24}+x=2-0=2\)

\(\Rightarrow x=4\)

P/s: Có thể tính sai :<

\(\dfrac{15^2\cdot16^4-15^3\cdot16^3}{12^2\cdot20^3-20^2\cdot12^3}\)
\(=\dfrac{15^2\cdot16^3\left(16-15\right)}{12^2\cdot20^2\left(20-12\right)}\)
\(=\dfrac{3^2\cdot5^2\cdot2^{12}}{2^4\cdot3^2\cdot2^4\cdot5^2\cdot2^3}\)
\(=\dfrac{2^{12}}{2^{11}}=2^1=2\)
 

ko bt

a: Bậc là 3

a) 66,8 : 89 = 0,7505...

b) 8,568 : 3,6 = 2,38

c) 429 : 572 = 0,75

d) 127 : 25,4 = 0,005

Chúc bạn học tốt.

😁😁😁

a) X + 2,14 = 7

               X = 7 - 2,14

               X = 4,86

b) 5,2 x 3,7 - 6,87

    = 19,24 - 6,87

    = 72,37

\(=\left(5x^2+10xy\right)-\left(4x+8y\right)\)

\(=5x\left(x+2y\right)-4\left(x+2y\right)\)

\(=\left(x+2y\right)\left(5x-4\right)\)

5x² + 10xy - 4x - 8y

= ( 5x² +10xy )-( 4x+8y )

= 5x( x + 2y) - 4( x+2y)

=(x+2y)(5x-4)

Chọn câu C