X + 50 = 50 - 0
HM
Những câu hỏi liên quan
A. ( x - 2005 ). 2006= 0
B. 480+ 45. 4=(x + 125 ) : 5 + 260
C. [( x + 50 ) . 50 - 50] : 50 = 50
(195-13.15):(1945+1014)
(x-2005).2006=0
480+45.4=(x+125):5+260
2005.(x-2006)=2005
[(x+50).50-50]:50=50
nhầm
câu c :
=> 480 + 180 = (x + 125) : 5 + 260
=> 660 = (x + 125) : 5 + 260
=> (x + 125) : 5 = 400
=> x + 125 = 2000
=> x = 1875
câu e :
=> (x + 50) . 50 - 50 = 2500
=> (x + 50) . 50 = 2550
=> x + 50 = 51
=> x = 1
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a/ = (195 - 195) : (1945 + 1014) = 0 : (1945 + 1014) = 0
b/ => x - 2005 = 0 => x = 0 + 2005 = 2005
c/ => 480 + 180 = (x + 125) : 5 + 260
=> 300 = (x + 125) : 5 + 260
=> (x + 125) : 5 = 40
=> x + 125 = 8
=> x = -117
d/ => x - 2006 = 1 => x = 2007
e/ => (x + 50) . 50 - 50 = 1
=> (x + 50) . 50 = 51
=> x + 50 = 51/50
=> x = -2449/50
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Tìm x
(x-2005).2006=0
480+45.4=(x+125):5+260
2005.(x-2006)=2005
{(x+50).50-50}:50=50
a)(x-2005).2006=0
=>x-2005=0
=>x=2005
b)480+45.4=(x+125):5+260
=>480+180=(x+125):5+260
=>660=(x+125):5+260
=>(x+125):5=400
=>x+125=2000
=>x=1875
c)2005.(x-2006)=2005
=>x-2006=1
=>x=2007
d){(x+50).50-50}:50=50
=>(x+50).50-50=2500
=>(x+50)*50=2550
=>x+50=51
=>x=1
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a (x-2005). 2006=0
b 2005.(x-2006)=2005
c 480+45.4=(x+125):5+260
d [(x+50).50-50]:50=50
a) (x - 2005 ) . 2006 = 0
x - 2005 = 0 : 2006
x - 2005 = 0
x = 0 + 2005
x = 2005
b) 2005.(x-2006) = 2005
x - 2006 = 2005 : 2005
x - 2006 = 1
x = 1 + 2006
x = 2007
c) 480+45.4=(x+125) : 5 + 260
480 + 180 = (x+125) : 5 + 260
660 = ( x + 125 ) : 5 + 260
660 - 260 = ( x+ 125 ) : 5
400 = ( x + 125 ) : 5
400 x 5 = x + 125
2000 = x + 125
2000 - 125 = x
1875 = x
tương tự
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231321131
1231231
4564646+
3123165
1564156
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1,Giải phương trình:
\(\frac{x+1}{99}\)+\(\frac{x+2}{98}\)+...+\(\frac{x+50}{50}\)+50=0
Ta có: \(\dfrac{x+1}{99}+\dfrac{x+2}{98}+...+\dfrac{x+50}{50}+50=0\)
\(\Leftrightarrow\dfrac{x+1}{99}+1+\dfrac{x+2}{98}+1+...+\dfrac{x+50}{50}+1=0\)
\(\Leftrightarrow\dfrac{x+100}{99}+\dfrac{x+100}{98}+...+\dfrac{x+100}{50}=0\)
\(\Leftrightarrow\left(x+100\right)\left(\dfrac{1}{99}+\dfrac{1}{98}+...+\dfrac{1}{50}\right)=0\)
mà \(\dfrac{1}{99}+\dfrac{1}{98}+...+\dfrac{1}{50}>0\)
nên x+100=0
hay x=-100
Vậy: S={-100}
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\(\dfrac{x+1}{99}+\dfrac{x+2}{98}+...+\dfrac{x+50}{50}+50=0\)
\(\Leftrightarrow\left(\dfrac{x+1}{99}+1\right)+\left(\dfrac{x+2}{98}+1\right)+\left(\dfrac{x+3}{97}+1\right)+...+\left(\dfrac{x+50}{50}+1\right)=0\)
\(\Leftrightarrow\dfrac{x+100}{99}+\dfrac{x+100}{98}+...+\dfrac{x+100}{50}=0\)
\(\Leftrightarrow\left(x+100\right).\left(\dfrac{1}{99}+\dfrac{1}{98}+\dfrac{1}{97}+...+\dfrac{1}{50}\right)=0\)
\(\Leftrightarrow x+100=0\) (vì \(\dfrac{1}{99}+\dfrac{1}{98}+\dfrac{1}{97}+...+\dfrac{1}{50}>0\) )
\(\Leftrightarrow x=-100\)
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( 0+0+0+0+1+1+1+1+2+2+2+2+...+10+10+10+10 )x(1+1+1+2+2+2+3+3+3+...+50+50+50 )
nhanh nha
olm duyệt
Tìm x:
a,456+( x - 357 ) = 1362
b, ( 2345 - x ) -183 = 2014
c, ( x - 2005 ) . 2006 = 0 ( dấu . là dấu nhân )
480 + 45 .4 = ( x + 125 ) : 5 +260
2005.( x - 2006 ) = 2005
[ ( x + 50) . 50 -50 ] : 50 = 50
456 + (x - 357) = 1362
=> x - 357 = 1362 - 456
=> x - 357 = 906
=> x = 906 + 357
=> x = 1263
c) (x - 2005) . 2006 = 0
=> x - 2005 = 0 : 2006
=> x - 2005 = 0
=> x = 0 + 2005
=> x = 2005
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a) 456 + ( x - 357 ) = 1362
=> x - 357 = 906
=> x = 1263
b) ( 2345 - x ) - 183 = 2014
=> 2345 - x = 2197
=> x = 148
c) ( x - 2005 ) . 2006 = 0
=> x - 2005 = 0
=> x = 2005
còn lại làm tương tự
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Tìm x, biết:
a) 456 + (x - 357) = 1362
b) (2345 - x) - 183 = 2014
c) (x - 2005) x 2006 = 0
d) 480 + 45 x 4 = (x + 125) : 5 +260
e) 2005 x (x - 2006) = 2005
g)[(x + 50) x 50 - 50] : 50 = 50
(x - 2005) x 2006 = 0
<=> x - 2005 = 0
<=> x = 2005
Vậy x = 2005
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\(456+\left(x-357\right)=1362\) \(\left(2345-x\right)-183=2014\)
\(x-357=906\) \(2345-x=2197\)
\(x=1263\) \(x=148\)
\(\left(x-2005\right).2006=0\) Phần sau tương tự thế !
\(x-2005=0\)
\(x=2005\)
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\(a,456+\left(x-357\right)=1362\)
\(x-357=1362-456\)
\(x-357=906\)
\(x=1263\)
\(b,\left(2345-x\right)-183=2014\)
\(2345-x=2197\)
\(x=148\)
\(c,\left(x-2005\right)\times2006=0\)
\(x-2005=0\)
\(x=2005\)
\(d,480+45\times4=\left(x+125\right):5+260\)
\(480+180=\left(x+125\right):5+260\)
\(660=\left(x+125\right):5+260\)
\(400=\left(x+125\right):5\)
\(x+125=2000\)
\(x=1875\)
\(e,2005\times\left(x-2006\right)=2005\)
\(x-2006=1\)
\(x=2007\)
\(g,[\left(x+50\right)\times50-50]:50=50\)
\(\left(x+50\right)\times50-50=2500\)
\(\left(x+50\right)\times50=2550\)
\(x+50=51\)
\(x=1\)
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Xem thêm câu trả lời
Giải các phương trình sau:
9) x-49/ 50 + x-50/ 49 = 49/ x-50 + 50/ x-49
8) 99-x/101 + 97-x/103 + 95-x/105 + 93-x/107 = 4
10) x+14/86 + x+15/85 + x+16/84 + x+17/83 + x+116/4 = 0
10) \(\frac{x+14}{86}+\frac{x+15}{85}+\frac{x+16}{84}+\frac{x+17}{83}+\frac{x+116}{4}=0\)
\(\Leftrightarrow\)\(\frac{x+14}{86}+1+\frac{x+15}{85}+1+\frac{x+16}{84}+1+\frac{x+17}{83}+1+\frac{x+116}{4}-4=0\)
\(\Leftrightarrow\)\(\frac{x+100}{86}+\frac{x+100}{85}+\frac{x+100}{84}+\frac{x+100}{83}+\frac{x+100}{4}=0\)
\(\Leftrightarrow\)\(\left(x+100\right)\left(\frac{1}{86}+\frac{1}{85}+\frac{1}{84}+\frac{1}{83}+\frac{1}{4}\right)=0\)
\(\Leftrightarrow\)\(x+100=0\) (vì 1/86 + 1/85 + 1/84 + 1/83 + 1/4 \(\ne\)0)
\(\Leftrightarrow\)\(x=-100\)
Vậy....
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