x + 1 = 1
NH
Những câu hỏi liên quan
LARGE 7)Gfrac{sqrt{x}+1}{x-1}+frac{sqrt{x}-1}{sqrt{x}+1}-frac{2sqrt{x}+2}{x-1}Gfrac{sqrt{x}+1}{sqrt{x}-1}+frac{sqrt{x}-1}{sqrt{x}+1}-frac{2(sqrt{x}+1)}{(sqrt{x}-1)(sqrt{x}+1)}Gfrac{sqrt{x}+1}{x-1}+frac{sqrt{x}-1}{sqrt{x}+1}-frac{2}{sqrt{x}-1}Gfrac{(sqrt{x}+1)^2+(sqrt{x}-1)^2-2(sqrt{x}+1)}{(sqrt{x}-1)(sqrt{x}+1)}Gfrac{2x-2sqrt{x}}{(sqrt{x}-1)(sqrt{x}+1)}Gfrac{2sqrt{x}(sqrt{x}-1)}{(sqrt{x}-1)(sqrt{x}+1)}Gfrac{2sqrt{x}}{sqrt{x}+1}8)H(frac{1}{sqrt{x}-1}+frac{sqrt{x}}{x-1}):(frac{sqrt{x}}{sqrt{x}-1}-...
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\[\LARGE 7)G=\frac{\sqrt{x}+1}{x-1}+\frac{\sqrt{x}-1}{\sqrt{x}+1}-\frac{2\sqrt{x}+2}{x-1}\\G=\frac{\sqrt{x}+1}{\sqrt{x}-1}+\frac{\sqrt{x}-1}{\sqrt{x}+1}-\frac{2(\sqrt{x}+1)}{(\sqrt{x}-1)(\sqrt{x}+1)}\\G=\frac{\sqrt{x}+1}{x-1}+\frac{\sqrt{x}-1}{\sqrt{x}+1}-\frac{2}{\sqrt{x}-1}\\G=\frac{(\sqrt{x}+1)^2+(\sqrt{x}-1)^2-2(\sqrt{x}+1)}{(\sqrt{x}-1)(\sqrt{x}+1)}\\G=\frac{2x-2\sqrt{x}}{(\sqrt{x}-1)(\sqrt{x}+1)}\\G=\frac{2\sqrt{x}(\sqrt{x}-1)}{(\sqrt{x}-1)(\sqrt{x}+1)}\\G=\frac{2\sqrt{x}}{\sqrt{x}+1}\\8)H=(\frac{1}{\sqrt{x}-1}+\frac{\sqrt{x}}{x-1}):(\frac{\sqrt{x}}{\sqrt{x}-1}-1)\\H=(\frac{1}{\sqrt{x}-1}+\frac{\sqrt{x}}{(\sqrt{x}-1)(\sqrt{x}+1)}):(\frac{\sqrt{x}-(\sqrt{x}-1)}{\sqrt{x}-1})\\H=\frac{\sqrt{x}+1+\sqrt{x}}{(\sqrt{x}-1)(\sqrt{x}+1)}:\frac{\sqrt{x}-\sqrt{x}+1}{\sqrt{x}-1}\\H=\frac{2\sqrt{x}+1}{(\sqrt{x}-1)(\sqrt{x}+1)}:\frac{1}{\sqrt{x}-1}\\H=\frac{2\sqrt{x}+1}{(\sqrt{x}-1)(\sqrt{x}+1)}.(\sqrt{x}-1)\\H=\frac{2\sqrt{x}}{\sqrt{x}+1}\]
1 x 1 x 1 x 1 x 1 x 1 x 1 x 1 x 1 x 1 x 1 =
1 nhé bạn
1
(số nào nhân với 1 bằng chính nó)
= 1
#Học tốt!!!
Xem thêm câu trả lời
giải phương trình |x+1|+|x-1|=1+|x^2-1|giải phương trình |x+1|+|x-1|=1+|x^2-1|giải phương trình |x+1|+|x-1|=1+|x^2-1|giải phương trình |x+1|+|x-1|=1+|x^2-1|giải phương trình |x+1|+|x-1|=1+|x^2-1|
ta có :
\(\left|x+1\right|+\left|x-1\right|=1+\left|\left(x-1\right)\left(x+1\right)\right|\)
\(\Leftrightarrow\left|x-1\right|\left|x+1\right|-\left|x-1\right|-\left|x+1\right|+1=0\)
\(\Leftrightarrow\left(\left|x-1\right|-1\right)\left(\left|x+1\right|-1\right)=0\Leftrightarrow\orbr{\begin{cases}\left|x-1\right|=1\\\left|x+1\right|=1\end{cases}}\)
\(\Leftrightarrow x\in\left\{-2,0,2\right\}\)
1 x 1 x 1 x 1 x 1 x 1 x 1 x 1 x 1 x 1 x 5 = ?
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1 .Hãy rút gọn đa thức sau:
M=1−[(1√x−1−√x−1):(1√x+1−1√x−1):√x+1.√x2−1(x−1)√x+1−(x+1).√
P = 1 1/3 x 1 1/8 x 1 1/15 x 1 1/24 x 1 1/35 x 1 1/48 x 1 1/63 x 1 1/80 x 1 1/99
Thực hiện phép trừ :
dfrac{2x}{x-1}-dfrac{x}{x-1}-dfrac{1}{x-1}
Cách thực hiện nào sau đây sai ?
(A) dfrac{2x}{x-1}-dfrac{x}{x-1}-dfrac{1}{x-1}left(dfrac{2x}{x-1}-dfrac{x}{x-1}right)-dfrac{1}{x-1}......................
(B) dfrac{2x}{x-1}-dfrac{x}{x-1}-dfrac{1}{x-1}dfrac{2x}{x-1}-left(dfrac{x}{x-1}-dfrac{1}{x-1}..............right)
(C) dfrac{2x}{x-1}-dfrac{x}{x-1}-dfrac{1}{x-1}dfrac{2x}{x-1}-left(dfrac{x}{x-1}+dfrac{1}{x-1}right)........
(D) dfrac{2x}{x-1}-dfrac{x}{x-1}-df...
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Thực hiện phép trừ :
\(\dfrac{2x}{x-1}-\dfrac{x}{x-1}-\dfrac{1}{x-1}\)
Cách thực hiện nào sau đây sai ?
(A) \(\dfrac{2x}{x-1}-\dfrac{x}{x-1}-\dfrac{1}{x-1}=\left(\dfrac{2x}{x-1}-\dfrac{x}{x-1}\right)-\dfrac{1}{x-1}=......................\)
(B) \(\dfrac{2x}{x-1}-\dfrac{x}{x-1}-\dfrac{1}{x-1}=\dfrac{2x}{x-1}-\left(\dfrac{x}{x-1}-\dfrac{1}{x-1}=..............\right)\)
(C) \(\dfrac{2x}{x-1}-\dfrac{x}{x-1}-\dfrac{1}{x-1}=\dfrac{2x}{x-1}-\left(\dfrac{x}{x-1}+\dfrac{1}{x-1}\right)=........\)
(D) \(\dfrac{2x}{x-1}-\dfrac{x}{x-1}-\dfrac{1}{x-1}=\dfrac{2x}{x-1}+\dfrac{-x}{x-1}+\dfrac{-1}{x-1}=.........\)
tính giá trị của biểu thức
A =( 1+1/15)x( 1+1/24)x(1+1/35)x ......x (1+1/9999)
B =(1+1/2)x(1=1/3)x(1+1/4)x.......x(1+1/2017)
C =(1-1/97)x(1-1/98)x(1-1/99)x.....x(1-1/1000)
tính giá trị biểu thức
A=(1+1/15)x(1+1/24)x(1+1/35)x.......x(1+1/9999)
B=(1+1/2)x(1+1/3)x(1+1/4)x...x(1+1/2017)
C=(1-1/97)x(1-1/98)x(1-1/99)x.......x(1-1/1000)
B=3/2x4/3x...........x2018/2017
=3x4x5x...........x2018/2x3x2x2x............x2017
=2x2018
=4036
A,C tương tự
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