21^5.9^4/6^3.8^3
Tìm x, biết:
a) (x- 5.9).2 = 0;
b) 21. (32 - x) = 21;
c) 25.(2.x - 4).12 = 0;
d) (x- 4) : 6 - 5 = 10.
Đáp số:
a) x=45
b) x=31
c) x=2
d) x=94
Tính:
\(\frac{5.2^{30}.6^2.3^{15}-2^3.8^9.3^{17}.21}{21.2^{29}.3^{16}.4-2^{29}.\left(3^4\right)^5}\)
\(\frac{5.2^{30}.6^2.3^{15}-2^3.8^9.3^{17}.21}{21.2^{29}.3^{16}.4-2^{29}.\left(3^4\right)^5}\)
\(=\frac{5.2^{30}.6^2.3^{15}-2^3.8^9.3^{15}.3^2.21}{21.2^{29}.3^{16}.4-2^{29}.\left(3^4\right)^5}\)
\(=\frac{3^{15}.\left(5.2^{30}.6^2-2^3.8^9.3^2.21\right)}{21.2^{29}.3^{16}.4-2^{29}.3^{20}}\)
Tiếp theo thì tự làm đc rồi chứ gì
Cho E=2^15.0,5^5+3.2^10/2^11.2^3-2^15:2^3 Cho F=2.6^7+6^8/2^5.9^4-2.3^7+3^8 Cho G=4^5.9^4-2.6^9/2^10.3^8+6^8.20
Tính:
a) \(\dfrac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}\)
b) T=\(\dfrac{5^{16}.27^7}{125^5.9^{11}}\)
a: \(=\dfrac{2^{10}\cdot3^8-2^{10}\cdot3^9}{2^{10}\cdot3^8+2^{10}\cdot3^8\cdot5}=\dfrac{2^{10}\cdot3^8\left(1-3\right)}{2^{10}\cdot3^8\left(1+5\right)}=\dfrac{-2}{6}=\dfrac{-1}{3}\)
b: \(=\dfrac{5^{16}\cdot3^{21}}{5^{15}\cdot3^{22}}=\dfrac{5}{3}\)
(6^3.8^4):12^3
(6^3.8^4):12^3
=> ( 216 . 4096 ) : 1728
=> 884736 : 1728 = 512
\(\left(6^3\times8^4\right)\div12^3\)
\(=\left(216\times4096\right)\div1728\)
\(=884736\div1728\)
\(=512\)
(63×84)÷123
=(216×4096)÷1728
=884736÷1728
=512
(6^3.8^4):12^3
\(\dfrac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}\)
\(\dfrac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}=\dfrac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+2^{10}.3^8.5}=\dfrac{2^{10}.3^8\left(1-3\right)}{2^{10}.3^8\left(1-5\right)}=\dfrac{-2}{-4}=\dfrac{1}{2}\)
Tính: A=\(\dfrac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}\)
\(A=\dfrac{4^5\cdot9^4-2\cdot6^9}{2^{10}\cdot3^8+6^8\cdot20}\)
\(=\dfrac{2^{10}\cdot3^8-2^{10}\cdot3^9}{2^{10}\cdot3^8+3^8\cdot2^{10}\cdot5}\)
\(=\dfrac{2^{10}\cdot3^8\left(1-3\right)}{2^{10}\cdot3^8\cdot\left(1+5\right)}\)
\(=-\dfrac{2}{6}=-\dfrac{1}{3}\)
1.Rut gọn
a)2^15.9^4/6^3.8^3
b)2^7.9^3/6^5/6^5.8^2
\(\frac{6^8.2^4-4^5.18^4}{27^3.8^4-3^9.2^{13}}\)
\(\frac{6^8.2^4-4^5.18^4}{27^3.8^4-3^9.2^{13}}\\ =\frac{2^8.3^8.2^4-2^{2.5}.3^{2.4}.2^4}{3^{3.3}.2^{3.4}-3^9.2^{13}}\\ =\frac{2^{12}.3^8-2^{14}.3^8}{3^9.2^{12}-3^9.2^{13}}\\ =\frac{2^{12}.3^8\left(1-2^2\right)}{3^9.2^{12}.\left(1-2\right)}\\ =\frac{3^8.\left(-3\right)}{3.\left(-1\right)}=3^8\)