\(225:15+3\left(2x-1\right)=270\)

\(\Leftrightarrow2x-1=85\)

hay x=43

\(3\left(2x+1\right)=270\)

\(\Leftrightarrow2x+1=90\)

hay \(x=\dfrac{89}{2}\)

Lời giải:

a. 

$=5^{6-3}+2^{3-2}=5^3+2^1=125+2=127$
b.

$=3333:3+225:15=1111+15=1126$

c.

$=15.2^3+4.3^2-5.7=15.8+4.9-35=120+36-35=120+1=121$

d.

$=5.4^2-18:3^2=5.16-18:9=80-2=78$

e.

$=6^2:4.3+2.5^3=36:4.3+2.125$

$=9.3+250=27+250=277$

f.

$=80-(4.25-3.8)=80-(100-24)=80-100+24=-20+24=4$

333:3+225:15^2

=111+225:225

=111+1

=112

333:3+225:15²

=111+225:225

=111+1

=112

\(333:3+225:15^2\)

\(=111+225:15\cdot15\)

\(=111+225:225\)

\(=111+1\)

\(=112\)

a) <

b) <

c) >

d) <

      a <

            b <

                           c >

                   d <

dsố: =0

\(\left(225-5^2\right)\left(225-6^2\right).....\left(225-15^2\right)\)

\(=\left(225-5^2\right)\left(225-6^2\right).....\left(15+15\right)\left(15-15\right)\)

\(=\left(225-5^2\right)\left(225-6^2\right).....\left(15+15\right).0=0\)

Vậy.................

Chúc bạn học tốt!!!