125*67+67*75
435 - 167 - 89 - 435 - 89
(-67) +125 + (-33) + 75
435 − 167 − 89 − 435 − 89
=(435 − 435) − (167 + 89 + 89)
= −(256 + 89)
= -345
----------------------------------
(-67) + 125 + (-33) + 75
= [(-67) + (-33)] + (125 + 75)
= -100 + 200
= 100
Thực hiên phép tính sau
95-(129-74):5+2022^0
(-67)+125+(-33)+75
86.(-108)+86.9-86
95 - (129 - 74) : 5 + 2022⁰
= 95 - 55 : 5 + 1
= 95 - 11 + 1
= 95 - 10
= 85
-------
(-67) + 125 + (-33) + 75
= (125 + 75) - (67 + 33)
= 200 - 100
= 100
--------
86.(-108) + 86.9 - 86
= 86.(-108 + 9 - 1)
= 86.(-100)
= 8600
3. Tính giá trị của biểu thức bằng cách thuận tiện .
a.) 476 + 70 + 30 = ..............
= ..............
b.) 67 + 125 + 75 = ...............
= ................
a) 476 + 70 + 30
= 476 + (70 + 30)
= 476 + 100
= 576
b) 67 + 125 + 75
= 67 + (125 + 75)
= 67 + 200
= 267
a) 476+70+30 = 476+(70+30)
= 476+100
= 576
b) 67+125+75 = 67+ (125+75)
= 67+ 200
= 267
tính nhanh
b) [(24+-67)]-[-67-(-24)]
c) 2^3.17-2^3.14
d) 26.(-125)-125.(-36)
e) 48-6(12+9)
f) (-67).(1-301)-301.67
b. 0
c. 112
d. 1250
e. -78
f. -67
b) [(24+-67)]-[-67-(-24)]=0
c) 2^3.17-2^3.14=112
d) 26.(-125)-125.(-36)=1250
e) 48-6(12+9)=-78
f) (-67).(1-301)-301.67=-67
(-67)+125+(-33)+75
86.(-108)+86.9-86
23.(-16)-23.84+300
235-5[(5^3-3^3):14]
95-(129-74):5+2022^0
\(\left(-67\right)+125+\left(-33\right)+75\)
\(=\left[\left(-67\right)+\left(-33\right)\right]+\left(125+75\right)\)
\(=100+200=300\)
_______
\(86.\left(-108\right)+86.9-86\)
\(=86.\left[\left(-108\right)+9-1\right]\)
\(=86.\left(-100\right)=-8600\)
_______
\(23.\left(-16\right)-23.84+300\)
\(=23.\left[\left(-16\right)-84\right]+300\)
\(=23.\left(-100\right)+300\)
\(=-2300+300\)
\(=-2000\)
______
\(235-5\left[\left(5^3-3^3\right):14\right]\)
\(=235-5\left[\left(125-27\right):14\right]\)
\(=235-5\left[98:14\right]\)
\(=235-5.7\)
\(=235-35\)
\(=200\)
_______
\(95-\left(129-74\right):5+2022^0\)
\(=95-55:5+1\)
\(=95-11+1\)
\(=84+1=85\)
\(#NqHahh\)
b) (-135) + 10
= - (….. – 10)
= - 125
e) (-67) + (+67) = ……
tính nhanh:
a)(-119). (-125). 4. (-8). (-25)
b)(-67). (-1)mũ 200. (-8). 125. (-1)mũ 2n+1
c)-67. 52- 48. 67
d)42.(-119)+ 119. (-58)
a) (-119).(-125).4.(-8).(-25) = [(-125).(-8)].[(-25).(-4)].(-119) = 1000.100.(-119) = 100000.(-119) = -11900000
b) (-67).(-1)^200.(-8).125.(-1)^2n+1 = -67.1.[(-8).125].(-1) = -67.(-1000).(-1) = 67000 . (-1) = -67000
c) -67.52-48.67 = 67.(-52)-48.67 = 67. (-52-48) = 67.(-100) = -6700
d)42.(-119)+119.(-58) = -42.119+119.(-58)=119.[-42+(-58)] = 119.(-100)=-11900
1. Tính hợp lí nếu có thể :
a) 125 + 80 + 375 + 220
b) 25.11.8.4.125
c) 18.74 + 18.27 - 18
d) 75 . 23 + 75 . 77 - 500
e) 150 : [25.(18-42)]
f) 125 . 23 . 2 . 8 . 50
g) 235 + 88 + 165 + 12
h) 71 . 32 + 71 . 68 - 1100
i) 67 : 66 + 43 .2 - 240
j) 546 - 6. [158 : (30 + 72)]
k) 268 + 147 + 132 + 253
2. Tìm số tự nhiên x, biết :
a) 7 . x = 707
b) 6x + 5 = 47
c) 35 : (x+1) = 7
d) 12 + (29 - 3x) = 35
e) 2.4x + 101 = 138
f) 7 . x = 140
g) 7 . (15 - x) + 14 = 84
h) 3x . 5 - 15 = 390
3. Tìm số tự nhiên n , biết :
(n+11) chia hết cho (n+1)
1.
a) \(125+80+375+220\)
\(=\left(125+375\right)+\left(80+220\right)\)
\(=500+300\)
\(=800\)
b) \(25.11.8.4.125\)
\(=\left(25.4\right).\left(8.125\right).11\)
\(=100.1000.11\)
\(=1100000\)
c) \(18.74+18.27-18\)
\(=18.\left(74+27-1\right)\)
\(=18.100\)
\(=1800\)
d) \(75.23+75.77-500\)
\(=75.\left(23+77\right)-500\)
\(=75.100-500\)
\(=7500-500\)
\(=7000\)
e) \(150:\left[25.\left(18-4^2\right)\right]\)
\(=150:\left[25.\left(18-16\right)\right]\)
\(=150:\left[25.2\right]\)
\(=150:50\)
\(=3\)
f) \(125.23.2.8.50\)
\(=\left(125.8\right).\left(2.50\right).23\)
\(=1000.100.23\)
\(=2300000\)
g) \(235+88+165+12\)
\(=\left(235+165\right)+\left(88+12\right)\)
\(=400+100\)
\(=500\)
h) \(71.32+71.68-1100\)
\(=71.\left(32+68\right)-1100\)
\(=71.100-1100\)
\(=7100-1100\)
\(=6000\)
i) \(6^7:6^6+4^3.2-24^0\)
\(=6+64.2-1\)
\(=6+128-1\)
\(=133\)
j) \(546-6.\left[158:\left(30+7^2\right)\right]\)
\(=546-6.\left[158:\left(30+49\right)\right]\)
\(=546-6.\left[158:79\right]\)
\(=546-6.2\)
\(=546-12\)
\(=534\)
k) \(268+147+132+253\)
\(=\left(268+132\right)+\left(147+253\right)\)
\(=400+400\)
\(=800\)
2.
a) \(7x=707\)
\(x=707:7\)
\(x=101\)
b) \(6x+5=47\)
\(6x=47-5\)
\(6x=42\)
\(x=42:6\)
\(x=7\)
c) \(35:\left(x+1\right)=7\)
\(x+1=35:7\)
\(x+1=5\)
\(x=5-1\)
\(x=4\)
d) \(12+\left(29-3x\right)=35\)
\(29-3x=35-12\)
\(29-3x=23\)
\(3x=29-23\)
\(3x=6\)
\(x=6:3\)
\(x=2\)
e) \(2.4^x+10^1=138\)
\(2.4^x=138-10\)
\(2.4^x=128\)
\(4^x=128:2\)
\(4^x=64=4^3\)
\(\Rightarrow x=3\)
f) \(7x=140\)
\(x=140:7\)
\(x=20\)
g) \(7\left(15-x\right)+14=84\)
\(7\left(15-x\right)=84-14\)
\(7\left(15-x\right)=70\)
\(15-x=70:7\)
\(15-x=10\)
\(x=15-10\)
\(x=5\)
h) \(3^x.5-15=390\)
\(3^x.5=390+15\)
\(3^x.5=405\)
\(3^x=405:5\)
\(3^x=81=3^4\)
\(\Rightarrow x=4\)
3.
Ta có:
\(\Rightarrow n+11⋮n+1\)
\(\Rightarrow n+1+10⋮n+1\)
\(\Rightarrow10⋮n+1\) hay \(n+1\inƯ\left(10\right)=\left\{-10;-5;-2;-1;1;2;5;10\right\}\)
\(\Rightarrow\) \(n\in\left\{-11;-6;-3;-2;0;1;4;9\right\}\)
Vì \(n\in N\) nên \(n\in\left\{0;1;4;9\right\}\)
(-57).(67-34)-67.(34-57)
(-4).(+125).(-25).(-6).(-8)