1. = 2(a+b)

2. =2(a-b)

3.=2(a+2b-3c)

4.=3(a-2b-3c)

5.=-4(a+2b+3c)

6.=-5(x+2xy+3y)

7.=-7(a+2ab+3b)

8.=6(xy-2x-3y)

9.=8(xy-3y+2x)

10.=9(ab-2a+1)

Lần sau bn cần ghi đề rõ ràng hơn

11.=x(y-1)

12.=a(x+1)

13.=m(x+y+1)

14.=-a(x+y+1)

15.=-a(x²+x+1)

16.=-2a(x+2y)

17.=2a(x-y+1)

18.=2(2ax-ay-2)

19.=5a(1-2x-3)

20.=-2ab(a+2b+3)

a) =2(a+b)

b) =2(a-2b)

c) =2(a+2b-3c)

d) =3(a-2b+3c)

e)= -4(a+2b+3c)

f) =-5(x+2xy+3y)

g) =-7(a+2ab+3b)

h) = 6(xy-2x-3y)

k) = 8(xy-3y+2x)

n)=9(ab-2a+1)

1, 2a+2b = 2( a + b )

2, 2a-2b = 2( a - b )

3, 2a+4b-6c = 2( a + 2b - 3c )

4, 3a-6b-9c = 3( a - 2b - 3c )

5, xy-x = x( y - 1 )

6, -5x-10xy-15y = -5( x + 2xy + 3y )

7, -7a-14ab-21b = -7( a + 2ab + 3b )

8, 6xy-12x-18y = 6 ( xy - 2x - 3y )

9, 8xy-24y+16x = 8 ( xy - 3y + 2x )

10, 9ab-18a+9 = 9( ab - 2a + 1 )

11, ax+a = a( x + 1 )

12, mx+my+m = m( x + y + 1 )

13, -ax-ay-a = -a( x + y +1 )

14, -2ax-4ay = -2a( x + 2y )

15, 2ax-2ay+2a = 2a( x - y + 1 )

16, 4ax-2ay-2 = 2( 2ax - a - 1 )

17, 5a-10ax-15a = 5a( 1 - 2x - 3 ) = 5a( -2x - 2 )

18, 5ax-15ay+20a = 5a( x - 3y + 4 )

19, 3a²x-6a²y+12a = 3a( ax - 2ay + 4 )

20, 2axy-4a²xy²+6a³x\(^2\) = 2ax( y - 2ay\(^2\) + 3a\(^2\)x )

\(5x-5y+ax-ay=5\left(x-y\right)+a\left(x-y\right)=\left(5+a\right)\left(x-y\right)\)

\(a^3-a^2x-ay+xy=a^2\left(a-x\right)-y\left(a-x\right)=\left(a^2-y\right)\left(a-x\right)\)

\(10x^2+10xy+5x+5y=10x\left(x+y\right)+5\left(x+y\right)=5\left(2x+1\right)\left(x+y\right)\) \(5ay-3bx+ax-15by=a\left(5y+x\right)-3b\left(5y+x\right)=\left(a-3b\right)\left(5y+x\right)\) \(x^3+x^2-x-1=x^2\left(x+1\right)-\left(x+1\right)=\left(x^2-1\right)\left(x+1\right)=\left(x+1\right)^2\left(x-1\right)\) \(2bx-3ay-6by+ax=x\left(2b+a\right)-3y\left(2b+a\right)=\left(x-3y\right)\left(2b+a\right)\)

\(x+2a\left(x-y\right)-y=\left(x-y\right)+2a\left(x-y\right)=\left(1+2a\right)\left(x-y\right)\)

Lm giúp tôi với :((

Bài làm

a) 2a²x³ - ax³ - a⁴ - x³a² - ax³ - 2x⁴

= 2a²x³ - ax³ - a⁴ - a²x³ - ax³ - 2x⁴

= ( 2a²x³ - a²x³ ) - ( ax³ + ax³ ) - a⁴ - 2ax⁴

= a²x³ - 2ax³ - a⁴ - 2ax⁴

b) 3xx⁴ + 4xx³ - 5x²x³ - 5x²x²

= 3x⁵ + 4x⁴ - 5x⁵ - 5x⁴

= ( 3x⁵ - 5x⁵ ) + ( 4x⁴ - 5x⁴ )

= -2x⁵ - x⁴

c) 3a - 4b² - 0,8b . 4b² - 2ab . 3b + b . 3b² - 1

= 3a - 4b² - 3,2b³ - 6ab² + 3b³ - 1

= 3a - 4b² - 0,2b³ - 6ab² - 1

d) 5x.2y² - 5x.3xy - x²y + 6xy² 

= 10xy² - 15x²y - x²y + 6xy²

= ( 10xy² + 6xy² ) - ( 15x²y + x²y )

= 16xy² - 16x²y

a)\(2a^2\)\(x^3\)-\(ax^3\)-\(a^4\)-\(x^3a^2\)-\(ax^3\)-\(2x^4\)
=(\(2a^2x^3-x^3a^2)\)+\((-ax^3-ax^3)\)-\(ax^4-2x^4\)
=\(a^2x^3-2ax^3-ax^4-2x^4\)
b)\(3xx^4+4xx^3-5x^2x^3-5x^2x^2 \)
=\(3x^5+4x^4-5x^5-5x^4\)
=\((3x^5-5x^5)+(4x^4-5x^4)\)
=\(-2x^5-x^4\)
d)\(5x.2y^2-5x.3xy-x^2y+6xy^2\)
=\((5.2)xy^2+(-5.3)xxy-x^2y+6xy^2\)
=\(10xy^2-15x^2y-x^2y+6xy^2\)
=\((10xy^2+6xy^2)+(-15x^2y-x^2y)\)
=\(16xy^2-16x^2y\)
câu c) mik ko biết làm

1: \(\dfrac{f\left(x\right)}{x-3}=\dfrac{2x^2-6x+\left(a+6\right)x-3a-18+3a+19}{x-3}\)

=2x^2+(a+6)+3a+19/x-3

Để f(x)/x-3 dư 4 thì 3a+19=4

=>3a=-15

=>a=-5

2: \(\dfrac{f\left(x\right)}{x-5}=\dfrac{3x^2-15x+\left(a+15\right)x-5a-75+5a+102}{x-5}\)

\(=3x+a+15+\dfrac{5a+102}{x-5}\)

Để dư là 27 thì 5a+102=27

=>5a=-75

=>a=-15

a Đề sai: )

b

\(a^3-a^2x-ay+xy\\ =a^2\left(a-x\right)-y\left(a-x\right)\\ =\left(a-x\right)\left(a^2-y\right)\)

c

\(4x^2-y^2+4x+1\\ =\left(2x\right)^2+2.2x.1+1-y^2\\ =\left(2x+1\right)^2-y^2\\ =\left(2x+1-y\right)\left(2x+1+y\right)\)

d

\(x^4+2x^3+x^2\\ =x^4+x^3+x^3+x^2\\ =x^3\left(x+1\right)+x^2\left(x+1\right)\\ =\left(x^3+x^2\right)\left(x+1\right)\)

e

\(5x^2-10xy+5y^2-5z^2\\ =5\left(x^2-2xy+y^2-z^2\right)\\ =5\left[\left(x-y\right)^2-z^2\right]\\ =5\left(x-y-z\right)\left(x-y+z\right)\)

c: =(2x+1)^2-y^2

=(2x+1+y)(2x+1-y)

d: =x^2(x^2+2x+1)

=x^2(x+1)^2

e: =5(x^2-2xy+y^2-z^2)

=5[(x-y)^2-z^2]

=5(x-y-z)(x-y+z)