d) Ta có: \(32\%-0.25:x=-\dfrac{17}{5}\)

\(\Leftrightarrow0.25:x=\dfrac{8}{25}+\dfrac{17}{5}=\dfrac{93}{25}\)

hay \(x=\dfrac{25}{372}\)

Vậy: \(x=\dfrac{25}{372}\)

e) Ta có: \(\left(x+\dfrac{1}{5}\right)^2+\dfrac{17}{25}=\dfrac{26}{25}\)

\(\Leftrightarrow\left(x+\dfrac{1}{5}\right)^2=\dfrac{9}{25}\)

\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{5}=\dfrac{3}{5}\\x+\dfrac{1}{5}=-\dfrac{3}{5}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{2}{5}\\x=-\dfrac{4}{5}\end{matrix}\right.\)

Vậy: \(x\in\left\{\dfrac{2}{5};-\dfrac{4}{5}\right\}\)

f) Ta có: \(-\dfrac{32}{27}-\left(3x-\dfrac{7}{9}\right)^3=-\dfrac{24}{27}\)

\(\Leftrightarrow\left(3x-\dfrac{7}{9}\right)^3=\dfrac{-8}{27}\)

\(\Leftrightarrow3x-\dfrac{7}{9}=-\dfrac{2}{3}\)

\(\Leftrightarrow3x=\dfrac{1}{9}\)

hay \(x=\dfrac{1}{27}\)

g) Ta có: \(60\%\cdot x+0.4x+x:3=2\)

\(\Leftrightarrow\dfrac{4}{3}x=2\)

hay \(x=\dfrac{3}{2}\)

Vậy: \(x=\dfrac{3}{2}\)

h) PT \(\Leftrightarrow\left|\dfrac{20}{9}-x\right|=\dfrac{2}{9}\) \(\Rightarrow\left[{}\begin{matrix}\dfrac{20}{9}-x=\dfrac{2}{9}\\x-\dfrac{20}{9}=\dfrac{2}{9}\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=2\\x=\dfrac{22}{9}\end{matrix}\right.\)

  Vậy ...

i) PT \(\Leftrightarrow\dfrac{8}{5}+\dfrac{2}{5}x=\dfrac{16}{5}\) \(\Leftrightarrow\dfrac{2}{5}x=\dfrac{8}{5}\) \(\Leftrightarrow x=4\)

  Vậy ...

a) -15 - 2.(x + 3) = 17

2.(x + 3) = -15 - 17

2.(x + 3) = -32

x + 3 = -32 : 2 

x + 3 = -16

x = -16 - 3

x = -19

b) 2². x - 3 = 32

4.x - 3 = 32

4x = 32 + 3

4x = 35

x = 35 : 4

x = 8,75

3/2+5/4+9/8/+17/16+33/32-6+x-1/x+1=31/32-2/2015

=(1+1/2)+(1+1/4)+(1+1/8)+(1+1/16)+(1+1/32-6+x-1/x+1=31/32-2/2015

=(1/2+1/4+1/8+1/16+1/32)+(1+1+1+1+1)-6+x-1/x+1=31/32-2/2015

=31/32+5-6+x-1/x+1=31/32-2/2015

=5-6+x-1/x+1=31/32-2/2015-31/32

=-1+x-1/x+1=-2/2015

=x-1/x+1=-2/2015- -1

=x-1/x+1=2013/2015

=>x=2014

a) 27 x (-17) + 17 x 127

= 27 x (-17) - 17 x (-127)

= -17 x (27-127)

= -17 x -100 = 1700

b) 2 x (1 +32) - 2 x 32

= 2 x (1 + 32 - 32)

= 2 x 1 = 2

a) => (x+32) - 17 = 42:2 = 21

=> x+32 = 21+17 = 38

=> x=38-32=6

b) => 61+(53-x) = 1785:17=105

=> 53-x = 105-61=44

=> x = 53-44 =9

c) => x^2 +54 -32 = 244:2 = 122

=> x^2 +22 = 122

=> x^2 = 122-2=100

=> x= 10 hoặc -10

giải oy pn **** giùm mk nka

a. X = 6

b. X = 9

c. X = 10

a) x÷0,(7)=0,(32):2,(4)

   \(x:\frac{7}{9}=\frac{32}{99}:\frac{22}{9}\)

\(x:\frac{7}{9}=\frac{16}{121}\)

\(x=\frac{16}{121}.\frac{7}{9}\)

\(x=\frac{112}{1089}\)

b)0,(17):2,(3)=x:0,(3)

\(\frac{17}{99}:\frac{7}{3}=x:\frac{1}{3}\)

\(\frac{17}{231}=x:\frac{1}{3}\)

x=\(\frac{17}{231}.\frac{1}{3}\)

\(x=\frac{17}{693}\)

a) \(\dfrac{-12}{17}< \dfrac{x}{17}< \dfrac{-8}{17}\)

\(\Rightarrow-12< x< -8\)

\(\Rightarrow x\in\left\{-11;-10;-9\right\}\)

b) \(\dfrac{-1}{2}< x< \dfrac{5}{3}\)

\(\Rightarrow\dfrac{-3}{6}< x< \dfrac{10}{6}\)

\(\Rightarrow x\in\left\{\dfrac{-2}{6};\dfrac{-1}{6};0;\dfrac{1}{6};...;\dfrac{7}{6};\dfrac{8}{6};\dfrac{9}{6}\right\}\)

c) \(3,456< x\le7,89\)

\(\Rightarrow x\in\left\{3,456;3,457,3,458;...;7,89\right\}\)

d) \(5,82< \overline{5,8x0}< 8,845\)

\(\Rightarrow x\in\left\{3;4\right\}\)

e) \(32,82< \overline{3x,850}< 35,845\)

\(\Rightarrow x\in\left\{3;4\right\}\)

\(a,3-\left(17-x\right)=-12\\ \Rightarrow17-x=15\\ \Rightarrow x=2\\ b,-26-\left(x-7\right)=0\\ \Rightarrow x-7=-26\\ \Rightarrow x=-19\\ c,25+\left(-2+x\right)=5\\ \Rightarrow-2+x=20\\ \Rightarrow x=18\\ d,30+\left(32-x\right)=10\\ \Rightarrow32-x=-20\\ \Rightarrow x=52\)

a) `3-(17-x)=-12`

`3-17+x=-12`

`x=-12-3+17`

`x=2`

b) `-26-(x-7)=0`

`-26-x+7=0`

`-19-x=0`

`x=-19`

c) `25+(-2+x)=5`

`25-2+x=5`

`x=5-25+2`

`x=-18`

d) `30+(32-x)=10`

`30+32-x=10`

`62-x=10`

`x=52`

Bài 1

a) 76 x 54 + 2 x 27 x 23 + 54 = 76 x 54 + 54 x 23 + 54 = 54 x (76 + 23 + 1) = 54 x 100 = 5400

b) 17 x 82 - 17 x 32 = 17 x (82 - 32) = 17 x 50 = 850

Bài 2

28 - (x + 3) = 14

x + 3 = 28 - 14

x + 3 = 14

x = 14 - 3

x = 11

a) X : \(\frac{7}{9}=\frac{32}{99}:\left(2+\frac{4}{9}\right)\) => X : \(\frac{7}{9}=\frac{32}{99}:\frac{22}{9}\)=> X : \(\frac{7}{9}=\frac{64}{81}\) => X = \(\frac{64}{81}.\frac{7}{9}=\frac{64}{63}\)

b) \(\frac{17}{99}:\left(2+\frac{3}{9}\right)=X:\frac{3}{9}\)=> \(\frac{17}{99}:\frac{7}{3}=X:\frac{1}{3}\)=> \(\frac{17}{231}=X:\frac{1}{3}\)=> X = \(\frac{17}{231}.\frac{1}{3}=\frac{17}{693}\)

Vậy...

a, \(x=\frac{64}{63}\)

b, \(\frac{17}{693}\)
 

a)X:O,(7)=O,(32):2,(4)

X:O,(7)=32/99:0,(4)+2

X:0,(7)=32/99:4/9+2

X:0,(7)=128/891+2

X=1910/891.7/9

X=1,667290186

b)0,(17)/2,(3)=X/0,(3)

=>X=17/9.3/9:7/3

X=17/63