5 + ( x + 27 ) = 64

a) \(\Rightarrow x+27=59\Rightarrow x=32\)

b) \(\Rightarrow x-2=39\Rightarrow x=41\)

c) \(\Rightarrow x+5=-322\Rightarrow x=-327\)

d) \(\Rightarrow5x=35\Rightarrow x=7\)

e) \(\Rightarrow4\left(x-5\right)=56\Rightarrow x-5=14\Rightarrow x=19\)

f) \(\Rightarrow15+x=37\Rightarrow x=22\)

g) \(\Rightarrow7\left(13-x\right)=35\Rightarrow13-x=5\Rightarrow x=8\)

h) \(\Rightarrow10\left(x+1\right)=100\Rightarrow x+1=10\Rightarrow x=9\)

8.(x+25)=181+155

8.(x+25)=336

x+5=336:8

x+5=44

x=44-5

x=39

k minh nha

8.(x+25)-155=181

8.(x+25)=181+155

8.(x+25)=336

x+25=336/8

x+25=42

x=42-25

x=17

a) 5.5^x = 625

=> 5^x+1 = 5⁴

=> x + 1 = 4

=> x = 4 - 1

=> x = 3

Vậy x = 3

b) 8(x + 25) - 155 = 181

=> 8(x + 25) = 181 + 155

=> 8(x + 25) = 336

=> x + 25 = 336 : 8

=> x + 25 = 42

=> x = 42 - 25

=> x = 17

Vậy x = 17

c) (x - 9)⁴ = (x - 9)²

=> (x - 9)⁴ - (x - 9)² = 0

=> (x - 9)².[(x - 9)² - 1] = 0

\(\Rightarrow\left[\begin{array}{nghiempt}\left(x-9\right)^2=0\\\left(x-9\right)^2-1=0\end{array}\right.\)\(\Rightarrow\left[\begin{array}{nghiempt}x-9=0\\\left(x-9\right)^2=1\end{array}\right.\)\(\Rightarrow\left[\begin{array}{nghiempt}x-9=0\\x-9=1\\x-9=-1\end{array}\right.\)\(\Rightarrow\left[\begin{array}{nghiempt}x=9\\x=10\\x=8\end{array}\right.\)

Vậy \(\left[\begin{array}{nghiempt}x=9\\x=10\\x=8\end{array}\right.\)

a)5*5^x=625

\(\Rightarrow5^{x+1}=625\)

\(\Rightarrow5^{x+1}=5^4\)

\(\Rightarrow x+1=4\)

\(\Rightarrow x=3\)

b)8(x+25)-155 =181

\(\Rightarrow8\left(x+25\right)=336\)

\(\Rightarrow x+25=42\)

\(\Rightarrow x=17\)

c) ( x-9)⁴ = ( x-9)²

\(\Rightarrow\left(x-9\right)^4-\left(x-9\right)^2=0\)

\(\Rightarrow\left(x-9\right)^2\left[\left(x-9\right)^2-1\right]=0\)

\(\Rightarrow\left[\begin{array}{nghiempt}\left(x-9\right)^2=0\\\left(x-9\right)^2-1=0\end{array}\right.\)

\(\Rightarrow\left[\begin{array}{nghiempt}x-9=0\\x-9=\pm1\end{array}\right.\)

\(\Rightarrow\left[\begin{array}{nghiempt}x=9\\x=10\\x=8\end{array}\right.\)

\(a,5.5^x=625\Rightarrow5^x=125\Rightarrow5^x=5^3\Rightarrow x=3\)

\(\text{b) 8(x+25)-155 =181}\Rightarrow8\left(x+25\right)=336\Rightarrow x+25=42\Rightarrow x=17\)

cái còn lại tương tự thôi bạn

bài 1

a) 155 - 10.(x+1) = 55

=>10 .(x+1) = 100

=>x + 1 = 10

=>x = 9

còn lại tương tự 

Tính nhanh:

17/5*-31/125*1/2*10/17*-1/2^3

\(x-100=0\)

\(x=100\)

\(\Rightarrow x+55=155\Rightarrow x=100\)

(x+55)=0+155

(x+55)=155

x=155-55

x=100

Bài 1: 

c: =47x100=4700

2: Tìm x

a) Ta có: x+25=40

nên x=40-25=15

Vậy: x=15

b) Ta có: 198-(x+4)=120

\(\Leftrightarrow x+4=198-120=78\)

hay x=78-4=74

Vậy: x=74

c) Ta có: \(\left(2x-7\right)\cdot3=125\)

\(\Leftrightarrow2x-7=\dfrac{125}{3}\)

\(\Leftrightarrow2x=\dfrac{125}{3}+7=\dfrac{125}{3}+\dfrac{21}{3}=\dfrac{146}{3}\)

\(\Leftrightarrow x=\dfrac{146}{3}:2=\dfrac{146}{6}=\dfrac{73}{3}\)

Vậy: \(x=\dfrac{73}{3}\)

d) Ta có: \(x+16⋮x+1\)

\(\Leftrightarrow x+1+15⋮x+1\)

mà \(x+1⋮x+1\)

nên \(15⋮x+1\)

\(\Leftrightarrow x+1\inƯ\left(15\right)\)

\(\Leftrightarrow x+1\in\left\{1;-1;3;-3;5;-5;15;-15\right\}\)

hay \(x\in\left\{0;-2;2;-4;4;-6;14;-16\right\}\)

Vậy: \(x\in\left\{0;-2;2;-4;4;-6;14;-16\right\}\)

\(a,x+25=40\\ \Rightarrow x=40-25\\ \Rightarrow x=15\\ b,198-\left(x+4\right)=120\\ \Rightarrow-\left(x+4\right)=120-198\\ \Rightarrow-\left(x+4\right)=-78\\ \Rightarrow x+4=78\\ \Rightarrow x=78-4\\ \Rightarrow x=74\\ c,\left(2x-7\right).3=125\\ \Rightarrow2x-7=\dfrac{125}{3}\\ \Rightarrow2x=\dfrac{125}{3}+7\\ \Rightarrow2x=\dfrac{146}{3}\\ \Rightarrow x=\dfrac{146}{3}:2\Rightarrow x=\dfrac{73}{3}\\ d,\left(x+16\right)⋮\left(x+1\right)\\ \Rightarrow\left[\left(x+1\right)+15\right]⋮\left(x+1\right)\\ mà:\left(x+1\right)⋮\left(x+1\right)\\ \Rightarrow15⋮\left(x+1\right)\\ \Rightarrow\left(x+1\right)\inƯ\left(15\right)\\ \Rightarrow\left(x+1\right)\in\left\{-15;-1;1;15\right\}\\ \Rightarrow x\in\left\{-16;-2;0;14\right\}\)

Tự kết luận nhé bạn

d,155-10(x+1)=55

          10(x+1) = 155 - 55

          10(x+1) = 100

               x+1  = 100 : 10

               x+1  = 10

                x     = 10 - 1 =9

e,6(x+\(2^3\))+40=100

6(x+\(2^3\))         = 100 - 40

6(x+\(2^3\))         = 60

    (x+\(2^3\))       = 60 : 6

(x+\(2^3\))           = 10

x                       = 10 - \(2^3\)

x                       = 10 - 8 = 2

f,\(2^2\)(x+\(3^2\))-5=55

\(2^2\)(x+\(3^2\))     = 55 + 5

\(2^2\)(x+\(3^2\))     = 60

        (x+\(3^2\))    = 60 : \(2^2\)

          (x+\(3^2\))  = 60 : 4

         (x+\(3^2\))   = 15

         x + 9         = 15

         x               = 15-9=6.

Hok tốt !

d) \(155-10\left(x+1\right)=55\)

\(\Rightarrow10\left(x+1\right)=155-55\)

\(\Rightarrow10\left(x+1\right)=100\)

\(\Rightarrow x+1=100:10\)

\(\Rightarrow x+1=10\)

\(\Rightarrow x=10-1\)

\(\Rightarrow x=9\)

Vậy x = 9

e) \(6\left(x+2^3\right)+40=100\)

\(\Rightarrow6\left(x+2^3\right)=100-40\)

\(\Rightarrow6\left(x+2^3\right)=60\)

\(\Rightarrow x+2^3=60:6\)

\(\Rightarrow x+2^3=10\)

\(\Rightarrow x+8=10\)

\(\Rightarrow x=10-8\)

\(\Rightarrow x=2\)

Vậy x = 2

f) \(2^2\left(x+3^2\right)-5=55\)

\(\Rightarrow2^2\left(x+3^2\right)=55+5\)

\(\Rightarrow2^2\left(x+3^2\right)=60\)

\(\Rightarrow4\left(x+9\right)=60\)

\(\Rightarrow x+9=60:4\)

\(\Rightarrow x+9=15\)

\(\Rightarrow x=15-9\)

\(\Rightarrow x=6\)

Vậy x = 6

\(d,155-10\left(x+1\right)=55\)                                               \(e,6\left(x+2^3\right)+40=100\)

\(\Rightarrow10\left(x+1\right)=155-55\)                                            \(\Rightarrow\left(x+2^3\right)+40=100:6\)

\(\Rightarrow10\left(x+1\right)=100\)                                                         ủa hình như câu này sai đề thì phải ??-.-'''

\(\Rightarrow x+1=100:10\)

\(\Rightarrow x+1=10\)

\(\Rightarrow x=10-1=9\)

9.2+(x+25)=100

18+(x+25)=100

x+25=100-18

x+25=82

x=82-25

x=57

155-10.(x+1)=55

10.(x+1)=155-55

10.(x+1)=100

x+1=100/10

x+1=10

x=10-1

x=9

a)9.2+(x+25)=100

18+x+25=100

43+x=100

=>x=100-43=57

b)155-10(x+1)=55

155-10x+10=55

10x+10=155-55

10x+10=100

10x=100-10=90

x=\(\frac{90}{100}\)=\(\frac{9}{10}\)

18+(x+25)=100

(x+25)=82

x=57