A x 6+126 x 3=450
Tính giá trị của các biểu thức
a) 450 – ( 25 – 10) = ..........................
= ..........................
450 – 25 – 10 = ..........................
= ..........................
b) 180 : 6 : 2 = ..........................
= ..........................
180 : ( 6 : 2 ) = ..........................
= ..........................
c) 410 – (50 +30) = ..........................
= ..........................
410 - 50 + 30 = ..........................
= ..........................
d) 16 x (6 : 3) = ..........................
= ..........................
16 x 6 : 3 = ..........................
= ..........................
a) 450 – ( 25 – 10) = 450 – 15
= 435
450 – 25 – 10 = 425 – 10
= 415
b) 180 : 6 : 2 = 30 : 6
= 15
180 : ( 6 : 2 ) = 180 : 3
= 60
c) 410 – (50 +30) = 410 -80
= 330
410 - 50 + 30 = 360 + 30
= 390
d) 16 x (6 : 3) = 16 x 2
= 32
16 x 6 : 3 = 96 : 3
= 32
Tính nhanh 54*450+18*126*3+848*27
\(54\times450+18\times126\times3+848\times27\)
\(=54\times450+\left(18\times3\right)\times126+\left(27\times2\right)\times424\)
\(=54\times450+54\times126+54\times424\)
\(=54\times\left(450+126+424\right)\)
\(=54\times\left(450+550\right)\)
\(=54\times1000\)
\(=54000\)
2 tìm x,biết;
a)x-1/4=-3/8.2/5
b)x/126=-7/24.-6/11
a) x -1/4 = -3/8 . 2/5
x - 1/4 = -3/20
x = -3/20 + 1/4
x = 1/10
b) x/126 = -7/24 . -6/11
x/126 = 7/44
\(\Rightarrow\)x = rỗng
a, x- 1/4 = (-3/20)
x= 1/10
b, x/126 = (7/44)
x = 441/22
(x-2)+(x-4)+(x-6)+...+(x-100)=450
(3*x-12)*(1+2+3+5+7+..+2019)=99*100-3*3300
426 : a+34: x=5
360:x-126:x=6
426 :2 + 34:x = 5
213 + 34:x =5
34:x= -208
x= -17/104
360 : x-126:x = 6
(360- 126) :x = 6
234 :x =6
x= 39
(Bạn xem lại câu a nhé, lớp 4 chưa học số âm)
426 : 2+34: x=5
213 + 34 : x = 5
247 : x = 5
x = 247 : 5
x = 49.4
360:x-126:x=6
( 360 - 126 ) : x = 6
234 : x = 6
x = 234 : 6
x = 39
a) 426:2+34:x=5
=> 213 -5=34:x
=> x=34: 208
=> x= \(\frac{17}{104}\)
b) 360:x-126:x=6
=> (360-126):x=6
=> x= 234:6
=> x= 39
1) thực hiện phép tính
-126+67+[32-(-126)]-64
240-[(82-49):3+135]:18
A+1+2+22+23+...+22021
-205+37-(-200)
2) Tìm x∈z biết
x-45=48-68
35+5(6-x)=-12-(-112)
517-(x-124)=-483
46-(3x-2)3=(-38)+20
Bài 2:
a: =>x-45=-20
hay x=25
b: =>35+30-5x=-12+112
=>65-5x=100
=>5x=-35
hay x=-7
c: =>x-124=1000
hay x=1124
d: \(\Leftrightarrow46-\left(3x-2\right)^3=-18\)
\(\Leftrightarrow\left(3x-2\right)^3=64\)
=>3x-2=4
hay x=2
1) thực hiện phép tính
-126+67+[32-(-126)]-64
240-[(82-49):3+135]:18
A+1+2+22+23+...+22021
-205+37-(-200)
2) Tìm x∈z biết
x-45=48-68
35+5(6-x)=-12-(-112)
517-(x-124)=-483
46-(3x-2)3=(-38)+20
Bài 2:
a: =>x-45=-20
hay x=25
b: =>35+30-5x=-12+112=100
=>65-5x=100
=>5x=-35
hay x=-7
c: =>x-124=1000
hay x=1124
d: \(\Leftrightarrow46-\left(3x-2\right)^3=-18\)
\(\Leftrightarrow\left(3x-2\right)^3=64\)
=>3x-2=4
hay x=2
Bài1:Thực hiện phép tính:
a,(2^4.3.5^2):{450:[450-(4.5^3-2^3.5^2)]}
b,3^3.5^2-20{90-[164-2.(7^8:7^6+7^0)]}
c,[(18^7:18^6-17).2022-1986].5.1^2022-13^2.2020^0
Bài2:Tìm x:
a,(2^x+1)^2+3.(2^2+1)=2^2.10
b,3.(x-7)+2.(x+5)=41
(GIÚP MIK VỚI Ạ)
Bài 1.
\(a,\left(2^4\cdot3\cdot5^2\right):\left\{450:\left[450-\left(4\cdot5^3-2^3\cdot5^2\right)\right]\right\}\)
\(=\left(16\cdot3\cdot25\right):\left\{450:\left[450- \left(4\cdot125-8\cdot25\right)\right]\right\}\)
\(=\left(48\cdot25\right):\left\{450:\left[450-\left(500-200\right)\right]\right\}\)
\(=1200:\left[450:\left(450-300\right)\right]\)
\(=1200:\left(450:150\right)\)
\(=1200:3\)
\(=400\)
\(---\)
\(b,3^3\cdot5^2-20\left\{90-\left[164-2\cdot\left(7^8:7^6+7^0\right)\right]\right\}\)
\(=27\cdot25-20\left\{90-\left[164-2\cdot\left(7^2+1\right)\right]\right\}\)
\(=675-20\left\{90-\left[164-2\cdot\left(49+1\right)\right]\right\}\)
\(=675-20\left[90-\left(164-2\cdot50\right)\right]\)
\(=675-20\left[90-\left(164-100\right)\right]\)
\(=675-20\left(90-64\right)\)
\(=675-20\cdot26\)
\(=675-520\)
\(=155\)
\(---\)
\(c,\left[\left(18^7:18^6-17\right)\cdot2022-1986\right]\cdot5\cdot1^{2022}-13^2\cdot2020^0\)
\(=\left[\left(18-17\right)\cdot2022-1986\right]\cdot5\cdot1-169\cdot1\)
\(=\left(1\cdot2022-1986\right)\cdot5-169\)
\(=\left(2022-1986\right)\cdot5-169\)
\(=36\cdot5-169\)
\(=180-169\)
\(=11\)
Bài 2.
\(a) (2^x+1)^2+3\cdot(2^2+1)=2^2\cdot10\\\Rightarrow (2^x+1)^2+3\cdot(4+1)=4\cdot10\\\Rightarrow (2^x+1)^2+3\cdot5=40\\\Rightarrow (2^x+1)^2+15=40\\\Rightarrow (2^x+1)^2=40-15\\\Rightarrow (2^x+1)^2=25\\\Rightarrow (2^x+1)^2= (\pm 5)^2\\\Rightarrow \left[\begin{array}{} 2^x+1=5\\ 2^x+1=-5 \end{array} \right.\\ \Rightarrow \left[\begin{array}{} 2^x=4\\ 2^x=-6 (vô.lí) \end{array} \right. \\ \Rightarrow 2^x=2^2\\\Rightarrow x=2\)
Vậy \(x=2\).
\(---\)
\(b)3\cdot(x-7)+2\cdot(x+5)=41\\\Rightarrow 3\cdot x+3\cdot(-7)+2\cdot x+2\cdot5=41\\\Rightarrow 3x-21+2x+10=41\\\Rightarrow (3x+2x)+(-21+10)=41\\\Rightarrow 5x-11=41\\\Rightarrow 5x=41+11\\\Rightarrow 5x=52\\\Rightarrow x=\dfrac{52}{5}\)
Vậy \(x=\dfrac{52}{5}\).
\(Toru\)
Tìm x
a,246:x+ 34:x=5
b,360:x-126:x=6
a) 246 : x + 34 : x = 5
( 246 + 34 ) : x = 5
280 : x = 5
x = 280 : 5
x = 56
b) 360 : x - 126 : x = 6
( 360 - 126 ) : x = 6
. 234 : x = 6
x = 234 : 6
x = 39
a, 246 : x + 34 : x = 5
( 246 + 34 ) : x = 5
280 : x = 5
x = 280 : 5
x = 56
Vay x=56
b , 360 : x - 126 : x = 6
( 360 - 126 ) : x = 6
234 : x= 6
x= 234 : 6
x= 39
Vay x=39
246 : x + 34 : x = 5
( 246 + 34 ) : x = 5
280 : x = 5
x = 280 : 5
x = 56
360 : x - 126 : x = 6
( 360 - 126 ) : x = 6
234 : x = 6
x = 234 : 6
x = 39