Biết
\(\sin\alpha=\frac{8}{17}\), Tính B=\(4\sin^2\alpha+3\cos^2\alpha\)
TH
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1. Tìm x, biết: a. tan x+cot x2b. sin x.cos xfrac{sqrt{3}}{4}2. a. Biết tanalphafrac{1}{3}Tính Afrac{sinalpha-cosalpha}{sinalpha+cosalpha}b. Biết sinalphafrac{2}{3}Tính B3.sin^2alpha+4.cos^2alphac. Tính Csin^210^o+sin^220^o+sin^270^o+sin^280^od. Tính Dtan20^o.tan35^o.tan55^o.tan70^oe. Tính Esin^6alpha+cos^6alpha+3.sin^2alpha.cos^2alphaf. Tính F3.left(sin^3alpha+cos^3alpharight)-2.left(sin^6alpha+cos^6alpharight)g. Tính Gsqrt{sin^4alpha+4.cos^2alpha}+sqrt{cos^4alpha+4.sin^2alpha}Mọi người giúp mì...
Đọc tiếp
1. Tìm x, biết:
a. \(\tan x+\cot x=2\)
b. \(\sin x.\cos x=\frac{\sqrt{3}}{4}\)
2.
a. Biết \(\tan\alpha=\frac{1}{3}\)Tính A=\(\frac{\sin\alpha-\cos\alpha}{\sin\alpha+\cos\alpha}\)
b. Biết \(\sin\alpha=\frac{2}{3}\)Tính B=\(3.\sin^2\alpha+4.\cos^2\alpha\)
c. Tính C=\(\sin^210^o+\sin^220^o+\sin^270^o+\sin^280^o\)
d. Tính D=\(\tan20^o.\tan35^o.\tan55^o.\tan70^o\)
e. Tính E=\(\sin^6\alpha+\cos^6\alpha+3.\sin^2\alpha.\cos^2\alpha\)
f. Tính F=\(3.\left(\sin^3\alpha+\cos^3\alpha\right)-2.\left(\sin^6\alpha+\cos^6\alpha\right)\)
g. Tính G=\(\sqrt{\sin^4\alpha+4.\cos^2\alpha}+\sqrt{\cos^4\alpha+4.\sin^2\alpha}\)
Mọi người giúp mình với. Mình cảm ơn ạ!
Biết tan α=3. Tính giá trị các biểu thức sau:
a)\(\frac{\sin\alpha-\cos\alpha}{\sin\alpha+\cos\alpha}\)
b)\(\frac{2\sin\alpha+3\cos\alpha}{3\sin\alpha-5\cos\alpha}\)
c)\(\frac{1+2\cos^2\alpha}{\sin^2\alpha-\cos^2\alpha}\)
d)\(\frac{\sin^4\alpha+\cos^4\alpha}{1+\sin^2\alpha}\)
\(\frac{1}{cos^2a}=1+tan^2a\Rightarrow cos^2a=\frac{1}{1+tan^2a}=\frac{1}{10}\)
a/ \(\frac{sina-cosa}{sina+cosa}=\frac{\frac{sina}{cosa}-\frac{cosa}{cosa}}{\frac{sina}{cosa}+\frac{cosa}{cosa}}=\frac{tana-1}{tana+1}=\frac{3-1}{3+1}\)
b/ \(\frac{2sina+3cosa}{3sina-5cosa}=\frac{3tana+3}{3tana-5}=\frac{3.3+3}{3.3-5}\)
c/ \(\frac{1+2cos^2a}{1-cos^2a-cos^2a}=\frac{1+2cos^2a}{1-2cos^2a}=\frac{1+2.\frac{1}{10}}{1-2.\frac{1}{10}}\)
d/ \(\frac{\left(1-cos^2a\right)^2+\left(cos^2a\right)^2}{1+1-cos^2a}=\frac{\left(1-\frac{1}{10}\right)^2+\left(\frac{1}{10}\right)^2}{2-\frac{1}{10}}\)
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tính
a) \(\tan^2\alpha-\sin^2\alpha-\tan^2\alpha\times\sin^2\alpha\)
b)\(\frac{sin^4\alpha-cos^4\alpha}{sin\alpha+cos\alpha}-sin\alpha+cos\alpha\)
Cho tan \(\alpha\)=\(\frac{3}{5}\). Tính
A= \(\frac{\sin\alpha+\cos\alpha}{\sin\alpha-\cos\alpha}\)
B=\(\frac{\sin\alpha\cdot\cos\alpha}{\sin^2\alpha-\cos^2\alpha}\)
C=\(\frac{\sin^3\alpha\cdot\cos^3\alpha}{2\sin\alpha\cdot\cos^2\alpha+\cos\alpha\cdot\sin^2\alpha}\)
Giúp mình với . MÌnh cảm ơn
Cho góc nhọn \(\alpha\)thỏa mãn \(\tan\alpha=\frac{2}{\sqrt{3}}\). Tính: \(B=\frac{\cos^4\alpha+\sin^2\alpha\left(\cos^2\alpha+1\right)}{2\cos^4\alpha+2\sin^2\cos^2-\frac{3}{5}\sin^2\alpha}\)
Chứng minh:
a) \(\tan^2\alpha-\sin^2\alpha=\tan^2\alpha.\sin^2\alpha\)
b) \(\frac{1-\cos\alpha}{\sin\alpha}=\frac{\sin\alpha}{17\cos\alpha}\)
Cho \(\tan\alpha-5\cot\alpha+4=0.\). Tính \(A=\frac{4\sin\alpha+2\cos\alpha}{3\sin\alpha-\cos\alpha}\)
\(tana-5cota+4=0\Rightarrow tana-\dfrac{5}{tana}+4=0\)
\(\Rightarrow tan^2a+4tana-5=0\Rightarrow\left[{}\begin{matrix}tana=1\\tana=-5\end{matrix}\right.\)
\(A=\dfrac{4sina+2cosa}{3sina-cosa}=\dfrac{\dfrac{4sina}{cosa}+\dfrac{2cosa}{cosa}}{\dfrac{3sina}{cosa}-\dfrac{cosa}{cosa}}=\dfrac{4tana+2}{3tana-1}=\left[{}\begin{matrix}3\\\dfrac{9}{8}\end{matrix}\right.\)
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Cho \(\tan\alpha=\frac{3}{5}\), hãy tính giá trị của:
a) \(M=\frac{\sin\alpha+\cos\alpha}{\sin\alpha-\cos\alpha}\)
b) \(N=\frac{\sin\alpha\cos\alpha}{\sin^2\alpha-\cos^2\alpha}\)
c) \(P=\frac{\sin^3\alpha+\cos^3\alpha}{2\sin\alpha\cos^2\alpha+\cos\alpha\sin^2\alpha}\)
\(M=\frac{\frac{sina}{cosa}+\frac{cosa}{cosa}}{\frac{sina}{cosa}-\frac{cosa}{cosa}}=\frac{tana+1}{tana-1}=\frac{\frac{3}{5}+1}{\frac{3}{5}-1}=...\)
\(N=\frac{\frac{sina.cosa}{cos^2a}}{\frac{sin^2a}{cos^2a}-\frac{cos^2a}{cos^2a}}=\frac{tana}{tan^2a-1}=...\) (thay số bấm máy)
\(P=\frac{\frac{sin^3a}{cos^3a}+\frac{cos^3a}{cos^3a}}{\frac{2sina.cos^2a}{cos^3a}+\frac{cosa.sin^2a}{cos^3a}}=\frac{tan^3a+1}{2tana+tan^2a}=...\)
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TD
Cho $\tan \alpha = 3$. Tính
a) \(\dfrac{2\sin\alpha+3\cos\alpha}{3\sin\alpha-4\cos\alpha}.\)
b) \(\dfrac{\sin\alpha\cos\alpha}{\sin^2\alpha-\sin\alpha\cos\alpha+\cos^2\alpha}.\)
a) \(\dfrac{2sina+3cosa}{3sina-4cosa}=\dfrac{9}{5}\)
b) \(\dfrac{sina.cosa}{sin^2a-sina.cosa+cos^2a}=0\)
\(a.\dfrac{2\sin\alpha+3\cos\alpha}{3\sin\alpha-4\cos\alpha}=\dfrac{2\left(3cos\alpha\right)+3cos\alpha}{3\left(3cos\alpha\right)-4cos\alpha}=\dfrac{9cos\alpha}{5cos\alpha}=\dfrac{9}{5}\)
\(b.\dfrac{sin\alpha cos\alpha}{sin^2\alpha-sin\alpha cos\alpha+cos^2\alpha}=\dfrac{3cos^2\alpha}{9cos^2\alpha-3cos^2\alpha+cos^2\alpha}=\dfrac{3cos^2\alpha}{7cos^2\alpha}=\dfrac{3}{7}\)
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