\(\dfrac{4}{5}\times\dfrac{5}{8}=\dfrac{20}{40}=\dfrac{1}{2}\)

\(\dfrac{7}{15}+\dfrac{4}{5}=\dfrac{7}{15}+\dfrac{12}{15}=\dfrac{19}{15}\)

\(\dfrac{2}{3}-\dfrac{3}{8}=\dfrac{16}{24}-\dfrac{9}{24}=\dfrac{7}{24}\)

\(\dfrac{1}{2}\div\dfrac{2}{5}=\dfrac{1}{2}\times\dfrac{5}{2}=\dfrac{5}{4}\)

1/2

19/15

7/24

5/4

4/5 x 5/8

= 20/40

= 1/2

7/15 + 4/5

= 7/15 + 12/15

= 19/15

2/3 - 3/8

= 16/24 - 9/24

= 7/24

1/2 : 2/5

= 1/2 x 5/2

= 5/4

a) 3 x 1/5 + 2/5 = 3/5 + 2/5 = 1

b) 3 : 1/5 - 2/5 = 15 - 2/5 = 73/5

bài 2 :
a) X x 1/2 = 1 - 1/5

    X x 1/2 = 4/5 

           X   = 4/5 : 1/2

           X   = 8/5 

vậy x =...

b) x : 1/3 = 1 + 1/5

    x : 1/3 = 6/5

          x   = 6/5 x 1/3

          x   = 2/5

vậy x =...

2/5 x 1/2 : 1/3 = 2/5 x 1/2 x 3 = 3/5

1/2 x 1/3 + 1/4= 1/6 + 1/4 = 4/24 + 6/24 = 10/24 =5/12

\(\dfrac{2}{5}\times\dfrac{1}{2}:\dfrac{1}{3}=\dfrac{2}{5}\times\dfrac{3}{2}=\dfrac{3}{5}\)

\(\dfrac{1}{2}\times\dfrac{1}{3}+\dfrac{1}{4}=\dfrac{1}{6}+\dfrac{1}{4}=\dfrac{2}{12}+\dfrac{3}{12}=\dfrac{5}{12}\)

2/5 x 1/2 : 1/3

= 1/5 : 1/3 

= 3/5

1/2 x 1/3 + 1/4

= 1/6 + 1/4

= 5/12

1) \(x.\left(x+7\right)=0\)
\(=>\left[\begin{matrix}x=0\\x+7=0\end{matrix}\right.=>\left[\begin{matrix}x=0\\x=-7\end{matrix}\right.\)
2) \(\left(x+12\right).\left(x-3\right)=0\)
\(=>\left[\begin{matrix}x+12=0\\x-3=0\end{matrix}\right.=>\left[\begin{matrix}x=-12\\x=3\end{matrix}\right.\)
3) \(\left(-x+5\right).\left(3-x\right)=0\)
\(=>\left[\begin{matrix}-x+5=0\\3-x=0\end{matrix}\right.=>\left[\begin{matrix}x=5\\x=3\end{matrix}\right.\)
4) \(x.\left(2+x\right).\left(7-x\right)=0\)
\(=>\left[\begin{matrix}x=0\\2+x=0\\7-x=0\end{matrix}\right.=>\left[\begin{matrix}x=0\\x=-2\\x=7\end{matrix}\right.\)
5) \(\left(x-1\right).\left(x+2\right).\left(-x-3\right)=0\)
\(=>\left[\begin{matrix}x-1=0\\x+2=0\\-x-3=0\end{matrix}\right.=>\left[\begin{matrix}x=1\\x=-2\\x=-3\end{matrix}\right.\)

Tổng quát: tích ab = 0 thì a=0 hoặc b=0

\(a\cdot b\cdot c=0\Leftrightarrow\left[\begin{matrix}a=0\\b=0\\c=0\end{matrix}\right.\)(nếu có 3 thừa số)

30240 : x = 42 

x = 30240 : 42

 x = 720

[ x + 3] x 247 = 40755

x + 3 = 40755 : 247

x + 3 = 165

x = 165 - 3

x = 162

57316 : [ x - 8 ] = 623

x-8 = 57316 : 623

x-8 = 92

x = 92 + 8

x = 100

x x 37 = 1147

x = 1147 : 37

x = 31

30240 : x = 42 

             x= 30240 : 42

             x=720

(x + 3) x 247 = 40755

 x  + 3            =  40755 : 247

  x  + 3           =    165

 x                   = 165 - 3

 x                   = 162 

57316 : (x - 8 )= 623

               x- 8  = 57316 : 623

              x- 8   = 92

              x       = 92 + 8

              x       = 100

X x 37 = 1147

X         = 1147 : 37

X         = 31

\(30240:x=42\)                       

\(x=30240:42\)

\(x=720\)

\(\left[x+3\right]\times247=40755\)

\(x+3=40755:247\)

\(x+3=165\)

\(x=165-3\)

\(x=162\)

\(57316:\left[x-8\right]=623\)

\(x-8=57316:623\)

\(x-8=92\)

\(x=92+8\)

\(x=100\)

\(x\times37=1147\)

\(x=1147:37\)

\(x=31\)

tớ  chưa học xin lỗi

`x - 3/3 = 4 - 1 - 2x/5`

`->` `x = (-5)`

\(\dfrac{x-3}{3}=4-\dfrac{1-2x}{5}\)

=>5(x-3)=60-3(1-2x)

=>5x-15=60-3+6x

=>5x-15=6x+57

=>6x+57=5x-15

hay x=-72(nhận)

\(3x\left(2x+1\right)=0\)

\(\Rightarrow\orbr{\begin{cases}2x+1=0\\3x=0\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}2x=-1\\x=0\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=-\frac{1}{2}\\x=0\end{cases}}\)

\(\frac{\frac{6}{5}+\frac{6}{35}-\frac{6}{125}-\frac{6}{2009}-\frac{6}{2011}}{\frac{7}{5}+\frac{7}{35}-\frac{7}{125}-\frac{7}{2009}-\frac{7}{2011}}\)

\(=\frac{6.(\frac{1}{5}+\frac{1}{35}-\frac{1}{125}-\frac{1}{2009}-\frac{1}{2011})}{7.(\frac{1}{5}+\frac{1}{35}-\frac{1}{125}-\frac{1}{2009}-\frac{1}{2011})}\)

\(=\frac{6}{7}\)

Tìm x

\(a,3x(2x+1)=0\)

\(\Rightarrow\hept{\begin{cases}3x=0\\2x+1=0\end{cases}}\)

\(\Rightarrow\hept{\begin{cases}x=0\\x=\frac{-1}{2}\end{cases}}\)

Vậy \(x=0\)hoặc \(x=\frac{-1}{2}\)

\(b.\frac{2}{3}-\frac{1}{3}(x-\frac{3}{2})-\frac{1}{2}(2x+1)=5\)

\(\frac{2}{3}-\frac{1}{3}x+\frac{1}{2}-x-\frac{1}{2}=5\)

\(\frac{2}{3}+\frac{1}{2}-\frac{1}{2}-x(\frac{1}{3}+1)=5\)

\(\frac{4}{3}x=\frac{2}{3}-5\)

\(\frac{4}{3}x=\frac{-13}{3}\)

\(x=\frac{-13}{3}\div\frac{4}{3}\)

\(x=\frac{-13}{4}\)

Chúc ban học tốt

\(\frac{\frac{6}{5}+\frac{6}{35}-\frac{6}{125}-\frac{6}{2009}-\frac{6}{2011}}{\frac{7}{5}+\frac{7}{35}-\frac{7}{125}-\frac{7}{2009}-\frac{7}{2011}}\)

\(=\frac{6.\left(\frac{1}{5}+\frac{1}{35}-\frac{1}{125}-\frac{1}{2009}-\frac{1}{2011}\right)}{7.\left(\frac{1}{5}+\frac{1}{35}-\frac{1}{125}-\frac{1}{2009}-\frac{1}{2011}\right)}=\frac{6}{7}\)

Tìm x

a)bạn tự làm vì nó rất dễ nha

b)\(\frac{2}{3}-\frac{1}{3}.\left(x-\frac{3}{2}\right)-\frac{1}{2}.\left(2x+1\right)=5\)

\(\frac{2}{3}-\frac{1}{3}x-\frac{1}{2}-\frac{1}{2}.2x-\frac{1}{2}=5\)

\(\frac{2}{3}-\frac{1}{3}x-\frac{1}{2}-\frac{2}{2}x-\frac{1}{2}=5\)

\(\frac{2}{3}-\frac{1}{3}x-\frac{1}{2}-x-\frac{1}{2}=5\)

\(\frac{1}{3}x-x=5+\frac{1}{2}+\frac{1}{2}+\frac{2}{3}\)

\(\left(\frac{1}{3}-1\right)x=5+1+\frac{2}{3}\)

\(\frac{-2}{3}x=6+\frac{2}{3}\)

\(\frac{-2}{3}x=\frac{20}{3}\)

\(x=\frac{20}{3}:\left(\frac{-2}{3}\right)\)

\(x=\frac{20}{3}.\left(\frac{3}{-2}\right)\)

x=-10

Vậy x=-10

Chúc bạn học tốt

theo dõi giúp mik nhé^^