Câu nào bạn ơi

12 What do you often do after school?

13 What is he doing now?

14 Where are you often have dinner?

15 What is Lan going to buy

16 Where are they going to stay?

17 Why do you like learning English?

18 How many pens does she want>

19 What does Nam have for for lunch

20 How many books does Ha have in the bags?

12. What do you often do after school?

13. What is he doing now?

14. Where do you often have dinner? 

15. What is Lan going to buy?
16. Where are they going to stay?

 17. Why do you like learning English?
18. How many pens does she want?

19. What does Nam have for lunch? 

20. How many books does Ha have in the bags? 

9. Has the work been done by him?

10. The boxes were opened and cigarettes were taken out by us

11. She was given a new one

12. He is proved wrong

13. We were promised higher wages

14. This is the third time we have been written to about this by them

15. We were asked to be there at 8 o'clock

16. She is being shown how to do it

18-3x6x7=18-18x7=18x(1-7)=18x(-6)=-108

18-3.6.7

=18-18.7

=18.(1-7)

=18.-6

=-108

18-3.6.7

=18-(3.6).7

=18-18.7

=18-126

=-108

hình thì đăng 1 câu thôi:)

Giúp ik

xét tam giác amb và tam giác amc 

am là cạnh chung 

mb =mc (am là trung tuyến )

ab =ac tam giác abc cân 

tam giác amb =amc (ccc)

dpcm

b)ta có tam giác amb = tam giác amc 

bam = cam ( 2 góc tương úng)

am là tia phân giác của bac

C)xét tam giấcpm và tam  giác aqm 

am là cạnh chung 

ap = aq 

pam = qam 

tam giác apm = tam giác aqm

pm = qm ( 2 cạnh tương ứng )

xét tam giác apm và tam giác aqm 

pm =qm ( cmt ) 

pb = qc 

bm = cm 

tam giác apm = tam giác aqm 

mp = mq 

dpcm

làm mõi bài 1 thôi nhé

a) Ta có: \(x^2-3=0\)

nên \(x^2=3\)

hay \(x\in\left\{\sqrt{3};-\sqrt{3}\right\}\)

b) Ta có: \(4x^2-9=0\)

\(\Leftrightarrow\left(2x-3\right)\left(2x+3\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=-\dfrac{3}{2}\end{matrix}\right.\)

c) Ta có: \(\left(x+2\right)^2-\left(x-2\right)^2=5\)

\(\Leftrightarrow x^2+4x+4-x^2+4x-4=5\)

\(\Leftrightarrow8x=5\)

hay \(x=\dfrac{5}{8}\)

d) Ta có: \(\left(x+2\right)^3-x^3+6x^2=7\)

\(\Leftrightarrow x^3+6x^2+12x+8-x^3+6x^2-7=0\)

\(\Leftrightarrow12x^2+12x+1=0\)

\(\Delta=12^2-4\cdot12\cdot1=144-48=96\)

Vì Δ>0 nên phương trình có hai nghiệm phân biệt là:

\(\left\{{}\begin{matrix}x_1=\dfrac{-12-4\sqrt{6}}{24}=\dfrac{-3-\sqrt{6}}{6}\\x_2=\dfrac{-12+4\sqrt{6}}{24}=\dfrac{-3+\sqrt{6}}{6}\end{matrix}\right.\)

e) Ta có: \(\left(x-2\right)^2-\left(x-1\right)\left(x+1\right)=7\)

\(\Leftrightarrow x^2-4x+4-x^2+1=7\)

\(\Leftrightarrow-4x=2\)

hay \(x=-\dfrac{1}{2}\)

a) Ta có: \(P\left(x\right)=7x^3+3x^4-x^2+5x^2-6x^3-2x^4+2017-x^3\)

\(=x^4+4x^2+2017\)

b) Bậc của P(x) là 4

c) Các hệ số của P(x) là 1;4;2017

Hệ số cao nhất là 4

Hệ số tự do là 2017

d) \(P\left(0\right)=0^4+4\cdot0^2+2017=2017\)

\(P\left(1\right)=1^4+4\cdot1^2+2017=1+4+2017=2022\)

\(P\left(-1\right)=\left(-1\right)^4+4\cdot\left(-1\right)^2+2017=1+4+2017=2022\)

e) \(P\left(-a\right)=\left(-a\right)^4+4\cdot\left(-a\right)^2+2017=a^4+4a^2+2017\)

\(P\left(a\right)=a^4+4a^2+2017\)

Do đó: P(-a)=P(a)