\(A=\frac{1135}{23}-\left(\frac{167}{32}+\frac{330}{23}\right)=\frac{1135}{23}-\frac{330}{23}+\frac{167}{32}=35+\frac{167}{32}=\frac{1287}{32}\)

49\(\frac{8}{23}\) - (5\(\frac{7}{32}\) + 14\(\frac{8}{23}\) )

= \(\frac{1135}{23}\) - (\(\frac{167}{32}\) +\(\frac{330}{23}\) )

= \(\frac{1135}{23}\) - \(\frac{14401}{736}\) 

=\(\frac{953}{32}\)

\(49\frac{8}{23}-\left(5\frac{7}{32}+14\frac{8}{23}\right)\)

\(=\frac{1135}{23}\left(\frac{135}{32}+\frac{330}{23}\right)\)

\(=\frac{1135}{23}.\frac{13665}{736}\)

\(=916,2201678\)

=1135/23-(167/32+330/23)

=(1135/23-330/23)-167/32

=35-167/32

=1120/32-167/32

=953/32

=hỗn số 29:25/32

  \(=49\frac{8}{23}-5\frac{7}{32}-14\frac{8}{23}\)

\(=\left(49\frac{8}{23}-14\frac{8}{23}\right)-5\frac{7}{32}\)

\(=35\frac{0}{23}-5\frac{7}{32}\)

\(=\frac{805}{23}-\frac{167}{32}\)

\(\frac{25760}{736}-\frac{3841}{736}\)

\(=\frac{21919}{736}=\frac{953}{32}\)

1135/23-167/32+330/23

=(1135/23-330/23)+167/32

=805/23+167/32

=35+167/32

=1120/32+167/32

=1287/32

\(=49\frac{8}{23}-5\frac{7}{32}-14\frac{8}{23}\)

\(=49\frac{8}{23}-14\frac{8}{23}-5\frac{7}{12}\)

\(=35-5\frac{7}{32}\)

\(=35-\frac{167}{32}\)

\(=\frac{1120}{32}-\frac{167}{32}\)

\(=\frac{935}{32}\)

\(49\frac{8}{23}-\left(5\frac{7}{32}+14\frac{8}{23}\right)\)

\(=49\frac{8}{23}-5\frac{7}{32}-14\frac{8}{23}\)

\(=\left(49\frac{8}{23}-14\frac{8}{23}\right)-5\frac{7}{32}\)

\(=35-5\frac{7}{32}\)

\(=35-\frac{167}{32}\)

\(=\frac{953}{32}\)

\(A=35-\frac{167}{32}\)

\(A=\frac{953}{32}\)

Bài 1:

5/16:0,125-(2 1/4-0,6).10/11

=5/16:5/4-(9/4-3/5).10/11

=1/4-33/20.10/11

=1/4-3/2

=-5/4

\(\frac{5}{16}:0,125-\left(2\frac{1}{4}-0,6\right).\frac{10}{11}\)

\(=\frac{5}{16}.8-\frac{33}{20}.\frac{10}{11}\)

\(=\frac{5}{2}-\frac{3}{2}=\frac{2}{2}=1\)

<br class="Apple-interchange-newline"><div></div>49823 −(5732 +14823 )

\(49\frac{8}{23}-19\frac{417}{736}\)

\(=\frac{953}{12}\)

Study well 

\(\frac{5}{16}:0,125-\left(2\frac{1}{4}-0,6\right).\frac{10}{11}\)ư

= \(\frac{5}{16}:\frac{1}{8}-\left(\frac{9}{4}-\frac{3}{5}\right).\frac{10}{11}\)

= \(\frac{5}{16}.8-\left(\frac{9}{4}-\frac{3}{5}\right).\frac{10}{11}\)

= \(\frac{5}{2}-\left(\frac{45}{20}-\frac{12}{20}\right).\frac{10}{11}\)

= \(\frac{5}{2}-\frac{33}{20}.\frac{10}{11}\)

= \(\frac{5}{2}-\frac{3}{2}\)

= \(1\)

b) \(49\frac{8}{23}-\left(5\frac{5}{32}+14\frac{8}{23}\right)\)

= \(49\frac{8}{23}-5\frac{7}{32}-14\frac{8}{23}\)

= \(\left(49\frac{8}{23}-14\frac{8}{23}\right)-5\frac{7}{32}\)

= \(35-\frac{167}{32}\)

= \(\frac{1120}{32}-\frac{167}{32}\)

= \(\frac{953}{32}\)

Chúc bạn học tốt !!! 

A= \(49\frac{8}{23}-\left(5\frac{7}{32}+14\frac{8}{23}\right)\)

=\(\frac{1135}{32}-\left(\frac{167}{32}+\frac{330}{23}\right)\)

=\(\frac{1135}{23}-\frac{167}{32}-\frac{330}{23}\)

=\(\left(\frac{1135}{23}-\frac{330}{23}\right)-\frac{167}{32}\)

=\(\frac{805}{23}-\frac{167}{32}\)

=\(\frac{953}{32}\)

B=\(6\frac{3}{8}+5\frac{1}{2}\)

=\(\frac{51}{8}+\frac{11}{2}\)

=\(\frac{51}{8}+\frac{44}{8}\)

=\(\frac{51+44}{8}\)

=\(\frac{95}{8}\)