tính bằng cách thuận tiện
a) 27/8-7/3+4/3-2
b) 7/9-3/7+2/3-4/7
c) 13,8+7-5,25+4,25
Tính bằng cách thuận tiện nhất
a) 27/8-7/3+4/3+2
b) 7/9-3/7+2/3-4/7
c) 13,8+7-5,25+4,25
c)=13,8+(7+4,25)-5,25
=13,8+(11.25-5.25)
=13,8+6=19,8
b, = 7/9 - 2/3 - < 4/7 =3/7 >
= 13/9 - 1
= 4/9
Tính bằng cách thuận tiện nhất :
1987+1992+1997+2002+2007
4,25+4,32+4,39+4,46+4,53
27/8 - 7/3 + 4/3 - 2
7/9 - 3/7 + 2/3 - 4/7
13,8 + 7 - 5,25 + 4,25
Bài 2 Tình bằng cách thuận tiện nhất
a, 7/9 - 2/7 + 2/3 + 4/7
b, 13,8 + 7 - 5,25 + 4,25
\(a,\dfrac{7}{9}-\dfrac{2}{7}+\dfrac{2}{3}+\dfrac{4}{7}\\ =\left(\dfrac{7}{9}+\dfrac{6}{9}\right)+\left(\dfrac{4}{7}-\dfrac{2}{7}\right)\\ =\dfrac{13}{9}+\dfrac{2}{7}\\ =\dfrac{109}{63}\\ b,13,8+7-5,25+4,25\\ =\left(13,8+7\right)-\left(5,25-4,25\right)\\ =20,8-1\\ =19,8\)
a \(\left(\dfrac{4}{7}-\dfrac{2}{7}\right)+\left(\dfrac{7}{9}+\dfrac{2}{3}\right)=\dfrac{2}{7}+\left(\dfrac{7}{9}+\dfrac{6}{9}\right)=\dfrac{2}{7}+\dfrac{15}{9}=\dfrac{2}{7}+\dfrac{5}{3}=\dfrac{6}{21}+\dfrac{35}{21}=\dfrac{41}{21}\)
b \(20.8-1=19.8\)
tính bằng cách thuận tiện
a) \(\frac{7}{9}\) - \(\frac{3}{7}\) + \(\frac{2}{3}\) -\(\frac{4}{7}\)
b) 13,8 + 7 - 5,25 + 4,25
a)\(\frac{7}{9}-\frac{3}{7}+\frac{2}{3}-\frac{4}{7}\)
\(=\frac{7}{9}+\frac{-3}{7}+\frac{2}{3}+\frac{-4}{7}\)
\(=\left(\frac{7}{9}+\frac{2}{3}\right)+\left(\frac{-3}{7}+\frac{-4}{7}\right)\)
\(=\frac{13}{9}-1\)
\(=\frac{4}{9}\)
b)13,8 + 7 - 5,25 + 4,25
=(13,8 + 7 + 4,25 ) - 5,25
=25,05 - 5,25
=19,8
Tính bằng cách thuận tiện nhất
\(\frac{27}{8}-\)\(\frac{7}{3}\)\(+\frac{4}{3}\)-2
\(\frac{7}{9}-\frac{3}{7}+\frac{2}{3}-\frac{4}{7}\)
13,8+7-5,5+4,25
tính nhanh:
a) 7/9-3/7+2/3-4/7
b)13,8+7-5,25+4,25
a) 7/9 - 3/7 + 2/3 - 4/7
= 7/9 - 3/7 + 6/9 - 4/7
=( 7/9 - 6/9 ) + ( 3/7 + 4/7 )
= 1/9 + 1
=10/9
b) 13,8 + 7 - 5,25 + 4,25
=(13,8 + 7 ) - (5,25 + 4,25 )
=20,8 - 9,5
= 11,3
Bài 4: Tính bằng cách thuận tiện
a) 5/9 + 13/7 + 15/13 + 8/7 + 4/9 + 11/13
b) 3/5 + 18/9 + 4/10
a) \(\dfrac{5}{9}+\dfrac{13}{7}+\dfrac{15}{13}+\dfrac{8}{7}+\dfrac{4}{9}+\dfrac{11}{13}\)
\(=\left(\dfrac{5}{9}+\dfrac{4}{9}\right)+\left(\dfrac{13}{7}+\dfrac{8}{7}\right)+\left(\dfrac{15}{13}+\dfrac{11}{13}\right)\)
\(=1+3+2\)
\(=6\)
b) \(\dfrac{3}{5}+\dfrac{18}{9}+\dfrac{4}{10}\)
\(=0,6+2+0,4\)
\(=\left(0,6+0,4\right)+2\)
\(=1+2\)
\(=3\)
\(a\dfrac{5}{9}+\dfrac{4}{9}+\dfrac{13}{7}+\dfrac{8}{7}+\dfrac{15}{13}+\dfrac{11}{13}=\dfrac{9}{9}+\dfrac{21}{7}+\dfrac{26}{13}=1+3+2=6\)
\(b\dfrac{3}{5}+2+\dfrac{2}{5}=\dfrac{5}{5}+2=1+2=3\)
Tính bằng cách thuận tiện
a. 5/7 x 5/9 + 4/9 x 5/7
b. 1/10 + 5/9 + 4/9 + 9/10 – 1
c. 5/7 x 5/9 + 4/9 x 5/7 + 2/7
d. 2/7 + 2/8 + 1/4 + 1/7 + 4/7
e. 4/5 + 3/10 + 2/10 + 0,7
f. 326 x 728 + 326 x 272
a) \(\dfrac{5}{7}\times\dfrac{5}{9}+\dfrac{4}{9}\times\dfrac{5}{7}\)
\(=\dfrac{5}{7}\times\left(\dfrac{4}{9}+\dfrac{5}{9}\right)\)
\(=\dfrac{5}{7}\times1\)
\(=\dfrac{5}{7}\)
b) \(\dfrac{1}{10}+\dfrac{5}{9}+\dfrac{4}{9}+\dfrac{9}{10}-1\)
\(=\left(\dfrac{5}{9}+\dfrac{4}{9}\right)+\left(\dfrac{1}{10}+\dfrac{9}{10}-1\right)\)
\(=1+0\)
\(=1\)
c) \(\dfrac{5}{7}\times\dfrac{5}{9}+\dfrac{4}{9}\times\dfrac{5}{7}+\dfrac{2}{7}\)
\(=\dfrac{5}{7}\times\left(\dfrac{5}{9}+\dfrac{4}{9}\right)+\dfrac{2}{7}\)
\(=\dfrac{5}{7}+\dfrac{2}{7}\)
\(=1\)
d) \(\dfrac{2}{7}+\dfrac{2}{8}+\dfrac{1}{4}+\dfrac{1}{7}+\dfrac{4}{7}\)
\(=\left(\dfrac{2}{8}+\dfrac{1}{4}\right)+\left(\dfrac{2}{7}+\dfrac{1}{7}+\dfrac{4}{7}\right)\)
\(=\left(\dfrac{1}{4}+\dfrac{1}{4}\right)+1\)
\(=\dfrac{1}{2}+1\)
\(=\dfrac{3}{2}\)
e) \(\dfrac{4}{5}+\dfrac{3}{10}+\dfrac{2}{10}+0,7\)
\(=\dfrac{4}{5}+\dfrac{5}{10}+\dfrac{7}{10}\)
\(=\dfrac{4}{5}+\dfrac{12}{10}\)
\(=\dfrac{4}{5}+\dfrac{6}{5}\)
\(=\dfrac{10}{5}\)
\(=2\)
g) \(362\times728+326\times272\)
\(=326\times\left(728+272\right)\)
\(=326\times1000\)
\(=326000\)
Tính thuận tiện
a) A=(15 - 6 13/18) : 11 1/27 - 2 1/8 : 1 11/40
b) B=(-3,2) . -15/64 + (0,8 - 2 4/15): 3 2/3
c) C= -7/9 . 4/11 + -7/9. 7/11 + 5 7/9
d) D= 50% .1 1/3 . 10 . 7/35 . 0,75
e) E= (2/5)^2 + 5 1/2 (4,5 - 2) + 23/-4
a: \(=\left(15-6-\dfrac{13}{18}\right):\dfrac{298}{27}-\dfrac{17}{8}:\dfrac{51}{40}\)
\(=\dfrac{149}{18}\cdot\dfrac{27}{298}-\dfrac{5}{3}=\dfrac{3}{2}-\dfrac{5}{3}=\dfrac{9-10}{6}=\dfrac{-1}{6}\)
b: \(=\dfrac{-16}{5}\cdot\dfrac{-15}{64}+\dfrac{-22}{15}:\dfrac{11}{2}\)
\(=\dfrac{3}{4}-\dfrac{4}{15}=\dfrac{29}{60}\)
c: \(=\dfrac{-7}{9}\left(\dfrac{4}{11}+\dfrac{7}{11}\right)+5+\dfrac{7}{9}=\dfrac{-7}{9}+\dfrac{7}{9}+5=5\)
d: \(=\dfrac{1}{2}\cdot\dfrac{4}{3}\cdot10\cdot\dfrac{1}{5}\cdot\dfrac{3}{4}=1\)
e: \(=\dfrac{4}{25}+\dfrac{11}{2}\cdot\dfrac{5}{2}+\dfrac{-23}{4}=\dfrac{204}{25}\)