5¹⁰:5⁸+3².2021⁰=
Q=1/5+2/5^2+3/5^3+...+2021/5^2021+2022/5^2022
So sánh Q với 5/36
(-3).(-137)+(-3).(-63)+2.17
(-5).(121-2021)+(-5).2021
a: =-3x200+34=-600+34=-566
(2021/2022 + 3/5 + -2021/2022) : 1^2/5
Hãy chứng tỏ 2021^3 + 2021^4+ 2021^5+ 2021^6+ 2021^7 chia hết cho 2022
a, 1-2+3-4+5-6+....+2021-2022
b, 1-6+2-7+3-8+4-9+.......+35-40
c, -1+2-3+4-5+6-.........-2021+2022
d, 1-4+2-5+3-6+.....+197-200
e, -1-2-3-4-5-....-199-200
a: =(-1)+(-1)+...+(-1)=-1011
b: =(-5)+(-5)+...+(-5)=-175
Xếp các phân số sau theo thứ tự từ lớn đến bé
a, 5/6 ; 6/5; 2021/2021 ; 7/3
b, 1/7 ; 2/7 ; 1/6 ; 5/3
a)M=-2021-68+2021-17-68
b)B=1-2+3-4+5-6+.....+991-1000
c)C=1-2-3+4+5-6-7+8+.......-998-999+1000
a: M=-2021+2021-68-68+17
=-119
b: B=(-1)+(-1)+...+(-1)
=-1x500
=-500
c: C=(1-2-3+4)+(5-6-7+8)+...+(997-998-999+1000)
=0
*Thực hiện
1/ (\(\dfrac{2021}{2020}\)+\(\dfrac{2020}{2021}\)) x (\(\dfrac{1}{2}\)-\(\dfrac{1}{3}\)-\(\dfrac{1}{6}\))
2/ (\(\dfrac{7}{19}\)-\(\dfrac{5}{12}\)):\(\dfrac{-5}{8}\)-(\(\dfrac{7}{19}\)-\(\dfrac{29}{12}\)):\(\dfrac{5}{8}\)
3/ \(\dfrac{-5}{6}\)x\(\dfrac{7}{24}\)-\(\dfrac{5}{6}\)x\(\dfrac{14}{24}\)-\(\dfrac{5}{6}\)x\(\dfrac{3}{24}\)
1/ \(\left(\dfrac{2021}{2020}+\dfrac{2020}{2021}\right).\left(\dfrac{1}{2}-\dfrac{1}{3}-\dfrac{1}{6}\right)\)
=\(\left(\dfrac{2021}{2020}+\dfrac{2020}{2021}\right).0\)
=\(0\)
mink chịu bài này nó rất khó
= 5 + 5 mũ 2 + 5 mũ 3 + ... + 5 mũ 2021 cho 30
\(A=5+5^2+5^3+...+5^{2021}\)
\(\Rightarrow A=\left(5^1+5^2\right)+5^2\left(5^1+5^2\right)...+5^{2018}\left(5^1+5^2\right)+5^{2021}\)
\(\Rightarrow A=30+5^2.30...+5^{2018}.30+5^{2021}\)
\(\Rightarrow A:30=1+5^2+...+5^{2018}+\dfrac{5^{2021}}{30}\)
\(\Rightarrow A:30=1+5^2+...+5^{2018}+\dfrac{5^{2020}}{6}\)
số dư là bao nhieu ạ ?
đề bài tìm số dư ạ