\(=5^2+9\cdot1\)
\(=25+9\)
\(=34\)
\(5^{10}:5^8+3^2.2021^0\\ =5^2+3^2.1\\ =25+9\\ =34\)
\(5^{10}\):\(5^8\)+\(3^2\).\(2021^0\)
=25+9.1
=34
\(=5^2+9\cdot1\)
\(=25+9\)
\(=34\)
\(5^{10}:5^8+3^2.2021^0\\ =5^2+3^2.1\\ =25+9\\ =34\)
\(5^{10}\):\(5^8\)+\(3^2\).\(2021^0\)
=25+9.1
=34
Q=1/5+2/5^2+3/5^3+...+2021/5^2021+2022/5^2022
So sánh Q với 5/36
(-3).(-137)+(-3).(-63)+2.17
(-5).(121-2021)+(-5).2021
(2021/2022 + 3/5 + -2021/2022) : 1^2/5
a, 1-2+3-4+5-6+....+2021-2022
b, 1-6+2-7+3-8+4-9+.......+35-40
c, -1+2-3+4-5+6-.........-2021+2022
d, 1-4+2-5+3-6+.....+197-200
e, -1-2-3-4-5-....-199-200
a)M=-2021-68+2021-17-68
b)B=1-2+3-4+5-6+.....+991-1000
c)C=1-2-3+4+5-6-7+8+.......-998-999+1000
*Thực hiện
1/ (\(\dfrac{2021}{2020}\)+\(\dfrac{2020}{2021}\)) x (\(\dfrac{1}{2}\)-\(\dfrac{1}{3}\)-\(\dfrac{1}{6}\))
2/ (\(\dfrac{7}{19}\)-\(\dfrac{5}{12}\)):\(\dfrac{-5}{8}\)-(\(\dfrac{7}{19}\)-\(\dfrac{29}{12}\)):\(\dfrac{5}{8}\)
3/ \(\dfrac{-5}{6}\)x\(\dfrac{7}{24}\)-\(\dfrac{5}{6}\)x\(\dfrac{14}{24}\)-\(\dfrac{5}{6}\)x\(\dfrac{3}{24}\)
1/1+3+1/1+3+5+...+1/1+3+5+...+2021
S = 5 + 5^2 + 5^3 + ... + 5^2020 + 5^2021. Chứng minh 4 . S + 5 + 5^2022
s= 5 +5^2+5^3+...+5^2020+5^2021. Chứng tỏ rằng 4.S+5=5^2022