a) \(A=\sqrt{9a}-\sqrt{16a}-\sqrt{49a}=3\sqrt{a}-4\sqrt{a}-7\sqrt{a}=-8\sqrt{a}\)

b) \(B=\dfrac{3+2\sqrt{3}}{\sqrt{3}}+\dfrac{2+\sqrt{2}}{\sqrt{2}}-\left(\sqrt{3}+\sqrt{2}\right)\)

\(=\dfrac{\sqrt{3}\left(2+\sqrt{3}\right)}{\sqrt{3}}+\dfrac{\sqrt{2}\left(\sqrt{2}+1\right)}{\sqrt{2}}-\left(\sqrt{3}+\sqrt{2}\right)\)

\(=2+\sqrt{3}+\sqrt{2}+1-\sqrt{3}-\sqrt{2}=3\)

\(\frac{1}{x+1}+\frac{1}{x-1}+\frac{2}{1-x^2}\)

\(=\frac{1}{x+1}+\frac{1}{x-1}-\frac{2}{\left(x-1\right)\left(x+1\right)}\)

\(=\frac{x-1+x+1-2}{\left(x-1\right)\left(x+1\right)}\)

\(=\frac{2x-2}{\left(x-1\right)\left(x+1\right)}\)

\(=\frac{2\left(x-1\right)}{\left(x-1\right)\left(x+1\right)}\)

\(=\frac{2}{x+1}\)

c: \(=\dfrac{x^2+x-x^2+x+2}{\left(x-1\right)\left(x+1\right)}=\dfrac{2}{x-1}\)

a) \(\dfrac{x^2+xy}{x^2-y^2}=\dfrac{x\left(x+y\right)}{\left(x+y\right)\left(x-y\right)}=\dfrac{x}{x-y}\)

b)\(\dfrac{x}{x-1}-\dfrac{x}{x+1}+\dfrac{2}{x^2-1}=\dfrac{x\left(x+1\right)-x\left(x-1\right)+2}{\left(x-1\right)\left(x+1\right)}=\dfrac{2\left(x+1\right)}{\left(x-1\right)\left(x+1\right)}=\dfrac{2}{x-1}\)

b) x^2+xy/x^2-y^2= x(x+y) /(x+y) (x-y) =x/x-y

c) =2/x-1

Đây bạn nhé!

\(=\dfrac{x^2+2x-x^2+4x-4+6-5x}{\left(x-2\right)\left(x+2\right)}=\dfrac{x+2}{\left(x-2\right)\left(x+2\right)}=\dfrac{1}{x-2}\)

\(C=\sqrt{3}-\sqrt{2}+\sqrt{\left(2-\sqrt{3}\right)^2}+\sqrt{2}\\ C=\sqrt{3}+2-\sqrt{3}=2\)

3/15 chia cả mẫu cả tử cho 3 được 1/5+2/5=3/5 nhé

\(=\left(\dfrac{1}{2}+\dfrac{1}{2}\right)-\left(\dfrac{5}{41}+\dfrac{36}{41}\right)=1-1=0\)

1/2-5/41+1/2-39/41

=(1/2+1/2)-(5/41+39/41)

=1-1

=2

\(a,2x^2+6x=2x\left(x+3\right)\\ b,x^2+2xy+y^2-9z^2\\ =\left(x^2+2xy+y^2\right)-\left(3z\right)^2\\ =\left(x+y\right)^2-\left(3z\right)^2\\ =\left(x+y-3z\right)\left(x+y+3z\right)\\ b,x^3-2x^2+x\\ =x\left(x^2+2x+1\right)\\ =x\left(x+1\right)^2\\ d,x^2-2x-15=x^2-5x+3x-15\\ =x\left(x-5\right)+3\left(x-5\right)\\ =\left(x+3\right)\left(x-5\right)\)

a) 2x² + 6x

=2x (x+3)

b) x² + 2xy +y²- 9z²

(x² + 2xy +y2)- 9z²

(x + y)² - (3z)²

(x+y-3z) (x+y+3z)