A = 1.2.3+2³.1.2.3+3³.1.2.3+4³.1.2.3 /3.4.5+2³.3.4.5+3³.3.4.5+4³.3.4.5

   =1.2.3 (1+2³+3³+4³)/3.4.5 (1+2³+3³+4³)

   =1.2.3/3.4.5

   =1/10

B=10101 ( 15/333333 + 2/333333 +57 / 333333 )

B=10101 . 74 /333333

  =74/33

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kh quá

\(B=10101\cdot\left(\dfrac{5}{111111}+\dfrac{5}{222222}-\dfrac{4}{111111}\right)\)

\(=10101\cdot\left(\dfrac{2}{222222}+\dfrac{5}{222222}\right)\)

\(=10101\cdot\dfrac{1}{31746}=\dfrac{7}{22}\)

A=7/22

Ai thấy đúng thì k cho mik nha

A=6/11 bạn ơi

\(A=10101.\left(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{3.7.11.13.37}\right)\)

\(A=10101.\left(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{111111}\right)\)

\(A=10101.\left(\frac{10}{222222}+\frac{5}{222222}-\frac{8}{222222}\right)\)

\(A=10101.\left(\frac{7}{222222}\right)\)

\(A=\frac{70707}{222222}\)

\(A=\frac{7}{22}\)

Vậy A = \(\frac{7}{22}\)

Chúc bạn học tốt!

10101 . \(\left(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{3.7.11.13.37}\right)\)

= 10101 . \(\left(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{111111}\right)\)

= 10101 . \(\frac{7}{222222}\)

= \(\frac{7}{22}\)

Lời giải:

Ta có:

\(A=10101.\left(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{3.7.11.13.37}\right)\)

\(=10101.\left(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{111111}\right)\)

\(=10101.\left(\frac{10}{222222}+\frac{5}{222222}-\frac{8}{222222}\right)\)

\(=10101.\left(\frac{10+5-8}{222222}\right)\)

\(=10101.\frac{7}{222222}\)

\(=\frac{7.10101}{22.10101}=\frac{7}{22}\)

Chúc bạn học tốt!Tick cho mình nhé!

\(10101.\left(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{3.7.11.13.37}\right)\)

\(=10101.\left(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{111111}\right)\)

\(=10101.\frac{7}{222222}\)

\(=\frac{7}{22}.\)

Chúc bạn học tốt!

=\(10101.\left(\frac{5}{111111}+\frac{5}{222222}.\frac{4}{111111}\right)\)

=\(10101.\left(\frac{5}{111111}+\frac{20}{24691308642}\right)\)

=\(10101.\frac{1111130}{24691308642}\)

=0,4545........