\(a,=\dfrac{5}{6}+\dfrac{6}{7}\\ =\dfrac{35}{42}+\dfrac{36}{42}=\dfrac{71}{42}\\ b,=\dfrac{5}{6}+\dfrac{4}{9}\\ =\dfrac{15}{18}+\dfrac{8}{18}=\dfrac{23}{18}\)

a) \(\dfrac{9}{5}+\dfrac{9}{5}:\dfrac{9}{5}\)

\(=\dfrac{9}{5}+\dfrac{9}{5}\times\dfrac{5}{9}\)

\(=\dfrac{9}{5}+1\)

\(=\dfrac{14}{5}\)

b) \(\dfrac{7}{5}-\dfrac{1}{2}\times\dfrac{1}{3}\)

\(=\dfrac{7}{5}-\dfrac{1}{6}\)

\(=\dfrac{42}{30}-\dfrac{5}{30}\)

\(=\dfrac{37}{30}\)

\(a,\dfrac{9}{5}+\dfrac{9}{5}:\dfrac{9}{5}\)

\(=\dfrac{9}{5}+\dfrac{9}{5}\times\dfrac{5}{9}\)

\(=\dfrac{9}{5}+1\)

\(=\dfrac{9}{5}+\dfrac{5}{5}\)

\(=\dfrac{14}{5}\)

\(b,\dfrac{7}{5}-\dfrac{1}{2}\times\dfrac{1}{3}\)

\(=\dfrac{7}{5}-\dfrac{1}{6}\)

\(=\dfrac{42}{30}-\dfrac{5}{30}\)

\(=\dfrac{37}{30}\)

|(5/8-5/14)+(3/8-9/14)|:4/7

=|(5/8+3/8)+(-5/14-9/14)|:4/7

=|1+(-1)|:4/7

=0

`A = ( 5 / 8 - 5 / 14 ) : 4 / 7 + ( 3 / 8 - 9 / 14 ) : 4 / 7`

`A = ( 5 / 8 - 5 / 14 + 3 / 8 - 9 / 14 ) : 4 / 7`

`A = [ ( 5 / 8 + 3 / 8 ) - ( 5 / 14 + 9 / 14 ) ] . 7 / 4`

`A = ( 8 / 8 - 14 / 14 ) . 7 / 4`

`A = ( 1 - 1 ) . 7 / 4 = 0 . 7 / 4 = 0`

\(A=\left(\dfrac{5}{8}-\dfrac{5}{14}\right)\times\dfrac{7}{4}+\left(\dfrac{3}{8}-\dfrac{9}{14}\right)\times\dfrac{7}{4}\)

\(A=\left(\dfrac{5}{8}-\dfrac{5}{14}+\dfrac{3}{8}-\dfrac{9}{14}\right)\times\dfrac{7}{4}\)

\(A=\left(1-1\right)\times\dfrac{7}{4}=0\)

Sửa đề: A=7/12-9/20+11/30-13/42+15/56

A=1/3+1/4-1/4-1/5+1/5+1/6-1/6-1/7+1/7+1/8

=1/3+1/8=11/24

a) 78 060 : (10 – 7) + 300 045

= 78 060 : 3 + 300 045

= 26 020 + 300 045

= 326 065

b) 26 000 + 9 015 × 6

= 26 000 + 54 090

= 80 090

=(1-2-3+4)+(5-6-7+8)+...+(2017-2018-2019+2020)+2021-2022-2023

=0+0+...+0-1-2023

=-2024

Bằng 2024

\(A=\dfrac{7}{3}+\dfrac{5}{7}+\dfrac{2}{3}-\dfrac{7}{12}+\dfrac{5}{2}=3+\dfrac{221}{84}=\dfrac{473}{84}\)

a) (-12). (7 - 72) - 25. (55 - 43) 

= (-12). (- 65) - 25. 12 

= 12. 65 – 12. 25

= 12. (65 - 25) 

= 12. 40 

= 480

b) (39 - 19) : (- 2) + (34 - 22). 5 

= 20 : (- 2) + 12. 5 

= - 10 + 60

= 60 - 10 

= 50.

fffff

a) \(\dfrac{5}{3}+\dfrac{4}{9}:\dfrac{1}{2}=\dfrac{5}{3}+\dfrac{4}{9}\times2=\dfrac{5}{3}+\dfrac{8}{9}=\dfrac{23}{9}\)

b) \(\dfrac{11}{10}-\dfrac{2}{5}:\dfrac{2}{3}=\dfrac{11}{10}-\dfrac{2}{5}\times\dfrac{3}{2}=\dfrac{11}{10}-\dfrac{3}{5}=\dfrac{11}{10}-\dfrac{6}{10}=\dfrac{5}{10}=\dfrac{1}{2}\)

Câu 4 

\(\dfrac{12\times15\times20}{10\times16\times25}=\dfrac{3\times4\times3\times5\times4\times5}{5\times2\times4\times4\times5\times5}=\dfrac{3\times3}{5\times2}=\dfrac{9}{10}\)

Câu 3:

\(a.\dfrac{5}{3}+\dfrac{4}{9}:\dfrac{1}{2}=\dfrac{5}{3}+\dfrac{8}{9}=\dfrac{15}{9}+\dfrac{8}{9}=\dfrac{23}{9}\)

\(b.\dfrac{11}{10}-\dfrac{2}{5}:\dfrac{2}{3}=\dfrac{11}{10}-\dfrac{3}{5}=\dfrac{11}{10}-\dfrac{6}{10}=\dfrac{5}{10}=\dfrac{1}{2}\)

Câu 4:

\(\dfrac{12\times15\times20}{10\times16\times25}=\dfrac{3\times3\times1}{2\times1\times5}=\dfrac{9}{10}\)

a. 15,36 x 4 + 1,98 x 5

=    61,44   +   9,9

=    71,34

( 15,36 + 1,98) x7

=  17,34  x 7

=   121,38

b. 15,36 x 4 - 1,98 x 5

=   61,44 -  9.9

=   51,54

( 15,36 - 1,98) x 7

= 13,38 x 7

= 93,66

a. 15,36 x 4 + 1,98 x 5

=    61,44   +   9,9

=    71,34

( 15,36 + 1,98) x7

=  17,34  x 7

=   121,38

b. 15,36 x 4 - 1,98 x 5

=   61,44 -  9.9

=   51,54

( 15,36 - 1,98) x 7

= 13,38 x 7

= 93,66

a. 15,36 x 4 + 1,98 x 5

=    61,44   +   9,9

=    71,34

( 15,36 + 1,98) x7

=  17,34  x 7

=   121,38

b. 15,36 x 4 - 1,98 x 5

=   61,44 -  9.9

=   51,54

( 15,36 - 1,98) x 7

= 13,38 x 7

= 93,66