Tính
1+2-3-4+5+6-7-8+9+..................-2012+2013+2014
Giúp mik với ,mai phải nộp rồi
Tuyển Cộng tác viên Hoc24 nhiệm kì 26 tại đây: https://forms.gle/dK3zGK3LHFrgvTkJ6
1 + 2-3-4 + 5 + 6-7-8 + 9 +............. -2012 +2013 + 2014=?
Giúp mk nha mn. Mai mk hok roy.
=(0+1+2-3)+(-4+5+6-7)+(-8+9+10-11)+....+(-2010+2011+2012-2013)+2014
=0+0+0+...+0+2014=2014
Tính nhanh : B = 1 + 2 + ( -3 ) + ( -4 ) + 5 + 6 + ( -7 ) + ( -8 ) +... + 2013 + 2014 + ( -2015 ) + ( -2016 ) ( Giúp mình nhanh với , mai phải đi học rồi :'( )
câu 1:Thực hiện phép tính:
a, A= -6.(-8+5):3-7.(-2) b, B= 4.5^2+24.(-5) +9
câu 2: tìm x
a, -8.|x|=(-4)^3
b,(4,5-2x).1 4/7= 11/4
GIÚP VS MAI MIK PHẢI NỘP RỒI
A = -6 . ( -8 + 5 ) : 3 - 7 . ( -2 )
A = -6 . -3 : 3 - ( -14 )
A = 6 - ( -14 )
A = 20
Chứng minh rằng:
A:1\5-1\5^2+1\5^3-...+1\5^2012-1\5^2013
A<5\26
Giúp mik với mai min nộp rồi nhé
Thanks bn nha
\(A=\frac{1}{5}-\frac{1}{5^2}+\frac{1}{5^3}-...+\frac{1}{5^{2012}}-\frac{1}{5^{2013}}\)
\(5A=1-\frac{1}{5}+\frac{1}{5^2}-...+\frac{1}{5^{2011}}-\frac{1}{5^{2012}}\)
\(5A+A=1-\frac{1}{5^{2013}}\)
\(6A=1-\frac{1}{5^{2013}}\)
\(A=\frac{1-\frac{1}{5^{2013}}}{6}\)
m,1+3+(-5)+(-7)+9+11+...+97+99
n,(-2)+(-4)+6+8+(-10)+(-12)+...+(-98)+(-100)
p,1+(-2)+(-3)+4+5+(-6)+(-7)+8+9+...+(-2015)+(-2016)
Đấy là nhóm vào
Giúp mìn nhé mai mình phải nộp rồi
Nhanh=tick
1+2-3-4-5+6+7-8-9-10+11+12-13-14-15+...+2011+2012-2013-2014-2015+2016+2017-2018-2019-2020 giup mik v
Lời giải:
$A=(1+2-3-4-5)+(6+7-8-9-10)+(11+12-13-14-15)+....+(2011+2012-2013-2014-2015)+(2016+2017-2018-2019-2020)$
$=(-9)+(-14)+(-19)+....+(-2019)+(-2024)$
$=-(9+14+19+...+2019+2024)$
Số số hạng: $(2024-9):5+1=404$
$A=-(2024+9).404:2=-410666$
mong các bạn giúp mik rồi mik tik cho
e) 17/5 : X = 34/5 : 4/3
f) X : 4/5= 25/8 : 5/4
g) (X x 0,25 + 2012) x 2013 = (50 + 2012) x 2013
h) (X - 1/2) x 5/3 = 7/4 - 1/
e: \(\dfrac{17}{5}:x=\dfrac{34}{5}:\dfrac{4}{3}=\dfrac{34}{5}\cdot\dfrac{3}{4}=\dfrac{102}{20}=\dfrac{51}{10}\)
\(\Leftrightarrow x=\dfrac{17}{5}:\dfrac{51}{10}=\dfrac{17}{5}\cdot\dfrac{10}{51}=\dfrac{10}{5}\cdot\dfrac{17}{51}=2\cdot\dfrac{1}{3}=\dfrac{2}{3}\)
f: \(x:\dfrac{4}{5}=\dfrac{25}{8}:\dfrac{5}{4}=\dfrac{25}{8}\cdot\dfrac{4}{5}=\dfrac{100}{40}=\dfrac{5}{2}\)
\(\Leftrightarrow x=\dfrac{5}{2}\cdot\dfrac{4}{5}=\dfrac{4}{2}=2\)
g: \(\left(0.25x+2012\right)\cdot2013=\left(50+2012\right)\cdot2013\)
\(\Leftrightarrow0.25x+2012=50+2012\)
\(\Leftrightarrow0.25x=50\)
hay x=200
h: \(\left(x-\dfrac{1}{2}\right)\cdot\dfrac{5}{3}=\dfrac{7}{4}-1=\dfrac{3}{4}\)
\(\Leftrightarrow x-\dfrac{1}{2}=\dfrac{3}{4}:\dfrac{5}{3}=\dfrac{9}{20}\)
\(\Leftrightarrow x=\dfrac{9}{20}+\dfrac{1}{2}=\dfrac{9}{20}+\dfrac{10}{20}=\dfrac{19}{20}\)
A= 1+ 2- 3- 4+ 5+ 6- 7- 8+ 9+ ... -2012+ 2013+ 2014
A=1+2-3-4+5+6-7-8+9+...-2012+2013+2014
A=1+(2-3-4+5)+(6-7-8+9)+...+(2010-2011-2012+2013)+2014
A=1+0+0+...+0+2014
A=2015
1 + 2 - 3 - 4 + 5 + 6 - 7 - 8 + 9 + ... - 2012 + 2013 + 2014 ( có 2014 số, 2014 chia 4 dư 2)
= 1 + ( 2 - 3 - 4 + 5) + ( 6 - 7 - 8 + 9) + ... + ( 2010 - 2011 - 2012 + 2013) + 2014
= 1 + 0 + 0 + ... + 0 + 2014
= 2015 + 0 = 2015
A = 1 + 2 - 3 - 4 + 5 + 6 - 7 - 8 + 9 + ... - 2012 + 2013 + 2014
= 1 + 2014 + (2 - 3 - 4 + 5) + (6 - 7 - 8 + 9) + ... + (2010 - 2011 - 2012 + 2013) = 2015 + 0 + 0 + ... + 0 = 2015
Bài 1:Tính
1) (1/2)^3 (3/2)^2
2) (2/3)^3 (3/2)^5
3) (5/4)^5 (4/5)^7
4) (-5/6)^6 (6/5)^8
5)(-4/3)^3 (9/16)^5
6) (1/3)^4 (-9/2)^6
7)(-4/9)^3 (-27/20)^4
8) (0,2)^4 . 5^6
9) (-4/3)^3 (9/16)^5
10) (-0,2)^3 .(-5)^5
11) (-4)^4 .(0,25)^6
12) $^2 . (0,2)^3
13) (0,5)^2 . 2^4
14) (-0,5)^3 .2^6
15) (-0,5)^5 .(-2)^10
16) (0,125)^2 .8^4
17) (0,125)^5 . (-8)^4
18) (-0,125)^7 . 8^10
19) (-0,1)^4 . 10^7
20) (0,1)^5 . (-10)^10
Giúp mình với ạ,mình cảm ơn ạ
1: =1/8*9/4=9/32
2: =8/27*243/32=9/4
3: =(5/4*4/5)^5*(4/5)^2=16/25
4: \(=\left(-\dfrac{5}{6}\cdot\dfrac{6}{5}\right)^2\cdot\left(\dfrac{6}{5}\right)^2=\dfrac{36}{25}\)
5: \(=\left(-\dfrac{4}{3}\right)^3\cdot\left(\dfrac{3}{4}\right)^{10}=\left(-1\right)\left(\dfrac{3}{4}\right)^7=-\left(\dfrac{3}{4}\right)^7\)
6: \(=\left(\dfrac{1}{3}\cdot\dfrac{-9}{2}\right)^4\left(-\dfrac{9}{2}\right)^2=\left(-\dfrac{3}{2}\right)^4\cdot\dfrac{81}{4}=\dfrac{9}{4}\cdot\dfrac{81}{4}=\dfrac{729}{16}\)
8: =(0,2*5)^4*5^2=25
10: =-0,5^5*2^10
=-0,5^5*2^5*2^5
=-32
13: =(0,5*2)^2*2^2=4