25/24 x 27/5 x 2 x34 x36
25 / 24x 27 /5 x 2 x34 /9 x 36 /17
\(\dfrac{25}{24}\times\dfrac{27}{5}\times2\times\dfrac{34}{9}\times\dfrac{36}{17}\)
\(=(\dfrac{25}{24}\times\dfrac{54}{5})\times\left(\dfrac{34}{9}\times\dfrac{36}{17}\right)\)
\(=\dfrac{45}{4}\times2\times4\)
\(=90\)
= 26/24 x 27/5 x2x34/9 x 2x2/17
= 13/12 x 27/5 x2 x34/9 x2 x 2/17
= 13/12 x2x2 x27/5 x 34/9 x2/17
= 13/3 x27/5 x 4/9
= 117/5x4/9
= 52/5
x-2/27+x-3/26+x-4/25+x-5/24+x-44/5
bài 1: tìm x thuộc Z
a) 10-x-5=(-5)-7-11
b) (x-3)-(x+17-24)-(25-x)=24-(-30)
c) (7-9x)-(2x-4)=-(5.x+35)-(-27)-(+25)
a: =>5-x=-23
=>x=5+23=28
b: =>x-3-x+7-25+x=54
=>x-21=54
=>x=75
c: =>7-9x-2x+4=-5x-35+27-25=-5x-37
=>-11x+3=-5x-37
=>-6x=-40
=>x=20/3
a) \(10-x-5=\left(-5\right)-7-11\)
\(\Rightarrow5-x=-23\)
\(\Rightarrow x=5+23\)
\(\Rightarrow x=28\)
b) \(\left(x-3\right)-\left(x+17-24\right)-\left(25-x\right)=24-\left(-30\right)\)
\(\Rightarrow x-3-x-17+24-25+x=54\)
\(\Rightarrow x-21=54\)
\(\Rightarrow x=54+21\)
\(\Rightarrow x=75\)
c) \(\left(7-9x\right)-\left(2x-4\right)=-\left(5x+35\right)-\left(-27\right)-25\)
\(\Rightarrow7-9x-2x+4=-5x-35+27-25\)
\(\Rightarrow11-11x=-5x-33\)
\(\Rightarrow-11x+5x=-33-11\)
\(\Rightarrow-6x=-22\)
\(\Rightarrow x=\dfrac{22}{6}=\dfrac{11}{3}\)
a.
10-x-5 = (-5) - 7 -11
=>5-x = 0
=>x=5
b
(x-3) - (x+17-24) - (25-x) = 24 - (-30)
=>x - 3 - x - 17 + 24 - 25 - x = 24 + 30
=>-x - 21 = 54
=>-x = 75
=>x = -75
c
(7 - 9x) - (2x - 4) = - (5x + 35) - (-27) - 25
=>7-9x - 2x + 4 = -5x - 35 + 27 - 35
=>11 - 11x + 5x = -43
=>16x = 11 + 43
=>16x = 54
=>x=4
Tìm x biết
a) (x-1/2)^2=4
b) 10/1/2-(x+1/3)^2=1/1/2
c) (x-1/5)^2+17/25=26/25
d) 1/5/27+(3x-7/9)^3=24/27
a) (x - 1/2)2 = 4
<=> (x - 1/2)2 = 22
<=> x - 1/2 = -2; 2
<=> x - 1/2 = 2 hoặc x - 1/2 = -2
x = 2 + 1/2 x = -2 + 1/2
x = 5/2 x = -3/2
=> x = 5/2 hoặc x = -3/2
b) 10/1/2 - (x + 1/3)2 = 1/1/2
<=> -(x + 1/3)2 = 1/1/2 - 10/1/2
<=> -(x + 1/3)2 = 1/2 - 5
<=> -(x + 1/3)2 = -5.2 + 1/2
<=> -(x + 1/3)2 = -9/2
<=> (x + 1/3)2 = 9/2
<=> x + 1/3 = \(\sqrt{\frac{9}{2}}\) hoặc x + 1/3 = \(-\sqrt{\frac{9}{2}}\)
x = \(\frac{3\sqrt{2}}{2}\) - 1/3 x = \(-\frac{3\sqrt{2}}{2}\) -1/3
=> x = \(\frac{3\sqrt{2}}{2}\) - 1/3 hoặc x = \(-\frac{3\sqrt{2}}{2}\) -1/3
c) (x - 1/5)2 + 17/25 = 26/25
<=> (x - 1/5)2 = 26/25 - 17/25
<=> (x - 1/5)2 = (3/5)2
<=> x - 1/5 = -3/5; 3/5
<=> x - 1/5 = 3/5 hoặc x - 1/5 = -3/5
x = 3/5 + 1/5 x = -3/5 + 1/5
x = 4/5 x = -2/5
=> x = 4/5 hoặc x = -2/5
1, 24+3.(5-x)=27
x = ?
2, 2.(x-5)-17=25
x = ?
24 + 3 . ( 5 - x ) = 27
3 . ( 5 - x ) = 27 - 24
3 . ( 5 - x ) = 3
5 - x = 3 : 3
5 - x = 1
x = 5 - 1
x = 4
Vậy x = 4
2 . ( x - 5 ) - 17 = 25
2 . ( x - 5 ) = 25 + 17
2 . ( x - 5 ) = 42
x - 5 = 42 : 2
x - 5 = 21
x = 21 + 5
x = 26
Vậy x = 26
24 + 3 x ( 5 - X ) = 27
27 x ( 5 - X ) = 27
5 - X = 27 : 27
5 - X = 1
X = 5 - 1
X = 4
2 x ( X - 5 ) - 17 = 25
2 x ( X - 5 ) = 27 + 15
2 x ( X - 5 ) = 42
X - 5 = 42 : 2
X - 5 = 21
X = 21 + 5
X = 26
Tìm X
a, 17/2 - |2x - 3/4| = -7/4
b, (x + 1/5)² + 17/25= 26/25
c, -1 5/27 - (3x -7/9)³ = -24/27
Phần c là -1 và 5/27 nhé (hỗn số)
`Answer:`
a. \(\frac{17}{2}-\left|2x-\frac{3}{4}\right|=-\frac{7}{4}\)
\(\Leftrightarrow\left|2x-\frac{3}{4}\right|=\frac{17}{2}+\frac{7}{4}\)
\(\Leftrightarrow\left|2x-\frac{3}{4}\right|=\frac{41}{4}\)
\(\Leftrightarrow\orbr{\begin{cases}2x-\frac{3}{4}=\frac{41}{4}\\2x-\frac{3}{4}=-\frac{41}{4}\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}2x=\frac{41}{4}+\frac{3}{4}\\2x=-\frac{41}{4}+\frac{3}{4}\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}2x=11\\2x=-\frac{19}{2}\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=11:2\\x=-\frac{19}{2}:2\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=\frac{11}{2}\\x=-\frac{19}{4}\end{cases}}\)
b. \(\left(x+\frac{1}{5}\right)^2+\frac{17}{25}=\frac{26}{25}\)
\(\Leftrightarrow\left(x+\frac{1}{5}\right)^2=\frac{26}{25}-\frac{17}{25}\)
\(\Leftrightarrow\left(x+\frac{1}{5}\right)^2=\frac{9}{25}\)
\(\Leftrightarrow\left(x+\frac{1}{5}\right)=\left(\frac{3}{5}\right)^2\)
\(\Leftrightarrow\orbr{\begin{cases}x+\frac{1}{5}=\frac{3}{5}\\x+\frac{1}{5}=-\frac{3}{5}\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=\frac{3}{5}-\frac{1}{5}\\x=-\frac{3}{5}-\frac{1}{5}\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=\frac{2}{5}\\x=-\frac{4}{5}\end{cases}}\)
c. \(-1\frac{5}{27}-\left(3x-\frac{7}{9}\right)^3=-\frac{24}{27}\)
\(\Leftrightarrow-\frac{32}{27}-\left(3x-\frac{7}{9}\right)^3=-\frac{24}{27}\)
\(\Leftrightarrow\left(3x-\frac{7}{9}\right)^3=-\frac{32}{27}-\left(-\frac{24}{27}\right)\)
\(\Leftrightarrow\left(3x-\frac{7}{9}\right)^3=-\frac{8}{27}\)
\(\Leftrightarrow\left(3x-\frac{7}{9}\right)^3=\left(-\frac{2}{3}\right)^3\)
\(\Leftrightarrow3x-\frac{7}{9}=-\frac{2}{3}\)
\(\Leftrightarrow3x=-\frac{2}{3}+\frac{7}{9}\)
\(\Leftrightarrow3x=\frac{1}{9}\)
\(\Leftrightarrow x=\frac{1}{9}:3\)
\(\Leftrightarrow x=\frac{1}{27}\)
Tìm x
17/25 + ( x + 1/5 ) 2 = 26/25
-92/27 - ( 3x - 7/9 )3 = 24/27
x + 1/5 = 26/25 - 17/25 x = 9/25 - 1/5 x = 4/5
1.Tìm x
a)25.(x-4)=0
b)2007.(3.x-12)=0
c)24+3.(5-x)=27
d)20-(x+4)=27
e)2.(x-5)-17=25
Lưu ý:dấu chấm là dấu nhân
Theo mình kết quả là
a, X là 4 b, X = 4 c, X = 5 d, X = 3 e, X = 16
Đúng thì k nhé .
THANKS