Trả lời:

\(B=\frac{0,75-30\%+\frac{3}{7}+\frac{3}{13}}{2,75-2,2+1\frac{4}{7}+3\frac{2}{3}}\)

\(B=\frac{\frac{3}{4}-\frac{3}{10}+\frac{3}{7}+\frac{3}{13}}{\frac{11}{4}-\frac{11}{5}+\frac{11}{7}+\frac{11}{3}}\)

\(B=\frac{2019}{1820}\div\frac{2431}{420}\)

\(B=\frac{2019}{1820}\times\frac{420}{2431}\)

\(B=\frac{6057}{31603}\)

\(\frac{1+0,6-\frac{3}{7}}{\frac{8}{3}+\frac{8}{5}-\frac{8}{7}}=\frac{\frac{3}{3}+\frac{3}{5}-\frac{3}{7}}{\frac{8}{3}+\frac{8}{5}-\frac{8}{7}}=\frac{3.\left(\frac{1}{3}+\frac{1}{5}-\frac{1}{7}\right)}{8.\left(\frac{1}{3}+\frac{1}{5}-\frac{1}{7}\right)}=\frac{3.1}{8.1}=\frac{3}{8}\)

\(\frac{\frac{1}{3}+0,25-\frac{1}{5}+0,125}{\frac{7}{6}+\frac{7}{8}-0,7+\frac{7}{16}}=\frac{\frac{1}{3}+\frac{1}{4}-\frac{1}{5}+\frac{1}{8}}{\frac{7}{6}+\frac{7}{8}-\frac{7}{10}+\frac{7}{16}}=\frac{1.\left(\frac{1}{3}+\frac{1}{4}-\frac{1}{5}+\frac{1}{8}\right)}{7.\left(\frac{1}{3}+\frac{1}{4}-\frac{1}{5}+\frac{1}{8}\right)}=\frac{1.1}{7.1}=\frac{1}{7}\)

=>\(\frac{3}{8}-\frac{1}{7}=\frac{13}{56}\)

Mk đg cần gấp các bn giúp mk nha

Cảm ơn bạn nha,  Nguyễn Thành An

\(3x+\frac{3}{9}+\frac{5}{8}+1=6\)

\(\Rightarrow3x+\frac{47}{24}=6\)

\(\Rightarrow3x=\frac{97}{24}\)

\(\Rightarrow x=\frac{97}{72}\)

\(x+\frac{3}{9}+x+\frac{5}{8}+x+\frac{7}{7}=6\)

\(3x=6-\frac{3}{9}-\frac{7}{7}-\frac{5}{8}\)

\(3x=\frac{97}{24}\)

\(x=\frac{97}{24}\div3\)

\(x=\frac{97}{24}\times\frac{1}{3}\)

\(x=\frac{97}{72}\)

\(x+\frac{3}{9}+x+\frac{5}{8}+x+\frac{7}{7}=6\)

\(x+\frac{1}{3}+x+\frac{5}{8}+x+1=6\)

\(x+\left(\frac{1}{3}+\frac{5}{8}+1\right)=6\)

\(x+\left(\frac{23}{24}+1\right)=6\)

\(x+\frac{47}{24}=6\)

\(x=6-\frac{47}{24}\)

\(x=\frac{97}{24}\)

(x+3)/7 thì bạn cộng thêm 7/7 vào, tương tự thì cộng 8/7, 9/7,.. Đén đây thì quy đồng  rồi rút gọn. tự nghĩ nhé

Ta có : \(\frac{x+3}{7}+\frac{x+3}{8}+\frac{x+3}{9}+\frac{x+3}{10}=\frac{x+3}{11}\)

\(\Leftrightarrow\frac{x+3}{7}+\frac{x+3}{8}+\frac{x+3}{9}+\frac{x+3}{10}-\frac{x+3}{11}=0\)

\(\Leftrightarrow\left(x+3\right)\left(\frac{1}{7}+\frac{1}{8}+\frac{1}{9}+\frac{1}{10}-\frac{1}{11}\right)=0\)

Mà : \(\left(\frac{1}{7}+\frac{1}{8}+\frac{1}{9}+\frac{1}{10}-\frac{1}{11}\right)\ne0\)

Nên : x + 3 = 0 

=> x = -3 

\(\frac{x+3}{7}+\frac{x+3}{8}+\frac{x+3}{9}+\frac{x+3}{10}=\frac{x+3}{11}\)

\(\Leftrightarrow\left(x+3\right)\left(\frac{1}{7}+\frac{1}{8}+\frac{1}{9}+\frac{1}{10}-\frac{1}{11}\right)=0\)( chuyển vế + đặt nhân tử chung )

\(\Leftrightarrow x+3=0\)(vì \(\frac{1}{7}+\frac{1}{8}+\frac{1}{9}+\frac{1}{10}-\frac{1}{11}\ne0\))

\(\Leftrightarrow x=-3\)

vậy phương trình có tập nghiệm là: S={-3}

a) \(\frac{1}{3}+\frac{3}{35}< \frac{x}{210}< \frac{7}{7}+\frac{3}{5}+\frac{1}{3}\)

\(\Rightarrow\frac{44}{105}< \frac{x}{210}< \frac{29}{15}\)

\(\Rightarrow\frac{88}{210}< \frac{x}{210}< \frac{406}{210}\)

\(\Rightarrow x\in\left\{89;90;91;...;405\right\}\)

b) \(\frac{5}{3}+-\frac{14}{3}< x< \frac{8}{5}+\frac{8}{10}\)

\(\Rightarrow-3< x< 2\frac{2}{5}\)

=> x thuộc {-2;-1;0;1;2} ( nếu x là số nguyên)

\(1,\)\(x-\frac{3}{5}=\frac{3}{35}-\frac{-7}{6}\)

        \(x-\frac{3}{5}=\frac{3}{35}+\frac{7}{6}\)

        \(x-\frac{3}{5}=\frac{263}{210}\)

                    \(x=\frac{263}{210}+\frac{3}{5}\)

                    \(x=\frac{389}{210}\)

        VẬY: \(x=\frac{389}{210}\)

\(\frac{x-1}{9}+\frac{x-2}{8}+\frac{x-3}{7}=\frac{x-4}{6}\)

\(\frac{x-1}{9}+\frac{x-2}{8}+\frac{x-3}{7}-\frac{x-4}{6}=0\)

\(\frac{56.\left(x-1\right)}{504}+\frac{63.\left(x-2\right)}{504}+\frac{72.\left(x-3\right)}{504}-\frac{84.\left(x-4\right)}{504}=0\)

\(\frac{56x-56}{504}+\frac{63x-126}{504}+\frac{72x-216}{504}-\frac{84x-336}{504}=0\)

\(\Rightarrow56x-56+63x-126+72x-216-84x+336=0\)

\(\Rightarrow107x-62=0\)

\(\Rightarrow107x=62\)

\(\Rightarrow x=\frac{62}{107}\)

vay \(x=\frac{62}{107}\)