Ta có: \(\frac{x}{3}=\frac{7}{8}\)
\(\Leftrightarrow x=\frac{7\cdot3}{8}=\frac{21}{8}\)
Vậy: \(x=\frac{21}{8}\)
\(\frac{x}{3}=\frac{7}{8}\)
=> 8x=7.3
=> 8x=21
=> x=\(\frac{21}{8}\)
bài 15 tìm x biết
a \(\frac{x}{4}-\frac{3}{7}+\frac{2}{5}=\frac{31}{140}\)
b\(\frac{5}{12}+\frac{5}{x}-\frac{1}{8}=\frac{1}{2}\)
c \(x+\frac{1}{9}-\frac{3}{5}=\frac{3}{6}\)
d \(\frac{3}{4}-x+\frac{6}{-11}=\frac{5}{6}\)
e \(x-\frac{1}{9}-\frac{3}{5}=\frac{3}{6}\)
mik cần gấp! giúp mình với
Bài 1:
\(\frac{7}{12}+\frac{-8}{15}\) ; \(\frac{5}{12}+\frac{-8}{15}\)
Bài 2: Tìm x
a)x - 23 =-56
b)2x - 36 = 24
c)x - \(\frac{4}{5}=\frac{3}{2}\)
d)x - 46 =123
e)2x - 25= -45
f)x -\(\frac{2}{3}=\frac{-7}{5}\)
mn ơi giúp em vs trước tối nay có nha mn
cảm ơn mn
tìm x
a, 2 . x \(\frac{-3}{4}\) = \(\frac{-5}{12}\)
b, \(\frac{2}{3}\) + \(\frac{1}{3}\) . x = 7
c, ( 4 . x + \(\frac{1}{8}\) ) = \(\frac{3}{10}\)
d, \(\frac{1}{3}\) . x - 5 = 1\(\frac{1}{2}\)
e, \(\frac{-2}{3}\) . x + \(\frac{1}{3}\) = \(\frac{-1}{2}\)
Tìm x: \(1\frac{1}{7}-\frac{5}{7}< \frac{x}{7}< 2\frac{1}{14}-1\frac{3}{14}\)
1/Tính:
\(\left(2-\frac{1}{5}\right).\left(\frac{-3}{15}+\frac{1}{3}\right)\)
2/Tìm x, biết:
\(\frac{x}{20}-\frac{2}{5}=\frac{4}{15}.\frac{-9}{8}\)
1: Tìm x
a) \(\frac{2}{3}x-\frac{2}{3}=\frac{5}{12}\)
b) \(\left(\frac{7}{2}+2x\right).2\frac{2}{3}=5\frac{1}{3}\)
Giúp mk với
Bài 1. tìm x
\(x-\frac{3}{5}=\frac{-7}{5}\)
bài 2
\(\frac{-2}{7}+\frac{5}{6}\)
gips em nha mn
mai e phải nộp r
Bài 1:Tìm x
a, \(2.x-\frac{1}{2}=\frac{5}{4}-\frac{1}{2}.x\)
b, \(\frac{3}{4}-\frac{5}{2}.x=2-3.x\)
c, \(\frac{3}{2}.\left(x-\frac{1}{3}\right)-2\left(x-\frac{1}{2}\right)=3\)
d, \(\frac{4}{3}.\left(x-\frac{3}{2}\right)-3.\left(\frac{1}{3}.x+1\right)=6\)
ai đó giúp mình trả lời câu hỏi này với
a)(1+\(\frac{3}{7}\)).x=1-1\(\frac{1}{7}\)
b)(4\(\frac{46}{65}+x\)).1\(\frac{1}{12}\)=5,75
