1x2x3...x9-1x2x3...x9-1x2x3...x7x8^2
a) (102+112+122) : (132+142)
b) 1x2x3....x9-1x2x3...x8-1x2x3....x7x82
1x2x3...9-1x2x3...8-1x2x3...82
Đáp số và cách làm
1x2+1x2x3+1x2x3x4+1x2x3x4x5+....+1x2x3...99x100
Đặt \(A=\dfrac{1}{1\cdot2\cdot3}+\dfrac{1}{2\cdot3\cdot4}+\dfrac{1}{3\cdot4\cdot5}+...+\dfrac{1}{98\cdot99\cdot100}\)
Ta có: \(A=\dfrac{1}{1\cdot2\cdot3}+\dfrac{1}{2\cdot3\cdot4}+\dfrac{1}{3\cdot4\cdot5}+...+\dfrac{1}{98\cdot99\cdot100}\)
\(\Leftrightarrow2A=\dfrac{2}{1\cdot2\cdot3}+\dfrac{2}{2\cdot3\cdot4}+\dfrac{2}{3\cdot4\cdot5}+...+\dfrac{2}{98\cdot99\cdot100}\)
\(\Leftrightarrow2A=-\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}-\dfrac{1}{2\cdot3}+\dfrac{1}{3\cdot4}-\dfrac{1}{3\cdot4}+\dfrac{1}{4\cdot5}-\dfrac{1}{4\cdot5}+...-\dfrac{1}{98\cdot99}+\dfrac{1}{99\cdot100}\)
\(\Leftrightarrow2A=-\dfrac{1}{2}+\dfrac{1}{99\cdot100}\)
\(\Leftrightarrow2A=\dfrac{-1}{2}+\dfrac{1}{9900}\)
\(\Leftrightarrow2A=\dfrac{-4950}{9900}+\dfrac{1}{9900}=\dfrac{-4949}{9900}\)
hay \(A=\dfrac{-4949}{19800}\)
1x2x3
1 x 2 x 3 = 6 nha bạn !
chúc bạn học tốt nhé !
hihi
1x2x3
1 x 2 x 3 = 2 x 3
= 6
k mik nha , mik k lại !!!!!!!!!!!!!!!!!!!!!!!!!!
1x2x3...x24x25
1x2x3+2x3x4+.........+2011x2012x2013=?
Gọi A = 1.2.3 + 2.3.4 + ................... + 2011.2012.2013
4A = 1.2.3.4 + 2.3.4.4 + ...................... + 2011.2012.2013.4
4A = 1.2.3.4 + 2.3.4.(5 - 1) +..................... + 2011.2012.2013.(2014 - 2010)
4A = 1.2.3.4 + 2.3.4.5 - 1.2.3.4 + .................... + 2011.2012.2013.2014 - 2010.2011.2012.2013
4A = 2011.2012.2013.2014
A = \(\frac{2011.2012.2013.2014}{4}=2011.503.2013.2014=..........\)
1x2x3+2x3x4+...+15x16x17
4xA=1x2x3x4+2x3x4x4+3x4x5x4+...+15x16x17x4
4xA=1x2x3x4+2x3x4x(5-1)+3x4x5x(6-2)+...+-15x16x17x(18-14)
4xA=1x2x3x4-1x2x3x4+2x3x4x5-2x3x4x5+3x4x5x6-...-14x15x16x17+15x16x17x18=15x16x17x18
=> A=15x4x17x18=18360