5.x+2.x=36
5 . \(x\) - 9 = 5 + 3 . \(x\)
(5\(x\) + 1)2 = \(\dfrac{36}{49}\)
2\(x - 1\) = 16
5.x - 9 = 5 + 3.x
5x - 3x = 5 + 9
2x = 14
x = 14 : 2
x = 7
--------------------
(5x + 1)² = 36/49
5x + 1 = 6/7 hoặc 5x + 1 = -6/7
*) 5x + 1 = 6/7
5x = 6/7 - 1
5x = -1/7
x = -1/7 : 5
x = -1/35
*) 5x + 1 = -6/7
5x = -6/7 - 1
5x = -13/7
x = -13/7 : 5
x = -13/35
Vậy x = -13/35; x = -1/35
--------------------
2ˣ⁻¹ = 16
2ˣ⁻¹ = 2⁴
x - 1 = 4
x = 4 + 1
x = 5
Tim x la phan tu cua N biet
a ) ( x - 5 ) x 4 = 36
b) ( 48 - x ) x 2 = 14
c) ( 2 x X - 3 ) x 5 = 4
d) 1 + 3 + 5 +..........+ X = 36
e) 1 + 2 + 3 + ...........+ X = 55 + 6 +.....+ 2X = 110
c, (2\(\times\) \(x\) - 3) \(\times\) 5 = 4
2 \(\times\) \(x\) - 3 = \(\dfrac{4}{5}\)
2 \(\times\) \(x\) = 0,8 + 3
2\(x\) = 3,8
\(x\) = \(3,8\) : 2
\(x\) = 1,9
d, 1 + 3 + 5 +....+\(x\) = 36
(\(x\) + 1)\(\times\) \(x\): 2 = 36
(\(x+1\)) \(\times\)\(x\) = 72
(\(x+1\))\(\times\)\(x\) = 8 x 9
\(x\) = 8
a) (X - 5) x 4 = 36
⇒ X - 5 = 36 : 4
⇒ X - 5 = 9
⇒ X = 9 + 5
⇒ X = 14
Vậy X = 14
b) (48 - X) x 2 = 14
⇒ 48 - X = 14 : 2
⇒ 48 - X = 7
⇒ X = 48 - 7
⇒ X = 41
Vậy X = 41
chứng minh B = 36 / 1 x 3 x 5 + 36 / 3 x 5 x7 + 36 / 5 x 7 x 9 + .... + 36 / 25 x 27 x29 < 3
\(B=\frac{36}{1.3.5}+\frac{36}{3.5.7}+\frac{36}{5.7.9}+...+\frac{36}{25.27.29}\)
\(=9.\left(\frac{4}{1.3.5}+\frac{4}{3.5.7}+\frac{4}{5.7.9}+...+\frac{4}{25.27.29}\right)\)
\(=9.\left(\frac{1}{1.3}-\frac{1}{3.5}+\frac{1}{3.5}-\frac{1}{5.7}+\frac{1}{5.7}-\frac{1}{7.9}+...+\frac{1}{25.27}-\frac{1}{27.29}\right)\)
\(=9.\left(\frac{1}{3}-\frac{1}{675}\right)\)
\(=9.\frac{224}{675}\)
\(=\frac{224}{75}\)
THIẾU
\(=\frac{224}{75}< \frac{225}{75}=3\)
Vậy \(B< 3\)
mấy bọn nguuuuuuuuuuuuuuuuuu
x-36:18+2.x+5=19+2.{x-1}
x-36/18+2.x+5=19+2.(x-1)
x-2+2x+5=19+2x-1.2
3x-2+5=2x-2+19
3x+3=2x+17
3x=2x+14
x=14
\(x-36:18+2.x+5=19+2\left(x-1\right)\)
\(\Leftrightarrow x+2x+5-\frac{36}{18}=19+2\left(x-1\right)\)
\(\Leftrightarrow3x+5-\frac{38}{16}=19+2\left(x-1\right)\)
\(\Leftrightarrow3x+5-2=19+2\left(x-1\right)\)
\(\Leftrightarrow3x+3=19+2\left(x-1\right)\)
\(\Leftrightarrow3x+3=2x+17\)
\(\Leftrightarrow3x=2x+17-3\)
\(\Leftrightarrow3x=2x+14\)
\(\Leftrightarrow3x=2x+14-2x\)
\(\Leftrightarrow x=14\)
=> x = 14
Tìm $x$, biết
$5 x\left(4 x^2-2 x+1\right)-2 x\left(10 x^2-5 x+2\right)=-36$.
\(20x^3-10x^2+5x-20x^3+10x^2-4x=0\)
\(\left(20x^3-20x^3\right)+\left(-10x^2+10x^2\right)+\left(5x-4x\right)=0\)
\(x=0\)
5x∙4x2-5x∙2x+5x∙1+-2x∙10x2--2x∙5x+-2x∙2=-36
20x3 - 10x2+ 5x + -20x3 - 10x2+ - 4x =-36
(20x3 -20x3)+(-10x2-10x2)+(5x-4x)=-36
x =-36
96-3(x+8)=42
15.5.(x-25)-225=0
250:x+15=25
36:(x-5)=2^2
[3.(70-x)+5]:2=46
\(a,96-3\left(x+8\right)=42\\ \Rightarrow3\left(x+8\right)=54\\ \Rightarrow x+8=18\\ \Rightarrow x=10.\\ b,15.5\left(x-25\right)-225=0\\ \Rightarrow75\left(x-25\right)-225=0\\ \Rightarrow75\left(x-25\right)=225\\ \Rightarrow x-25=3\\ \Rightarrow x=28.\\ c,250:x+15=25\\ \Rightarrow250:x=10\\ \Rightarrow x=25\\ d,36:\left(x-5\right)=2^2\\ \Rightarrow36:\left(x-5\right)=4\\ \Rightarrow x-5=9\\ \Rightarrow x=14.\\ e,\left[3.\left(70-x\right)+5\right]:2=46\\ \Rightarrow3.\left(70-x\right)+5=92\\ \Rightarrow3\left(70-x\right)=87\\ \Rightarrow70-x=29\\ \Rightarrow x=41.\)
a) X x 5 - X x 2 = 120 b) X x 13 - X x 10 = 240 c) 28 x X - X x 18 = 250
d) 5 x X - X x 2 = 36
a: =>x(5-2)=120
=>3x=120
=>x=40
b: =>x(13-10)=240
=>3x=240
=>x=80
c; =>10x=250
=>x=25
d: =>3x=36
=>x=12
12^2-2^2 x(518-x)=-36
2./x-5/=8
(x + 2)^2 + (2x -1)^2-(x - 3)^2 = 36
(2x -1)2 + (x + 3)2 - 5(x + 7)(x - 7) = 0
a: Ta có: \(\left(x+2\right)^2+\left(2x-1\right)^2-\left(x-3\right)^2=36\)
\(\Leftrightarrow x^2+4x+4+4x^2-4x+1-x^2+6x-9=36\)
\(\Leftrightarrow4x^2+6x-4-36=0\)
\(\Leftrightarrow4x^2+6x-40=0\)
\(\text{Δ}=6^2-4\cdot4\cdot\left(-40\right)=676\)
Vì Δ>0 nên phương trình có hai nghiệm phân biệt là:
\(\left\{{}\begin{matrix}x_1=\dfrac{-6-26}{8}=-4\\x_2=\dfrac{-6+26}{8}=\dfrac{5}{2}\end{matrix}\right.\)