Dễ

\(\frac{2}{5}+\frac{3}{5}\times\left(3x-3,7\right)=-\frac{53}{10}\)

\(\frac{3}{5}\times\left(3x-3,7\right)=-\frac{53}{10}-\frac{2}{5}\)

\(\frac{3}{5}\times\left(3x-3,7\right)=-\frac{57}{10}\)

\(\left(3x-3,7\right)=-\frac{57}{10}\div\frac{3}{5}\)

\(3x-3,7=-\frac{19}{2}\)

\(3x=-\frac{19}{2}+3,7\)

\(3x=-\frac{29}{5}\)

\(x=-\frac{29}{5}\div3\)

\(x=-\frac{29}{15}\)

Chúc bạn học tốt ^^

3/5.(3x-37/10)= -53/10-2/5

3/5.(3x-37/10)=-57/10

3x-37/10 =-57/10 : 3/5

3x-37/10=-19/2

3x =-19/2+37/10

3x =-29/15

x=-29/15 : 3

x=-29/15

x : 2/5 + 3/5 . (3x - 3,7) = -53/10

x. 2/5 + 3/5. 3x - 3/5. 37/10 = -53/10

x . 5/2 + 9/5.x - 111/50 = -53/10

x. ( 5/2 + 9/5) = -53/10 + 111/50

x . 43/10 = -73/25

x = -73/25 : 43/10

x = -146/215

\(\frac{2}{5}+\frac{3}{5}\times\left(3x-3,7\right)=-\frac{53}{10}\)

\(\frac{3}{5}\times\left(3x-3,7\right)=-\frac{53}{10}-\frac{2}{5}\)

\(\frac{3}{5}\times\left(3x-3,7\right)=\frac{-53-4}{10}\)

\(\frac{3}{5}\times\left(3x-3,7\right)=-\frac{57}{10}\)

\(3x-3,7=-\frac{57}{10}\div\frac{3}{5}\)

\(3x-3,7=-\frac{57}{10}\times\frac{5}{3}\)

\(3x-3,7=-\frac{19}{2}\)

\(3x=-\frac{19}{2}+\frac{37}{10}\)

\(3x=\frac{-95+37}{10}\)

\(3x=-\frac{58}{10}\)

\(x=-\frac{29}{5}\div3\)

\(x=-\frac{29}{5}\times\frac{1}{3}\)

\(x=-\frac{29}{15}\)

Chúc bạn học tốt

Mà ban nè -29/5 ở mo ra rứa bạn

\(-\frac{29}{5}\) là rút gọn của \(-\frac{58}{10}\) đó bn

\(\frac{2}{5}+\frac{3}{5}.\left(3x-3,7\right)=\frac{-53}{10}\)

\(\frac{3}{5}.\left(3x-3,7\right)=\frac{-57}{10}\)

\(\left(3x-3,7\right)=\frac{-19}{2}\)

\(3x=-5,8\)

\(x=\frac{-29}{15}\)

Vậy \(x=\frac{-29}{15}\)

Dễ quá mà bn ko biết làm à 

2/3x -3/2x=5/12

x(2/3-3/2)=5/12

x=5/12. (-5/6)

x=-25/72

a; \(\dfrac{2}{3}\)\(x\) - \(\dfrac{3}{2}\)\(x\) = \(\dfrac{5}{12}\)

    (\(\dfrac{2}{3}\) - \(\dfrac{3}{2}\))\(x\) = \(\dfrac{5}{12}\)

     - \(\dfrac{5}{6}\)\(x\) = \(\dfrac{5}{12}\)

     \(x\)   = \(\dfrac{5}{12}\) : (- \(\dfrac{5}{6}\))

     \(x=\) - \(\dfrac{1}{2}\)

Vậy \(x=-\dfrac{1}{2}\) 

b; \(\dfrac{2}{5}\) + \(\dfrac{3}{5}\).(3\(x\) - 3,7) = \(\dfrac{-53}{10}\)

           \(\dfrac{3}{5}\).(3\(x\) - 3,7) = \(\dfrac{-53}{10}\) - \(\dfrac{2}{5}\)

          \(\dfrac{3}{5}\).(3\(x\) - 3,7) = - \(\dfrac{57}{10}\)

         3\(x\) - 3,7 = - \(\dfrac{57}{10}\) : \(\dfrac{3}{5}\)

         3\(x\)   - 3,7 = - \(\dfrac{19}{2}\)

         3\(x\)         = - \(\dfrac{19}{2}\) + 3,7

          3\(x\)        = - \(\dfrac{29}{5}\)

           \(x\)         = - \(\dfrac{29}{5}\) : 3

           \(x\)        = - \(\dfrac{29}{15}\)

Vậy \(x\) \(\in\) - \(\dfrac{29}{15}\) 

c; \(\dfrac{7}{9}\) : (2 + \(\dfrac{3}{4}\)\(x\)) + \(\dfrac{5}{9}\) = \(\dfrac{23}{27}\)

    \(\dfrac{7}{9}\): (2 + \(\dfrac{3}{4}\)\(x\)) = \(\dfrac{23}{27}\) - \(\dfrac{5}{9}\)

     \(\dfrac{7}{9}\):(2 + \(\dfrac{3}{4}\)\(x\)) = \(\dfrac{8}{27}\)

      2 + \(\dfrac{3}{4}\)\(x\) = \(\dfrac{7}{9}\) : \(\dfrac{8}{27}\)

      2 + \(\dfrac{3}{4}\)\(x\) =  \(\dfrac{21}{8}\)

             \(\dfrac{3}{4}x\) = \(\dfrac{21}{8}\) - 2

             \(\dfrac{3}{4}\)\(x\) =  \(\dfrac{5}{8}\)

               \(x\) = \(\dfrac{5}{8}\) : \(\dfrac{3}{4}\)

              \(x\) =  \(\dfrac{5}{6}\)

Vậy \(x=\dfrac{5}{6}\)

a) \(x=-\frac{1}{2}\)

b) \(x=-\frac{29}{15}\)

c) \(x=\frac{5}{6}\)

**** cho mình nhé

a) -1/2

b) -29/15

c) 5/6

****

a) \(\frac{2}{5}+\frac{3}{5}.\left(3x-3,7\right)=\frac{-53}{10}\)

=> \(\frac{3}{5}.\left(3x-3,7\right)=\frac{-53}{10}-\frac{2}{5}\)

=> \(\frac{3}{5}.\left(3x-3,7\right)=\frac{-57}{10}\)

=> \(\left(3x-3,7\right)=\frac{-19}{5}\)

=>\(3x=\frac{-19}{5}+\frac{37}{10}\)

=>\(3x=\frac{-1}{10}\)

=>\(x=\frac{-1}{30}\)

Ko biết đúng hay sai!!?

a) \(\left(\dfrac{3}{5}+0,415-\dfrac{3}{200}\right).2\dfrac{2}{3}.0,25\)

\(=\left(\dfrac{3}{5}+\dfrac{83}{200}-\dfrac{3}{200}\right).\dfrac{8}{3}.\dfrac{1}{4}\)

\(=\left(\dfrac{3}{5}+\dfrac{2}{5}\right).\dfrac{2}{3}\)

\(=1.\dfrac{2}{3}=\dfrac{2}{3}\)

b) \(\dfrac{2}{5}+\dfrac{3}{5}.\left(3x-3,7\right)=\dfrac{-53}{10}\)

\(\dfrac{3}{5}.\left(3x-\dfrac{37}{10}\right)=\dfrac{-53}{10}-\dfrac{2}{5}=\dfrac{-57}{10}\)

\(3x-\dfrac{37}{10}=\dfrac{-57}{10}:\dfrac{3}{5}=\dfrac{-19}{2}\)

\(3x=\dfrac{-19}{2}+\dfrac{37}{10}=\dfrac{-29}{5}\)

\(x=\dfrac{-29}{5}:3=\dfrac{-29}{15}\)