a: =>31-x=60

=>x=-29

b: =>(x-140):35=280-270=10

=>x-140=350

=>x=490

c: =>(1900-2x):35=48

=>1900-2x=1680

=>2x=220

=>x=110

d: =>\(2^{2x-1}=2^9\cdot2=2^{11}\)

=>2x-1=11

=>x=6

e: =>(x+2)^5=4^5

=>x+2=4

=>x=2

f: =>3x-4=0 hoặc x-1=0

=>x=4/3 hoặc x=1

g: =>(2x-1)^2=49

=>2x-1=7 hoặc 2x-1=-7

=>x=-3 hoặc x=4

h: =>x(x+1)/2=78

=>x(x+1)=156

=>x=12

 m , Ta có : \(\left(1900-2.x\right):3-32=16\)

 \(\Leftrightarrow\frac{1900-2.x}{35}-32=16\)( Nhân hai vế với 35 ) 

 \(\Leftrightarrow1900-2.x-1120=560\)

  \(\Leftrightarrow780-2.x=560\)

 \(\Leftrightarrow-2.x=560-780\)

\(\Leftrightarrow\) \(-2.x=-220\)

 \(\Rightarrow x=110\)

Vậy x = 110

n, Ta có : \(720:\left[41-\left(2.x-5\right)\right]=2^3.5\)

             \(\Leftrightarrow720:\left(41-2.x+5\right)=8.5\)

              \(\Leftrightarrow720:\left(46-2.x\right)=40\)

              \(\Leftrightarrow\frac{720}{46-2.x}=40\)

              \(\Leftrightarrow\frac{720}{2.\left(23-x\right)}=40\)

               \(\Leftrightarrow\frac{360}{23-x}\)

               \(\Leftrightarrow360=40.\left(23-x\right)\)

               \(\Leftrightarrow9=23-x\)

               \(\Leftrightarrow x=14\)

Vậy x = 14

o, Ta có : \(\left(x-5\right).\left(x^2-4\right)=0\)

             \(\Leftrightarrow\orbr{\begin{cases}x-5=0\\x^2-4=0\end{cases}}\)

              \(\Rightarrow\orbr{\begin{cases}x=5\\x=\pm2\end{cases}}\)

Vậy \(x=5;-2;2\)

\(2x-3+3|x-1|=4x+1.\)

\(\Leftrightarrow3|x-1|=2x+4\)

*Với x < 1 ta có phương trình: 

\(3\left(-x+1\right)=2x+4\)

\(\Leftrightarrow-3x+3=2x+4\)

\(\Leftrightarrow5x+1=0\)

\(\Leftrightarrow x=-\frac{1}{5}\)(TM)

*Với \(x\ge1\)ta có phương trình: 

\(2x-3+3\left(x-1\right)=4x+1\)

\(\Leftrightarrow2x-3+3x-3=4x+1\)

\(\Leftrightarrow x-7=0\)

\(\Leftrightarrow x=7\)(TM)

Vậy ............

a) 720:[41-(2x-5)]=8*5

   720:[41-(2x-5)]=40

    41-(2x-5)     = 720:40

     41-(2x-5)   = 18

    2x-5         =41-18

   2x-5         =23

  2x               =23+5

 2x             =28

x            =28:2

x=14

b) x+(x+1)+(x+2)+......+(x+30)=1240

x+x+1+x+2+...+x+30=1240

(x+x+x+....+x) + (1+2+3+....30)=1240

31*x + \(\frac{\left(30+1\right)\cdot30}{2}\)=1240

31*x + 465 =1240

31*x=1240-465

31*x =775

x = 775:31

x=25

tick mình nhé 

CHTT nha bạn ! 

Đề thiếu rồi. Bạn xem lại.

#)Giải :

\(x\left(2x-1\right)\left(x+5\right)-\left(2x^2+1\right)\left(x+4,5\right)=3,5\)

\(\Leftrightarrow\left(2x^2-x\right)\left(x+5\right)-2x^3-9x^2-x-4,5=3,5\)

\(\Leftrightarrow2x^3+10x^2-x^2-5x-2x^3-9x^2-x-4,5=3,5\)

\(\Leftrightarrow-5x-4,5=3,5\)

\(\Leftrightarrow-5x=8\)

\(\Leftrightarrow x=-\frac{8}{5}\)

\(x\left(2x-1\right)\left(x+5\right)-\left(2x^2+1\right)\left(x+4,5\right)=3,5\)

\(\Leftrightarrow\left(2x^2-x\right)\left(x+5\right)-\left(2x^3+9x^2+x+4,5\right)=3,5\)

\(\Leftrightarrow2x^3+10x^2-x^2-5x-2x^3-9x^2-x-4,5=3,5\)

\(\Leftrightarrow-6x=8\)

\(\Leftrightarrow x=\frac{-8}{6}=\frac{-4}{3}\)

\(\frac{5}{1.2}+\frac{5}{2.3}+...+\frac{5}{99.100}-2x=\frac{1}{1.3}+\frac{1}{3.5}+\frac{1}{5.7}+...+\frac{1}{97.99}\)

\(5\left(\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{99.100}\right)-2x=\frac{1}{2}\left(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{97.99}\right)\)

\(5\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{99}-\frac{1}{100}\right)-2x=\frac{1}{2}\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{97}-\frac{1}{99}\right)\)\(5\left(1-\frac{1}{100}\right)-2x=\frac{1}{2}\left(1-\frac{1}{99}\right)\)

\(5.\frac{99}{100}-2x=\frac{1}{2}.\frac{98}{99}\)

\(\frac{99}{20}-2x=\frac{49}{99}\)

\(2x=\frac{99}{20}-\frac{49}{99}\)

\(2x=\frac{8821}{1980}\)

\(x=\frac{8821}{1980}:2\)

\(x=\frac{8821}{3960}\)