Ta có: \(5^{x-1}+3\cdot5^{x+1}=1900\)
\(\Leftrightarrow5^x:5+3\cdot5^x\cdot5=1900\)
\(\Leftrightarrow5^x\cdot\frac{1}{5}+15\cdot5^x=1900\)
\(\Leftrightarrow5^x\cdot\left(\frac{1}{5}+15\right)=1900\)
\(\Leftrightarrow5^x\cdot15,2=1900\)
\(\Leftrightarrow5^x=\frac{1900}{15,2}=125\)
\(\Leftrightarrow5^x=5^3\)
hay x=3
Vậy: x=3
Tìm số nguyên x biết:
a)3.5\(^x\)=3.5\(^4\)
b)9.7\(^x\)=\(6.7^5+3.7^5\)
c)\(2.3^{x+2}+4.3^{x+1}=10.3^7\)
GIÚP MÌNH VỚI CÁC BẠN ƠI
tìm x biết: \(\left|x+\dfrac{1}{1.3}\right|+\left|x+\dfrac{1}{3.5}\right|+.....+\left|x+\dfrac{1}{97.99}\right|=50x\)
Tim x, bt:\(\dfrac{1}{1.3}+\dfrac{1}{3.5}+\dfrac{1}{5.7}+...+\dfrac{1}{x\left(x+2\right)}=\dfrac{8}{17}\)
Tìm x:
\(5^{x+4}-3.5^{x+3}=2.5^{11}\)
5x+4-3.5x+3=2.511
Tìm số nguyên x, nếu biết
a, \(3.5^{x+2} + 4.5^{x-3}\)
b, \((\dfrac{1}{2}-\dfrac{1}{3})6^x+6^{x+2}=6^{10}+6^7\)
c, \((\dfrac{1}{3}+\dfrac{1}{6}) . 2^x + 2^{x+1}= 2^{12}+2^{10}\)
1. Tìm x, biết:
a) \(\left|x-1\right|+\left|x-4\right|=5\)
b) \(3\left|x+4\right|+\left|x-5\right|=10\)
c) \(\left|x+3\right|+\left|2x+1\right|=3x-6-\left|x+1\right|\)
d) \(\left|x\right|-\left|2x+3\right|=\left|x-1\right|\)
e) \(\left|x+1\right|+\left|2x-3\right|=\left|3x-2\right|\)
f) \(\left|x+2\right|+\left|x+\dfrac{3}{5}\right|=10x-\left|x+\dfrac{1}{2}\right|\)
g) \(\left|x+3\right|+\left|x+1\right|=3x\)
h) \(\left|x-1\right|+\left|x-3\right|< x+1\)
i) \(\left|x+\dfrac{1}{1.3}\right|+\left|x+\dfrac{1}{3.5}\right|+...+\left|x+\dfrac{1}{97.99}\right|=50x\)
j) \(\left|3x-5\right|+\left|3x+1\right|=6\)
(Ai làm đc bài nào thì làm nha)
Số tự nhiên x thỏa mãn:
B = \(\frac{1}{1.3}+\frac{1}{3.5}+\frac{1}{5.7}+...+\frac{1}{x\left(x+2\right)}=\frac{8}{17}\)
là x = .....
Trình bày cách giải cụ thể ra nha!
tìm x,y biết: |x-1/2|+|x-1/3|+|x-1/4|+|y-1/5|=1/4
