Ta có : \(\frac{1007}{2013}=\frac{2013-6}{2013}=1-\frac{6}{2013}>1-\frac{6}{2012}=\frac{1006}{2012}>\frac{1005}{2012}\)

=> \(\frac{1007}{2013}>\frac{1005}{2012}\)

\(\frac{1007}{2013}\)> \(\frac{1005}{2012}\)

ko biet luon a bn

\(\frac{2005}{2003}-1=\frac{2}{2003}\)

\(\frac{2003}{2001}-1=\frac{2}{2001}\)

Vì \(\frac{2}{2003}\frac{2003}{2001}\)

Ta thấy \(\frac{2019}{2001}< 1\)và \(\frac{2017}{2003}>1\)

\(=>\frac{2019}{2001}< \frac{2017}{2003}\)

~ Chúc hok tốt ~

\(\frac{2019}{2001}=2019:2001\)

\(\frac{2017}{2003}=2017:2003\)

ta có 2019:2001=1,008995502 và 2017:2003=1,006989516

ta có 1,008995502>1,006989516

\(\Rightarrow\)\(\frac{2019}{2001}>\frac{2017}{2003}\)

CHÚC BẠN HỌC TỐT

ta có 2019/2001=2019:2001 và 2017/2003=2017:2003

vì 2019:2001 >2017:2003

nên 2019/2001 >2017/2003

ta có: 2019/2001=2019:2001 và 2017/2003=2017:2003

vì 2019:2001 >2017:2003

nên 2019/2001 >2017/2003

2003 / 2001 = 1 + 2/2001

1999/1997 = 1 + 2/1997 

vì 2/ 2001 < 2/1997

nên 1 + 2/2001 < 1 + 2/1997

hay 2003 < 1999/1997

b, = 5/9 x 1/4 + 4/9 x 1/4 

= 1/4 x ( 5/9 + 4/9 )

= 1/4 x 1 

= 1/4

* Ý a mk k nhớ cách làm ^^, xl * 

\(b,\dfrac{5}{9}\times\dfrac{1}{4}+\dfrac{4}{9}\times\dfrac{3}{12}\)

\(=\dfrac{5}{9}\times\dfrac{1}{4}+\dfrac{4}{9}\times\dfrac{1}{4}\)

\(=\dfrac{1}{4}\times\left(\dfrac{5}{9}+\dfrac{5}{9}\right)\)

\(=\dfrac{1}{4}\times\dfrac{9}{9}=\dfrac{1}{4}\times1=\dfrac{1}{4}\)

Giúp mình, mình đang cần gấp!!!

Tham khảo : 

Sứa , san hô , hải quỳ , thủy tức , sứa tu dài ,...

\(\dfrac{2001+2002}{2002+2003}< \dfrac{2001}{2002}+\dfrac{2002}{2003}\)

(1) \(\frac{2002}{2003}\)và  \(\frac{145}{146}\)

Ta có: \(1-\frac{2002}{2003}=\frac{1}{2003}\);      \(1-\frac{145}{146}=\frac{1}{145}\)

Vì        \(\frac{1}{2003}< \frac{1}{146}\Rightarrow-\frac{1}{2003}>-\frac{1}{146}\)

\(\Rightarrow1-\frac{1}{2003}>1-\frac{1}{146}\)\(\Rightarrow\frac{2002}{2003}>\frac{145}{146}\)

Vậy   \(\frac{2002}{2003}>\frac{145}{146}\)

(2) \(\frac{2012}{2013}\)và     \(\frac{2012}{2015}\)

Vì: \(2013< 2015\Rightarrow\frac{2012}{2013}>\frac{2012}{2015}\)

Vậy: \(\frac{2012}{2013}>\frac{2012}{2015}\)

(3) \(\frac{159}{163}\) và  \(\frac{374}{371}\)

Vì \(\frac{159}{163}< 1\)và \(\frac{374}{371}>1\)

Nên \(\frac{374}{371}>\frac{159}{163}\)

Vậy \(\frac{374}{371}>\frac{159}{163}\)

(4) \(\frac{50}{110}\)và   \(\frac{65}{120}\)

Ta có: \(\frac{50}{110}< \frac{50}{100}=\frac{1}{2}\) và  \(\frac{65}{120}>\frac{60}{120}=\frac{1}{2}\) 

\(\Rightarrow\frac{50}{110}< \frac{65}{120}\)

Vậy \(\frac{50}{110}< \frac{65}{120}\)

(5) \(\frac{127}{139}\)và   \(\frac{130}{134}\)

Ta có: \(\frac{127}{139}< \frac{127}{134}< \frac{130}{134}\)

\(\Rightarrow\frac{127}{139}< \frac{130}{134}\)

Vậy \(\frac{127}{139}< \frac{130}{134}\)

\(2013< 2015\Rightarrow\frac{2012}{2013}>\frac{2012}{2015}\)\(2013< 2015\Rightarrow\frac{2012}{2013}>\frac{2012}{2015}\)

Cái dòng cuối bị thừa nha bạn, nhấn nhầm rồi máy nó nhảy

a) 2002/2003 > 145/146

b) 2013/2012 >2012/2015

c) 374/371 > 159/163

d) 50/110 < 65/120

e) 127/139 < 130/134