Bài 1.tìm số nguyên x biết :
a) x+x+x+91 = -2
b) -152-(3x+1)=-2*27
tìm số nguyên x, biết:
n) (-8).x + 17 = -23
o) (-15).x = 10.(-4) - 5
p) (-3).x -4 = 2.(-7) + 4
q) x + x + x + 91 = -2
r) -152 - (3x + 1) = (-2) . (-27)
n: (-8)*x+17=-23
=>\(x\cdot\left(-8\right)=-23-17=-40\)
=>\(x\cdot8=40\)
=>\(x=\dfrac{40}{8}=5\)
o: \(\left(-15\right)\cdot x=10\left(-4\right)-5\)
=>\(x\cdot\left(-15\right)=-40-5=-45\)
=>\(x\cdot15=45\)
=>\(x=\dfrac{45}{15}=3\)
p: \(\left(-3\right)\cdot x-4=2\cdot\left(-7\right)+4\)
=>\(\left(-3\right)\cdot x-4=-14+4=-10\)
=>\(x\left(-3\right)=-10+4=-6\)
=>\(3x=6\)
=>\(x=\dfrac{6}{3}=2\)
q: x+x+x+91=-2
=>\(3x+91=-2\)
=>\(3x=-2-91=-93\)
=>\(x=-\dfrac{93}{3}=-31\)
r: \(-152-\left(3x+1\right)=\left(-2\right)\cdot\left(-27\right)\)
=>\(-152-3x-1=54\)
=>\(-153-3x=54\)
=>\(3x=-153-54=-207\)
=>\(x=-\dfrac{207}{3}=-69\)
Tìm số nguyên x, biết:
x+x+x+91=-2
-152-(3x+1)=(-2).(-27)
/5x+1/=11
x + x + x + 91 = -2
x + x + x = -2 - 91
x + x + x = -93
3x = -93
x = -93 : 3
x = -31
-152 - (3x + 1) = (-2) . (-27)
-152 - (3x + 1) = 54
3x + 1 = -152 - 54
3x + 1 = -206
3x = -206 - 1
3x = -207
x = -207 : 3
x = -69
|5x + 1| = 11
5x + 1 = 11 hay 5x + 1 = -11
5x = 11 - 1 hay 5x = -11 - 1
5x = 10 hay 5x = -12
x = 10 : 5 hay x = -12 : 5
x = 2 hay x = -2,4
Mà x ∈ Z
x = 2
Tìm số nguyên X
a 5(-x-2)=0
b (-4).x=26
c -152-(3x+1)=(-2).(27)
cứu em với
a) 5(-x - 2) = 0
-x - 2 = 0
-x = 0 + 2
-x = 2
x = -2 (nhận)
Vậy x = -2
b) (-4).x = 26
x = 26 : (-4)
x = -13/2 (loại)
Vậy không tìm được x là số nguyên thỏa mãn đề bài
c) -152 - (3x + 1) = (-2).27
-152 - (3x + 1) = -54
3x + 1 = -152 + 54
3x + 1 = -98
3x = -98 - 1
3x = -99
x = -99 : 3
x = -33 (nhận)
Vậy x = -33
a, 5.(- \(x\) - 2) = 0
- \(x\) - 2 = 0
\(x\) = - 2
b, (-4).\(x\) = 26
\(x\) = 26 : (-4)
\(x\) = - \(\dfrac{13}{2}\) (loại) vì \(x\)\(\in\) Z)
c; -152 - (\(3x\) + 1) = (-2).(27)
-152 - 3\(x\) - 1 = - 54
3\(x\) = -54 + 1 + 152
3\(x\) = - 99
\(x\) = - 99: 3
\(x\) = - 33
Bài 1:Tìm số nguyên x, biết:
Bỏ ngoặc rồi tìm x.
a) x-8-(12-2x)= -20
b) -27+(x+8)-(+11)=2
c) -2x-16=2-(3x+9)
a) x - 8 - (12 - 2x) = -20
=> x - 8 - 12 + 2x = -20
=> (x + 2x) + (-8 - 12) = -20
=> 3x - 20 = -20
=> 3x = 0 => x = 0
b) -27 + (x + 8) - ( +11) = 2
=> -27 + x + 8 - 11 = 2
=> -27 + x = 2 + 11 - 8
=> -27 + x = 5
=> x = 5 - (-27) = 32
c) -2x - 16 = -2 - (3x + 9)
=> -2x - 16 = -2 - 3x - 9
=> -2x - 16 + 2 + 3x + 9 = 0
=> (-2x + 3x) + (-16 + 2 + 9) = 0
=> x - 5 = 0
=> x = 5
\(a,x-8-\left(12-2x\right)=-20\)
\(x-8-12+2x=-20\)
\(x+2x-8-12=-20\)
\(3x-20=-20\)
\(3x=-20+20\)
\(3x=0\)
\(x=0\)
\(b,-27+\left(x+8\right)-\left(+11\right)=2\)
\(-27+x+8-11=2\)
\(x-27+8-11=2\)
\(x-30=2\)
\(x=2+30\)
\(x=32\)
\(c,-2x-16=2-\left(3x+9\right)\)
\(-2x-16=2-3x-9\)
\(-2x+3x=2-9+16\)
\(x=9\)
Học tốt
a) x - 8 - ( 12 - 2x ) = -20
x - 8 - 12 + 2x = -20
x + 2x = -20 + 8 + 12
3x = 0
x = 0 \(\left(x\in Z,tm\right)\)
Vậy x=0
b) -27 + ( x + 8 ) - ( +11 ) = 2
-27 + x + 8 - 11 = 2
x = 2 + 27 - 8 + 11
x = 32 \(\left(x\in Z,tm\right)\)
Vậy x = 32
c) -2x - 16 = 2 - ( 3x + 9 )
-2x - 16 = 2 - 3x - 9
-2x + 3x = 2 - 9 +16
x = 9 \(\left(x\in Z,tm\right)\)
Vậy x = 9
Bài 1: Tính
a) - ( 515 - 80 + 91 ) - ( 2003 + 80 - 91 )
b) - 2016 + 57 + 2016 - 257 + 100
Bài 2: Tìm x, biết
a) 25 - ( 30 + x ) = - ( 3x - 27 )
b) ( x - 12 ) - 15 = ( 20 - 7 ) - ( 18 + x )
c) | x - 5 | - 10 = 3
Các bạn ghi cách giải cho mình nhé
Tìm số nguyên x, biết :
a, -152 - ( 3x + 1 ) = (-2) . (-77)
b, 234 + ( -334 - x ) = 500
c, ( 567 - x ) + 121 = -641
Minh can gap!!!!!
\(a,-152-\left(3x+1\right)=\left(-2\right).\left(-77\right)\)
\(-152-\left(3x+1\right)=154\)
\(3x+1=-152-154\)
\(3x=306\)
\(x=-102\)
Vậy \(x=-102\)
\(b,234+\left(-334-x\right)=500\)
\(-334-x=266\)
\(x=-600\)
Vậy \(x=-600\)
\(c,\left(567-x\right)+121=-641\)
\(567-x=-762\)
\(x=1329\)
Vậy \(x=1329\)
Làm lại câu a :
a, -152-(3x+1)=(-2).(-77)
-152-(3x+1)=154
3x+1=-306
3x=-307
x=-307/3
Vậy x=-307/3
a,-152-(3x+1)=(-2).(-77)
-152-(3x+1)=154
3x+1=-152-154
3x+1=-306
3x=-307
x=-307/3
b,234+(-334-x)=500
-334-x=500-234
-334-x=266
x=-334-266
x=-600
c,(567-x)+121=-641
567-x=-641-121
567-x=-762
x=567-(-762)
x=1329
Bài 3(2 điểm): Tìm số nguyên x biết:
a) 3x + 27 = 9
b) 2x + 12 = 3(x – 7)
c) 2x2 – 1 = 49
d) |-9 – x| -5 = 12
a) 3x + 27 = 9
=> 3x = 9 - 27
=> 3x = -18
=> x = -18 : 3
=> x = -6
b) 2x + 12 = 3(x - 7)
=> 2x + 12 = 3x - 3 . 7
=> 2x + 12 = 3x - 21
=> 3x - 2x = 21 - 12
=> x = 9
c) 2x . 2 - 1 = 49
=> 2x . 2 = 49 + 1
=> 2x . 2 = 50
=> 2x = 50 : 2
=> 2x = 25
=> x =25 : 2
=> x = 25/2
d) |-9 - x| - 5 = 12
=> |-9 - x| = 12 + 5
=> |-9 - x| = 17
=> \(\orbr{\begin{cases}-9-x=17\\-9-x=-17\end{cases}}\)
=> \(\orbr{\begin{cases}x=-9-17\\x=-9-\left(-17\right)\end{cases}}\)
=> \(\orbr{\begin{cases}x=-26\\x=8\end{cases}}\)
3x + 27 = 9
3x = 9 - 27
3x = - 18
x = - 6
b, 2x + 12 = 3.( x - 7 )
2x + 12 = 3x - 21
2x - 3x = - 21 - 12
- x = - 33
x = 33
c, 2x2 - 1 = 49
=> 2x2 = 49 + 1
=> 2x2 = 50
=> x2 = 50 : 2
=> x2 = 25
=> x = 5 hoặc x = - 5
d, | - 9 - x | - 5 = 12
| - 9 - x | = 12 + 5
| - 9 - x | = 17
=> - 9 - x = 17 hoặc - 9 - x = - 17
=> x = - 26 hoặc x = 8
Giúp mik làm bài này với.
Tìm x€Z bt:
-x-14+32=-26
-152-(3x+1)=(-2).(-27)
X+x+x+82=-2-x
(-1).(-3).(-6).x=36
a) \(-x-14+32=-26\)
\(-x=-26-32+14\)
\(-x=-44\)
\(x=44\)
b) \(-152-\left(3x+1\right)=\left(-2\right)\left(-27\right)\)
\(-152-3x-1=54\)
\(-3x=96\)
\(x=-32\)
c) \(x+x+x+82=-2-x\)
\(3x+82=2+x\)
\(2x=-80\)
\(x=-40\)
d) \(\left(-1\right)\left(-3\right)\left(-6\right)x=36\)
\(-18x=36\)
\(x=-2\)
1)
\(-x-14+32=-26\)
\(\Rightarrow-x+18=-26\)
\(\Rightarrow-x=-26-18\)
\(\Rightarrow-x=-44\)
\(\Rightarrow x=44\)
Vậy \(x=44\)
2)
\(-152-\left(3x+1\right)=\left(-2\right)\left(-27\right)\)
\(\Rightarrow-152-3x-1=54\)
\(\Rightarrow-153-3x=54\)
\(\Rightarrow-3x=54+163\)
\(\Rightarrow-3x=207\)
\(\Rightarrow x=207:\left(-3\right)\)
\(\Rightarrow x=-69\)
Vậy \(x=-69\)
3)
\(x+x+x+82=-2-x\)
\(\Rightarrow3x+82=-2-x\)
\(\Rightarrow3x+x=-2-82\)
\(\Rightarrow4x=-84\)
\(\Rightarrow x=-21\)
Vậy \(x=-21\)
4)
\(\left(-1\right)\left(-3\right)\left(-6\right).x=36\)
\(\Rightarrow-18x=36\)
\(\Rightarrow x=-2\)
Vậy \(x=-2\)
Bài 1:
a) Tìm a,b,c biết (3c - 4b)/ 2 = (4a-2c) /3 = (2b - 3a) / 4; c + b + 2a = -27
b) Tìm x, y, z biết (3x - 4y) /5 = (5y - 3c) /4 = (4x - 5z) / 3 ; x^2 - z^3 = 36