-2018 mũ 0 -176:[50:(5 mũ 2.7-5 mũ 2.6)]
(3.|x|.2 mũ 4).7 mũ 2018=2.7 mũ 2019. 1/2019 mũ 0
Giải gấp hộ mình nhé huhu
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1. 6 X mũ 3 -8 =40
2. 4 X mũ 5 +15=47
3. 2 X mũ 3-4=12
4. 5 X mũ 3-5=0
5. (X -5) mũ 2016 = (X-5) mũ 2018
6. (3X -2) mũ 20= (3X-1) mũ 20
7. (3X -1) mũ 10 = (3X-1) mũ 20
8. (2X -1) mũ 50 = 2X-1
9. (X phần 3 -5) mũ 2000= ( X phần 3-5) mũ 2008
1. \(6x^3-8=40\\ 6x^3=48\\ x^3=8\\ \Rightarrow x=2\)Vậy x = 2
2. \(4x^5+15=47\\ 4x^5=32\\ x^5=8\\ \Rightarrow x\in\varnothing\left(\text{vì }x\in N\right)\)Vậy x ∈ ∅
3. \(2x^3-4=12\\ 2x^3=16\\ x^3=8\\ \Rightarrow x=2\)Vậy x = 2
4. \(5x^3-5=0\\ 5x^3=5\\ x^3=1\\ \Rightarrow x=1\)Vậy x = 1
5. \(\left(x-5\right)^{2016}=\left(x-5\right)^{2018}\\ \Rightarrow\left[{}\begin{matrix}x-5=0\\x-5=1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=5\\x=6\end{matrix}\right.\)Vậy \(x\in\left\{5;6\right\}\)
6. \(\left(3x-2\right)^{20}=\left(3x-1\right)^{20}\\ \Rightarrow3x-2=3x-1\\ 3x-3x=2-1\\ 0=1\left(\text{vô lí}\right)\)Vậy x ∈ ∅
7. \(\left(3x-1\right)^{10}=\left(3x-1\right)^{20}\\ \left(3x-1\right)^{10}=\left[\left(3x-1\right)^2\right]^{10}\\ \Rightarrow\left(3x-1\right)^2=3x-1\\ \left(3x-1\right)^2-\left(3x-1\right)=0\\ \left(3x-1\right)\left[\left(3x-1\right)-1\right]=0\\ \left(3x-1\right)\left(3x-2\right)=0\\ \Rightarrow\left[{}\begin{matrix}3x-1=0\\3x-2=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}3x=1\\3x=2\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\frac{1}{3}\left(\text{loại vì }x\in N\right)\\x=\frac{2}{3}\left(\text{loại vì }x\in N\right)\end{matrix}\right.\)Vậy x ∈ ∅
8. \(\left(2x-1\right)^{50}=2x-1\\ \left(2x-1\right)^{50}-\left(2x-1\right)=0\\ \left(2x-1\right)\left[\left(2x-1\right)^{49}-1\right]=0\\ \Rightarrow\left[{}\begin{matrix}2x-1=0\\\left(2x-1\right)^{49}=1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}2x=1\\2x-1=1\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\frac{1}{2}\left(\text{loại vì }x\in N\right)\\x=1\left(t/m\right)\end{matrix}\right.\)Vậy x = 1
9. \(\left(\frac{x}{3}-5\right)^{2000}=\left(\frac{x}{3}-5\right)^{2008}\\ \left(\frac{x}{3}-5\right)^{2008}-\left(\frac{x}{3}-5\right)^{2000}=0\\ \left(\frac{x}{3}-5\right)^{2000}\left[\left(\frac{x}{3}-5\right)^8-1\right]=0\\ \Rightarrow\left[{}\begin{matrix}\left(\frac{x}{3}-5\right)^{2000}=0\\\left(\frac{x}{3}-5\right)^8=1\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}\frac{x}{3}-5=0\\\frac{x}{3}-5=1\\\frac{x}{3}-5=-1\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}\frac{x}{3}=5\\\frac{x}{3}=6\\\frac{x}{3}=4\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=5\cdot3=15\\x=6\cdot3=18\\x=4\cdot3=12\end{matrix}\right.\)Vậy \(x\in\left\{15;18;12\right\}\)
\(1.6x^3-8=40\\ \Leftrightarrow6x^3=48\\ \Leftrightarrow x^3=8\Leftrightarrow x^3=2^3=\left(-2\right)^3\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-2\end{matrix}\right.\)
Vậy \(x\in\left\{2;-2\right\}\)
\(2.4x^3+15=47\) (T nghĩ đề là mũ 3)
\(\Leftrightarrow4x^3=32\Leftrightarrow x^3=8=2^3=\left(-2\right)^3\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-2\end{matrix}\right.\)
Vậy \(x\in\left\{2;-2\right\}\)
Câu 3, 4 tương tự nhé.
\(5.\left(x-5\right)^{2016}=\left(x-5\right)^{2018}\\ \Leftrightarrow\left(x-5\right)^{2018}-\left(x-5\right)^{2016}=0\\ \Leftrightarrow\left(x-5\right)^{2016}\left[\left(x-5\right)^2-1\right]=0\\ \Leftrightarrow\left(x-5\right)^{2016}\left(x-5-1\right)\left(x-5+1\right)=0\\ \Leftrightarrow\left(x-5\right)^{2016}\left(x-6\right)\left(x-4\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}\left(x-5\right)^{2016}=0\\x-6=0\\x-4=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x-5=0\\x=6\\x=4\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=5\\x=6\\x=4\end{matrix}\right.\)
Vậy \(x\in\left\{4;5;6\right\}\)
Tính nhanh nếu có thể
a,(5 mũ 2001- 5 mũ 2000):5 mũ 2000
b,(5 mũ 7 + 7 mũ 5).(6 mũ 8 +8 mũ 6) .(2 mũ 4 - 4 mũ 2)
c,[(5 mũ 2 . 2 mũ 3)-7 mũ 2 . 2] :2.6-725
Tính nhanh nếu có thể
a,(5 mũ 2001- 5 mũ 2000):5 mũ 2000
b,(5 mũ 7 + 7 mũ 5).(6 mũ 8 +8 mũ 6) .(2 mũ 4 - 4 mũ 2)
c,[(5 mũ 2 . 2 mũ 3)-7 mũ 2 . 2] :2.6-725
a) (5 mũ 2001- 5 mũ 2000):5 mũ 2000
= ( 5 mũ 1 . 5 mũ 2000-5 mũ 2000) : 5 mũ 2000
=5 mũ 2000 . ( 5 mũ 1 - 1) : 5 mũ 2000
= 5 mũ 2000 . 4 : 5 mũ 2000
= ( 5 mũ 2000 : 5 mũ 2000 ) .4
= 5 mũ 0 . 4
= 1 . 4 = 4
b)
A = 5 mũ 2018- 2016 phần 5 mũ 2018 - 2017 và B = 5 mũ 2018-2018 phần 5 mũ 2018 -2019
a, { 145 - [ 130 - ( 246 - 236 ) ] : 2 } . 5
b, 100 : { 250 : [ 450 - ( 4.5 (mũ 3) - 2 ( mũ 2 ) .25 ) ] }
c, 355 - 5 ( mũ 1 ) . [ 4 ( mũ 3 ) - ( 3 ( mũ 3 ) - 5 ( mũ 2 ) ) : 1 ( mũ 18 ) ]
d, 2018 ( mũ 0 ) + [ 5 ( mũ 19 ) + 5 ( mũ 17 ) + ( 125 - 120 ) ( mũ 3 ) ]
a: \(=\left\{145-\left[130-10\right]:2\right\}\cdot5\)
\(=\left\{145-60\right\}\cdot5=85\cdot5=425\)
b: \(=100:\left\{250:\left[450-4\cdot125+4\cdot25\right]\right\}\)
\(=\dfrac{100}{250:\left[450-500+100\right]}=\dfrac{100}{250:50}=\dfrac{100}{5}=20\)
c: \(=355-5\cdot\left[64-\left(27-25\right)\right]=355-5\cdot\left[64-2\right]\)
\(=355-310=45\)
Ai giúp mình với
a, { 145 - [ 130 - ( 246 - 236 ) ] : 2 } . 5
b, 100 : { 250 : [ 450 - ( 4.5 (mũ 3) - 2 ( mũ 2 ) .25 ) ] }
c, 355 - 5 ( mũ 1 ) . [ 4 ( mũ 3 ) - ( 3 ( mũ 3 ) - 5 ( mũ 2 ) ) : 1 ( mũ 18 ) ]
d, 2018 ( mũ 0 ) + [ 5 ( mũ 19 ) + 5 ( mũ 17 ) + ( 125 - 120 ) ( mũ 3 ) ]
các góc nhọn,tù,vuông có bao nhiêu độ
Tìm n biết
(5^2018+5^2018+5^2018+5^2018+5^2018)-5^n=0
(5^1: năm mũ một tại điện thoại Ko có mũ)
3 mũ 3. 5 mũ 3 - 20 . { 546 - 2 mũ 3 ( 7 mũ 8 : 7 mũ 6 + 7 mũ 0 )]}
62500: {50 mũ 2 : [112-(52-2 mũ 3. 5)]}
Bài làm
33.53-20.{546-23.(78:76+70)}
=27.125-20.{546-8.50}
=27.125-20.{546-400}
=3375-20.146
=3357-2920
=455
62500:{502:[112-(52-23.5)]}
=62 500:{250:[112-(52-40)]}
=62 500:{250:[112-12]
=62 500:{250:100}
=62 500:2,5
=25 000