A=2008.(1/2007-1000/1004)-2009.(1/2007-2)
2008.(\(\dfrac{1}{2007}\)-\(\dfrac{2009}{1004}\))-2009.(\(\dfrac{1}{2007}\)-2)
\(=\dfrac{2008}{2007}-2\cdot2009-\dfrac{2009}{2007}+2009\cdot2\)
=-1/2007
a) [-2008*57+1004(-86)]/[32*74+16*(-48)]
b)1+2-3-4+5+6-7-8+9+10-...+2006-2007-2008+2009
So sánh
bài 1 :A= 2006/2007-2007/2008+2008/2009-2009/2010
B= -1/2006*2007-1/2008*2009
bài 2: C= 2006/2007+2007/2008+2008/2009+2009/2006 với 4
a) [ -2008 x 57 + 1004 x (-86) ] : [ 32 x 74 + 16 x (-48) ]
b) 1 + 2 - 3 - 4 + 5 + 6 - 7 - 8 + 9 +10 - ......................... + 2006 - 2007 - 2008 + 2009
Tính nhanh: a) 1004 . 2009 +1005 / 1005 .2009- 1004
b) 1004 .2010 +1 / 1006.2009 - 3013
c) 2008 . 2008 -3 / 2007 .2009 - 2
Mng mọi người giúp mình bài toán này!!! Mình đang cần gấp.
a, 1004 .2009 + 1005 = (1005-1) .2009 +1005
= 1005 .2009 -2009 +1005
= 1005 .2009 -1004
Vậy ( 1004 .2009 +1005) / (1005 .2009 -1004) =1
b, 1004 .2010 +1 = 1004 .2009 +1004 +1
= (1006 -2) .2009 +1005
= 1006 .2009 -2 .2009 +1005
= 1006 .2009 -4008 +1005
= 1006 .2009 -3013
Vậy (1004 .2010 +1) / (1006 .2009 -3013) = 1
c, 2007 .2009 -2 = 2007.(2008+1) -2
= 2007.2008 +2007 -2
= 2007.2008 +2005
= (2008-1) .2008 +2005
= 2008 .2008 -2008 +2005
= 2008 .2008 -3
Vậy (2008 .2008 -3) / (2007 .2009 -2) =1
dựa và mà làm nha bạn
1005.2009-1004=1004.2009+2009-1004=1004.2009+1005
=> a=1
2. So sánh A và B:
A= 2006/2007 - 2007/2008 + 2008/2009 - 2009/2010
B=-1/2006*2007 - 1/2008*2009
tính hợp lý :
a, \(2008.\left(\dfrac{1}{2007}-\dfrac{2009}{1004}\right)-2009.\left(\dfrac{1}{2007}-2\right)\)
b, \(\dfrac{5^5.20^3-5^4.20^3+5^7.4^5}{\left(20+5\right)^3.4^5}\)
a: \(=\dfrac{2008}{2007}-2009\cdot2-\dfrac{2009}{2007}+2009\cdot2\)
=-1/2007
b: \(=\dfrac{5^5\cdot5^3\cdot2^6-5^4\cdot5^3\cdot2^6+5^7\cdot2^{10}}{5^6\cdot2^{10}}\)
\(=\dfrac{5^8\cdot2^6-5^7\cdot2^6+5^7\cdot2^{10}}{5^6\cdot2^{10}}\)
\(=\dfrac{5^7\cdot2^6\left(5-1+2^4\right)}{5^6\cdot2^{10}}=\dfrac{5}{16}\cdot\dfrac{20}{1}=\dfrac{100}{16}=\dfrac{25}{4}\)
A=(2008/1+2007/2+...........+2/2007+2/2008)/(1/2+1/3+........+1/2008+1/2009)
Câu 1: So sánh các số hữu tỉ:
A = 2006/2007 - 2007/2008 + 2008/2009 - 2009/2010 với B = -1/2006 x 2007 - (-1)/2007 x 2008