tim x
x/3 =3/x
8/5=-12/x
x/-4=-4/x
TÌM
-12 / 25 . ( 3 / 4 + 6 / -11 5 / 6 ) = 0
=> cái vế trong ngoặc là 0.
rồi bạn làm tiếp nha
\(\dfrac{-12}{25}.\left(\dfrac{3}{4}-x+\dfrac{6}{-11}-\dfrac{5}{6}\right)=0\)
\(\dfrac{3}{4}-x+\dfrac{-6}{11}-\dfrac{5}{6}=0\)
\(\dfrac{3}{4}-x+\dfrac{-91}{66}=0\)
\(\dfrac{3}{4}-x=0-\left(\dfrac{-91}{66}\right)\)
\(\dfrac{3}{4}-x=\dfrac{91}{66}\)
\(x=\dfrac{-83}{132}\)
a: Ta có: \(-\dfrac{12}{25}\cdot\left(\dfrac{3}{4}-x+\dfrac{6}{-11}-\dfrac{5}{6}\right)=0\)
\(\Leftrightarrow x+\dfrac{83}{132}=0\)
hay \(x=-\dfrac{83}{132}\)
a) Tính bằng cách thuận tiện
12/15 + 4/3 + 1/4 + 3/4 + 5/3 + 3/15
b) Tìm X
X x 3/4 = 1/6 x 3/5 x 6/5 x 5/3 (MÌNH CẦN GẤP ĐỂ NỘP)
a. \(=\left(\dfrac{12}{15}+\dfrac{3}{15}\right)+\left(\dfrac{4}{3}+\dfrac{5}{3}\right)+\left(\dfrac{1}{4}+\dfrac{3}{4}\right)\\ =1+2+1=4\)
b. \(x\times\dfrac{3}{4}=\dfrac{1\times3\times6\times5}{6\times5\times5\times3}\\ x\times\dfrac{3}{4}=\dfrac{1}{5}\\ x=\dfrac{1}{5}:\dfrac{3}{4}\\ x=\dfrac{4}{15}\)
a.
(12/15+3/15)+(4/3+5/3)+(1/4+3/4)
=1+3+1=5
b.X x 3/4=1/5
X=1/5:3/4
X=4/15
Giải các phương trình sau: x x - 3 - x x - 5 = x x - 4 - x x - 6
ĐKXĐ: x ≠ 3, x ≠ 4, x ≠ 5, x ≠ 6.
Ta có:
Vậy phương trình đã cho có nghiệm là x = 0;x = 9/2.
bài 3 :tìm x
x-3/5=10 x:4=2/3
bài 4: xếp các phân số 12/27;8/14;20/40 theo thứ tự tăng dần
Giải các phương trình sau: x x - 3 - x x - 5 = x x - 4 - x x - 6
Tìm x
x - 3/4 = 8/5 x 5/4
\(x-\dfrac{3}{4}=2\)
\(x=2+\dfrac{3}{4}\)
\(x=\dfrac{11}{4}\)
x - 3/4 = 8/5 x 5/4
x - 3/4 = 2
x = 2 + 3/4
x = 11/4
vậy x =...
1.tìm x
X x 6/7=5/14 X : 2/3=4/9
X-1/4=3/2 X+4/5=8/9
`x xx 6/7=5/14`
`=>x=5/14:6/7`
`=>x=5/14xx7/6`
`=>x=35/84`
`=>x=5/12`
Vậy `x=5/12`
__
`x:2/3=4/9`
`=>x=4/9xx2/3`
`=>x=8/27`
Vậy `x=8/27`
__
`x-1/4=3/2`
`=>x=3/2+1/4`
`=>x=6/4+1/4`
`=>x=7/4`
Vậy `x=7/4`
__
`x+4/5=8/9`
`=>x=8/9-4/5`
`=>x=40/45-36/45`
`=>x=4/45`
Vậy `x=4/45`
\(x\cdot\dfrac{6}{7}=\dfrac{5}{14}\)
\(x\) \(=\dfrac{5}{14}:\dfrac{6}{7}\)
\(x\) \(=\dfrac{5}{12}\)
\(x:\dfrac{2}{3}=\dfrac{4}{9}\)
\(x\) \(=\dfrac{4}{9}\cdot\dfrac{2}{3}\)
\(x\) \(=\dfrac{8}{27}\)
\(x-\dfrac{1}{4}=\dfrac{3}{2}\)
\(x\) \(=\dfrac{3}{2}+\dfrac{1}{4}\)
\(x\) \(=\dfrac{7}{4}\)
\(x+\dfrac{4}{5}=\dfrac{8}{9}\)
\(x\) \(=\dfrac{8}{9}-\dfrac{4}{5}\)
\(x\) \(=\dfrac{4}{45}\)
Giải các phương trình sau:
1) 2 1 5 x 2) 2 1 5 x x
3) 3 1 2 x x 4) 3 2 2 x x
5) 2 1 5 x x 6) 3 2 x x
7) 2 3 2 1 x x 8) 2 1 4 1 0 x x 2
9) 2 5 4 3 1 1 2
3 2 3 1
x x
x x x x
10) 1 7 3 2
3 3 9
x x x
x x x
11) 5 296 2 1 3 1
16 4 4
x x
x x x
12)
2 4
1
2 1 2 1 2 1 2 1
x x
x x x x
13) 2 1 2 2
2 2
x
x x x x
14) 22 4
2 6 2 2 2 3
a)5^x : (5^2)^2= 625
b)(12/25)^x= (3/5)^2-(-3/5)^49: 45
c) (-3/4)^3 xX = 337
d) (x-1)^4-(x-1)^7=0
giúp mk nha mk tick cho
a) \(5^x:\left(5^2\right)^2=625\)
\(5^x:625=625\)
\(5^x=5^8\)=> x = 8
Mấy câu kia tương tự
d) \(\left(x-1\right)^4-\left(x-1\right)^4\cdot\left(x-1\right)^3=0\)
\(\left(x-1\right)^4\cdot\left[1-\left(x-1\right)^3\right]=0\)
\(\Rightarrow\orbr{\begin{cases}x-1=0\\\left(x-1\right)^3=1\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=1\\x-1=1\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=1\\x=2\end{cases}}\)
Vậy,..........