1/4/23-5/21-4/23+1,5+1/16/21
Tuyển Cộng tác viên Hoc24 nhiệm kì 26 tại đây: https://forms.gle/dK3zGK3LHFrgvTkJ6
A=1/4/23-5/21-4/23+/1,5+1/16/21
B=1/5√100-√9/16
|2005-x|*2004=2005
1. 5/21+0,5-19/23+16/21-4/23
2. 27/23+5/21-4/23+6/21+1/2
giải giúp mình nhé mấy bạn
1, \(\frac{5}{21}+0,5-\frac{19}{23}+\frac{16}{21}-\frac{4}{23}\)
\(=\frac{5+16}{21}-\frac{19+4}{23}+0,5\)
\(=1-1+0,5\)
\(=0,5\)
2,\(\frac{27}{23}+\frac{5}{21}-\frac{4}{23}+\frac{6}{21}+\frac{1}{2}\)
\(=\frac{27-4}{23}+\frac{5+6}{21}+\frac{1}{2}\)
\(=1+\frac{11}{21}+\frac{1}{2}\)
\(=\frac{42+22+21}{42}\)
\(=\frac{85}{42}\)
1/4/23+5/21-4/23+0,5+16/21
=27/23+5/21-4/23+1/2+16/21
=682/483-4/23+1/2+16/21
=26/21+1/2+16/21
=5/2
27/23--5/21-4/23+16/21+1/2
1\(\dfrac{4}{23}\) +\(\dfrac{5}{21}\) - \(\dfrac{4}{23}\) + 0,5 +\(\dfrac{16}{21}\)
=1+4/23-4/23+5/21+16/21+1/2
=1+1+1/2
=5/2
\(\dfrac{27}{23}\) + \(\dfrac{5}{21}\) - \(\dfrac{4}{23}\) + \(0,5\) + \(\dfrac{16}{21}\)
= [ \(\dfrac{27}{23}\) - \(\dfrac{4}{23}\) ] + [ \(\dfrac{5}{21}\) + \(\dfrac{16}{21}\) ] + 0,5
= 1 + 1 + 0,5
= 2 + 0,5
= 2,5
1 va 4/23 - 5/-21 - 4/23 - 0,5 + 2 va 16/21
tính: 27/23 + 5/21 -4/23 + 16/21 + 1/2
\(\left(\frac{27}{23}-\frac{4}{23}\right)+\left(\frac{5}{21}+\frac{16}{21}\right)+\frac{1}{2}\)
\(=1+1+\frac{1}{2}\)
\(=\frac{5}{2}\)
k cho mk nha!
14/23+5/21-4/23+0,5+16/21. 14/23 là hỗn số một và bốn phần ba
\(\left(1\dfrac{4}{23}-\dfrac{5}{21}\right)-\left(\dfrac{4}{23}-\dfrac{3}{4}\right)-\dfrac{16}{21}\)
\(=\left(1\dfrac{4}{23}-\dfrac{4}{23}\right)-\left(\dfrac{5}{21}+\dfrac{16}{21}\right)+\dfrac{3}{4}=1-1+\dfrac{3}{4}=\dfrac{3}{4}\)