\(=\frac{2^5.3^5.2^2.5^2}{2^5.3^6.5}=\frac{5.2^2}{3}=\frac{20}{3}\)

1;Ta có\(5.3^x=5.3^4\)

\(\Rightarrow3^x=3^4\)

\(\Rightarrow x=4\)

2.Ta có \(9.5^x=6.5^6+3.5^6\)

\(\Rightarrow9.5^x=5^6.\left(6+3\right)\)

\(\Rightarrow9.5^x=9.5^6\)

\(\Rightarrow5^x=5^6\)\

\(\Rightarrow x=6\)

3, Ta có \(2.3^{x+2}+4.3^{x+1}=10.3^6\)

\(\Rightarrow3^{x+1}.\left(2.3+4\right)=10.3^6\)

\(\Rightarrow3^{x+1}.10=10.3^6\)

\(\Rightarrow3^{x+1}=3^6\)

\(\Rightarrow x+1=6\)

\(\Rightarrow x=5\)

a) 5.3^x = 5.3⁴

=> 3^x=3⁴

=> x=4

b) 9.5^x=6.5⁶+3.5⁶

=> 9.5^x = (6+3)5⁶

=> 9.5^x=9.5⁶

=> 5^x=5⁶

=> x=6

c) 2.3^x+2 + 4.3^x+1 = 10.3⁶

=> 2.3^x+1.3 + 4.3^x+1 = 10.3⁶ 

=> 6.3^x+1+4.3^x+1=10.3⁶

=> (6+4).3^x+1=10.3⁶

=> 10.3^x+1=10.3⁶

=> 3^x+1=3⁶

=> x+1=6

=> x=5

5.3^x=5.3⁴

<=> 3^x=3⁴( chia cả hai vế cho 5)

<=> x=4

Câu thứ hai viết lại đề

7.3^x=5.3⁷+2.3⁷

<=> 7.3^x=3⁷.(5+2)

<=> 7.3^x=3⁷.7

<=> 3^x=3⁷(chia cả hai vế cho 7)

<=> x=7

Ta có: \(\frac{2^5.7+2^5}{2^5.5^2-2^5.3}\) = \(\frac{2^5.\left(7+1\right)}{2^5.\left(5^2-3\right)}\) = \(\frac{2^5.8}{2^5.22}\) = \(\frac{8}{22}\) =\(\frac{56}{154}\)

​\(\frac{3^4.5-3^6}{3^4.13+3^4}\) = \(\frac{3^4.\left(5-3^2\right)}{3^4.\left(13+1\right)}\) = \(\frac{3^4.\left(-4\right)}{3^4.14}\) = \(\frac{-4}{14}\)= \(\frac{-44}{154}\)

\(\frac{2^5.3^7-2^5.3^6}{2^5.3^6}=\frac{2^5.3^6.\left(3-1\right)}{2^5.3^6}=2\)

Tìm số ự nhiên x biết.

a, 2^x=4^6.16³

2^x=(2²)².(2⁴)³

2^x=2⁴.2¹²

2^x=2¹⁶

=>x=16

Vậy x=16

học tốt

a, \(2^x=4^6\cdot16^3\)

\(2^x=\left(2^2\right)^6\cdot\left(2^4\right)^3\)

\(2^x=2^{12}\cdot2^{12}\)

\(2^x=2^{24}\)

\(\Rightarrow\text{ }x=24\)

\(b,\text{ }\frac{2^{x-3}}{4^{10}}=8^3\)

\(\Rightarrow\text{ }\frac{2^{x-3}}{\left(2^2\right)^{10}}=\left(2^3\right)^3\)

\(\frac{2^{x-3}}{2^{20}}=2^9\)

\(\Rightarrow\text{ }2^{x-3}=2^{20}\cdot2^9\)

\(2^{x-3}=2^{29}\)

\(\Rightarrow\text{ }x-3=29\)

\(x=29+3\)

\(x=32\)

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