Giải :

a) 997 + 86 = 997 + ( 3 + 83 ) = ( 997 + 3 ) + 83 = 100 + 83 = 1083

b) 37 x 38 + 62 x 37 = 37 x ( 38 + 62 ) = 37 x 100 = 3700

c) 27 x 332 + 68 x 27 + 73 x 332 + 68 x 73

= 332 x ( 27 + 73 ) + 68 x ( 27 + 73 )

= 332 x 100 + 68 x 100

= 100 x ( 332 + 68 )

= 100 x 400 

= 40 000

d) 43 x 11 = 43 x ( 10 + 1 ) = 430 + 43 = 473

67 x 101 = 67 x ( 100 + 1 ) = 6700 + 67 = 6767

423 x 1001 = 423 x ( 1000 + 1 ) = 423000 + 423 = 423423

a) 997 + 86 = 1083

b) 37 x 38 + 62 x 37 = 37 x (38 + 62)

                                 = 37 x 100

                                 = 3700

c)27 x 332 + 68 x 27 + 73 x 332 + 68 x 73 = 27 x (332 + 68) + 73 x (332 + 68)

                                                                   = 27 x 400 + 73 x 400

                                                                   = (27 + 73) x 400

                                                                   = 100 x 400

                                                                   = 40000

d) 43 x 11 = 473 ; 67 x 101 = 6767 ; 423 x 1001 = 423423

chúc bạn học tốt

a=190 b=120 c=100

\(a,=\dfrac{1}{3}\times\left(\dfrac{1}{2}+\dfrac{1}{3}\right)=\dfrac{1}{3}\times\dfrac{5}{6}=\dfrac{5}{18}\\ b,=\dfrac{4}{5}\times\left(\dfrac{1}{2}-\dfrac{1}{3}\right)=\dfrac{4}{5}\times\dfrac{1}{6}=\dfrac{2}{15}\\ c,=456\times99-6\times99+456\\ =456\times\left(99+1\right)-594\\ =456\times100-594=45600-594=45006\\ d,=101\times\left(101-1\right)=101\times100=10100\)

Lời giải:

$A=(99-97)+(95-93)+(91-89)+...+(7-5)+(8-1)$

$=\underbrace{2+2+2+...+2}_{24}+7$

$=2\times 24+7$

$=55$

a) \(\left(145\times99+145\right)-\left(143\times102-143\right)\)

\(=\left[145\times\left(99+1\right)\right]-\left[143\times\left(102-1\right)\right]\)

\(=\left(145\times100\right)-\left(143\times101\right)\)

\(=14500-14443\)

\(=57\)

b) \(54\times47-47\times53-20-27\)

\(=47\times\left(54-53\right)-20-27\)

\(=47-20-27\)

\(=0\)

c) \(10000-47\times72-47\times28\)

\(=10000-47\times\left(72+28\right)\)

\(=10000-47\times100\)

\(=10000-4700\)

\(=5300\)

d) \(3457-27\times48-48\times73+6543\)

\(=\left(3457+6543\right)-48\times\left(27+73\right)\)

\(=10000-48\times100\)

\(=10000-4800\)

\(=5200\)

B1:

\(a.301^2=\left(300+1\right)^2=300^2+2.300.1+1^2\\ =90000+600+1=90601\\ b.88^2+2.88.12+12^2=\left(88+12\right)^2=100^2=10000\\ c.99.100=100^2-100=10000-100=9900\\ d,153^2+94.153+47^2=153^2+2.153.47+47^2=\left(153+47\right)^2=200^2=40000\)

B2:

\(A=x^2-20x+101\\ =x^2-2.x.10+10^2+1\\ =\left(x-10\right)^2+1\ge1\forall x\in R\left(Vì:\left(x-10\right)^2\ge0\forall x\in R\right)\\ \Rightarrow min_A=1\Leftrightarrow x-10=0\Leftrightarrow x=10\)

1. \(\left(\dfrac{1}{99}+\dfrac{12}{999}-\dfrac{123}{9999}\right).\left(\dfrac{1}{2}-\dfrac{1}{3}-\dfrac{1}{6}\right)\)

\(=\left(\dfrac{1}{99}+\dfrac{12}{999}-\dfrac{123}{9999}\right).0\)

\(=0\)

Bài 1: 

Ta có: \(A=\left(\dfrac{1}{99}+\dfrac{12}{999}-\dfrac{123}{9999}\right)\cdot\left(\dfrac{1}{2}-\dfrac{1}{3}-\dfrac{1}{6}\right)\)

\(=\left(\dfrac{1}{99}+\dfrac{12}{999}-\dfrac{123}{9999}\right)\cdot\left(\dfrac{3}{6}-\dfrac{2}{6}-\dfrac{1}{6}\right)\)

=0

(-0,4)x(-0,5)x(-0,8)

= 0,2x(-0,8)

=-0,16 

3,4x(-23,68)-3,4x45,12+(-31,2)x3,4

=34,5x5,789+4,211x34,5
=34,5x(5,789+4,211)
=34,5x10
=345

=72x100=7200

=72x100=7200