hộ mik vs

Đáp số là 26461,26922 em nhé

bạn có thể vt rõ câu hỏi ra đc ko

\(\left(-3\right)^2.\left(-5\right)-\left[\left(-95\right)+\left(13+7\right)^2\right]\)

\(=9.\left(-5\right)-\left(-95+20^2\right)\)

\(=-45+95-400\)

\(=50-400\)

\(=-350\)

Đặt A = 1 + ( - 2 ) + ( - 3 ) + 4 + 5 + ( - 6 ) + ( - 7 ) + 8 + ... + 99 - 100 - 101 - 102 + 103

=> A = [ 1 + ( - 2 ) + ( - 3 ) + 4 ] + [ 5 + ( - 6 ) + ( - 7 ) + 8 ] + .... + [ 99 - 100 - 101 + 102 ] + 103

=> A = 0 + 0 + 0 + .... + 103

=> A = 103

Vậy A = 103

làm bừa cho rồi

\(=2^5+5^1\times2^4-3\times2^5\)

\(=32+5\times16-3\times32\)

\(=32+80-96\)

\(=16\)

Học giỏi (◠‿◠)

\(2^7:2^2+5^4:5^3\times2^4-3\times2^5\)

\(=2^5+5\times2^4-3\times2^5=2^4\left(2+5+6\right)=16\times11=176\)

=\(2^{7-2}\)+\(5^{4-3}\)x\(2^4\)-3 x\(2^5\)

=\(2^5\)+\(5^1\)x\(2^4\)-3 x \(2^5\)

=32 + 5 x 16 - 3 x32

=32 + 80 - 96

=112 - 96

=16

k mình nhé!!!

Mình Xong trước

Lời giải:

\(17x^2-2x^3-3x^4-4x-5=-3x^4-2x^3+17x^2-4x-5\)

\(=-3x^2(x^2+x-5)+x^3+2x^2-4x-5\)

\(=-3x^2(x^2+x-5)+x(x^2+x-5)+(x^2+x-5)\)

\(=(x^2+x-5)(-3x^2+x+1)\)

Do đó: $(17x^2-2x^3-3x^4-4x-5):(x^2+x-5)=(-3x^2+x+1)$

(ko bt đúng sai đâu nhá!)

2)

200 : [ 117 -( 23-2.3 ) ]

= 200:[117-(23-6)]

= 200:[117-17]

= 200:100

= 2

4)

2020-[45-(6-1)² ] + 1992⁰

= 2020 - [45-5² ] + 1992⁰

= 2020 - 40² + 1

= 2020 - 1600 + 1

= 420 +1

= 421

6)

480 : [75 + (7² - 8.3) : 5 ] + 2021⁰ 

= 480 : [ 75+( 49 - 24 ): 5 ] + 2021⁰

= 480: [ 75 + 25 : 5 ] + 2021⁰

= 480 : [ 75 + 5 ] + 2021⁰

= 480 : 80 + 1 

= 6 + 1

= 7

8)

2⁴ . 5 - [ 131 - (13 - 4)² ]

= 10⁴ - [ 131 - 9² ]

= 10⁴ - 50

= 10000 - 50

= 9950

(1992⁰ = 1 : 2021⁰=1)

          \(\frac{5}{9}.\frac{-4}{17}+\frac{-13}{17}.\frac{5}{9}+2\frac{4}{9}\)

\(=\)\(\frac{5}{9}.\left(\frac{-4}{17}+\frac{-13}{17}\right)+2\frac{4}{9}\)

\(=\frac{5}{9}.\left(-1\right)+\frac{22}{9}\)

\(=\frac{5}{9}+\frac{22}{9}\)

\(=3\)

\(a,đk:x\ne0;4;1\)

\(\dfrac{x-1}{x^2-5x+4}-\dfrac{4}{x^2-4x}\\ =\dfrac{x-1}{\left(x-1\right)\left(x-4\right)}-\dfrac{4}{x\left(x-4\right)}\\ =\dfrac{x\left(x-1\right)}{x\left(x-1\right)\left(x-4\right)}-\dfrac{4\left(x-1\right)}{x\left(x-1\right)\left(x-4\right)}\\ =\dfrac{x^2-x-4x+4}{x\left(x-1\right)\left(x-4\right)}\\ =\dfrac{x^2-5x+4}{x.\left(x-1\right)\left(x-4\right)}=\dfrac{\left(x-1\right)\left(x-4\right)}{x.\left(x-1\right)\left(x-4\right)}=\dfrac{1}{x}\)

\(đk:x\ne-2;1\)

\(\dfrac{x}{x+2}+\dfrac{7x-16}{\left(x+2\right)\left(7x-7\right)}\\ =\dfrac{x\left(7x-7\right)}{\left(x+2\right)\left(7x-7\right)}+\dfrac{7x-16}{\left(x+2\right)\left(7x-7\right)}\\ =\dfrac{7x^2-7x+7x-16}{\left(x+2\right)\left(7x-7\right)}\\ =\dfrac{7x^2-16}{\left(x+2\right)\left(7x-7\right)}\)

a)

\(\dfrac{x-1}{x^2-5x+4}-\dfrac{4}{x^2-4x}\) \(ĐKXĐ:x\ne0;x\ne4;x\ne1\)

\(=\dfrac{x-1}{x^2-4x-x+4}-\dfrac{4}{x\left(x-4\right)}\)

\(=\dfrac{x-1}{x\left(x-4\right)-\left(x-4\right)}-\dfrac{4}{x\left(x-4\right)}\)

\(=\dfrac{x-1}{\left(x-1\right)\left(x-4\right)}-\dfrac{4}{x\left(x-4\right)}\)

\(=\dfrac{x^2-x}{x\left(x-1\right)\left(x-4\right)}-\dfrac{4\left(x-1\right)}{x\left(x-1\right)\left(x-4\right)}\)

\(=\dfrac{x^2-x-4x+4}{x\left(x-1\right)\left(x-4\right)}\)

\(=\dfrac{x\left(x-1\right)-4\left(x-1\right)}{x\left(x-1\right)\left(x-4\right)}\)

\(=\dfrac{\left(x-1\right)\left(x-4\right)}{x\left(x-1\right)\left(x-4\right)}\\ =\dfrac{1}{x}\)

b)

\(\dfrac{x}{x+2}+\dfrac{7x-16}{\left(x+2\right)\left(7x-7\right)}\)  \(ĐKXĐ:x\ne-2;x\ne1\)

\(=\dfrac{x\left(7x-7\right)}{\left(x+2\right)\left(7x-7\right)}+\dfrac{7x-16}{\left(x+2\right)\left(7x-7\right)}\)

\(=\dfrac{7x^2-7x+7x-16}{\left(x+2\right)\left(7x-7\right)}\)

\(=\dfrac{7x^2-16}{\left(x+2\right)\left(7x-7\right)}\)

a: Ta có: \(3\sqrt{2}\cdot5\sqrt{6}\cdot4\sqrt{12}\)

\(=\sqrt{18\cdot25\cdot6\cdot16\cdot12}\)

\(=\sqrt{518400}\)

=720

b: Ta có: \(\left(\sqrt{7}-\sqrt{2}\right)^2+2\sqrt{14}\)

\(=9-2\sqrt{14}+2\sqrt{14}\)

=9

c: Ta có: \(\left(1+\sqrt{5}+\sqrt{6}\right)\left(1+\sqrt{5}-\sqrt{6}\right)\)

\(=6+2\sqrt{5}-6\)

\(=2\sqrt{5}\)